题目内容
一列简谐横波沿直线由a向b传播,相距10.5 m的a、b两处的质点振动图象如图所示中a、b所示,则( )
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241910256072964.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241910256072964.png)
A.该波的振幅可能是20 cm |
B.该波的波长可能是8.4 m |
C.该波的波速可能是10.5 m/s |
D.该波由a传到b可能历时7 s |
D
试题分析:由图知振幅A=10 cm;
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824191025888594.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824191026153517.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824191026419719.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824191026715651.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824191026980555.png)
思路分析:先列出式子
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824191025888594.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824191026153517.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824191026419719.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824191026715651.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824191026980555.png)
点评:本题是一道综合性多解题,根据表达式列出多解式子是关键,本题中最重要的是找到列多解问题的等式关系,从而利用波速公式求解。
![](http://thumb2018.1010pic.com/images/loading.gif)
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