题目内容
在验证动量守恒定律的实验里,两半径相同的小球质量之比
∶
=8∶3,实验记录纸上,各点(O、M、P、N)位置如图31所示,其中O点为斜槽末端所系重锤线指的位置,那么,
、
两球中,__ __球是入射球,碰撞结束时刻,两球的动量之比
∶
=__________。![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115538430693.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115538337330.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115538352229.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115538368200.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115538384206.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115538399220.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115538415220.gif)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824115538430693.gif)
A 4:3
实验要求入射球质量大于被碰球质量,故选A球为入射球。根据动量守恒和平抛运动知识可知m1(op)=m1(oM)+m2(oN),解得PA:PB=4:3
![](http://thumb2018.1010pic.com/images/loading.gif)
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