ÌâÄ¿ÄÚÈÝ

ijͬѧÉè¼ÆÁËÒ»¸ö²â¶¨¼¤¹â²¨³¤µÄʵÑé×°ÖÃÈçͼ¼×Ëùʾ£¬¼¤¹âÆ÷·¢³öµÄÒ»ÊøÖ±¾¶ºÜСµÄºìÉ«¼¤¹â½øÈëÒ»¸öÒ»¶Ë×°ÓÐË«·ì¡¢ÁíÒ»¶Ë×°ÓийâƬµÄÕÚ¹âͲ£¬¸Ð¹âƬµÄλÖÃÉϳöÏÖÒ»ÅŵȾàµÄÁÁµã£¬Í¼ÒÒÖеĺڵã´ú±íÁÁµãµÄÖÐÐÄλÖã®
£¨1£©Í¨¹ýÁ¿³öÏàÁÚ¹âµãµÄ¾àÀë¿ÉËã³ö¼¤¹âµÄ²¨³¤£¬¾Ý×ÊÁϽéÉÜ£¬ÈôË«·ìµÄ·ì¼ä¾àÀëΪa£¬ÔòË«·ìµ½¸Ð¹âƬµÄ¾àÀëΪL£¬¸Ð¹âƬÉÏÏàÁÚÁ½¹âµã¼äµÄ¾àÀëΪb£¬Ôò¹âµÄ²¨³¤v=1m/s£®¸Ãͬѧ²âµÄL=1.0000m£¬Ë«·ì¼ä¾àa=0.220mm£¬ÓôøÊ®·Ö¶ÈÓαêµÄ¿¨³ß²â¸Ð¹âƬÉϵĵã¼ä¾àʱ£¬³ßÓëµãµÄÖÐÐÄλÖÃÈçͼÒÒËùʾ£®Í¼ÒÒÖеÚÒ»¸ö¹âµãµ½µÚËĸö¹âµãµÄ¾àÀëÊÇ
 
mm£®ÊµÑéÖм¤¹âµÄ²¨³¤¦Ë=
 
m£¨±£ÁôÁ½Î»ÓÐЧÊý×Ö£©
£¨2£©Èç¹ûʵÑéʱ½«ºì¼¤¹â»»³ÉÀ¶¼¤¹â£¬ÆÁÉÏÏàÁÚÁ½¹âµã¼äµÄ¾àÀ뽫
 
£®£¨±ä´ó¡¢±äС¡¢²»±ä£©
¾«Ó¢¼Ò½ÌÍø
·ÖÎö£º£¨1£©Óα꿨³ßµÄ¶ÁÊýµÈÓÚÖ÷³ß¶ÁÊý¼ÓÉÏÓαê¶ÁÊý£¬²»ÐèÒª¹À¶Á£®¸ù¾Ý¡÷x=
L
d
¦Ë
£¬Çó³ö¼¤¹âµÄ²¨³¤£®
£¨2£©À¶¹âµÄ²¨³¤±Èºì¹â¶Ì£¬¸ù¾Ý¡÷x=
L
d
¦Ë
£¬ÅжÏÏàÁÚÁ½¹âµç¼äµÄ¾àÀë±ä»¯£®
½â´ð£º½â£º£¨1£©Ö÷³ß¶ÁÊýΪ8mm£¬Óαê¶ÁÊýΪ0.1¡Á5=0.5mm£¬ËùÒÔµÚÒ»¸ö¹âµãµ½µÚËĸö¹âµãµÄ¾àÀëÊÇ8.5mm£®
         ÒòΪ¡÷x=
L
d
¦Ë
£¬ËùÒÔ¦Ë=
¡÷xd
L
=
8.5¡Á10-3
3
¡Á0.22¡Á10-3
1
=6.2¡Á10-7m
   £¨2£©¸ù¾Ý¡÷x=
L
d
¦Ë
£¬Öª²¨³¤±ä¶Ì£¬ÆÁÉÏÏàÁÚÁ½¹âµã¼äµÄ¾àÀ뽫±äС£®
¹Ê±¾Ìâ´ð°¸Îª£º£¨1£©8.5£» 6.2¡Á10-7£»£¨2£©±äС£®
µãÆÀ£º½â¾ö±¾ÌâµÄ¹Ø¼üÕÆÎÕÓα꿨³ßµÄ¶ÁÊý·½·¨£¬ÒÔ¼°ÕÆÎÕÌõÎƼä¾à¡÷x=
L
d
¦Ë
£®
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ijͬѧÉè¼ÆÁËÒ»¸ö²â¶¨Ô²ÖÜÔ˶¯½ÇËٶȵÄʵÑéÔÚÈçͼ¼×ËùʾµÄ×°ÖÃÖУ¬ÀûÓÃÅçÆáÍ°Äܹ»ÏòÍâÅçÉäËÙ¶ÈÒ»¶¨µÄÓÍÆáÎíµÎ£¨ÅçÉäËÙ¶Èv0¿ÉÑ¡Ôñ²»Í¬ÖµÇÒΪÒÑÖª£©£¬Ò»¸öÖ±¾¶ÎªD=40cmµÄÖ½´ø»·£¬°²·ÅÔÚÒ»¸ö¿ÉÒÔ°´ÕÕÒ»¶¨×ªËÙת¶¯µÄ¹Ì¶¨×ªÌ¨ÉÏ£¬Ö½´ø»·ÉÏ¿ÌÓÐÒ»ÌõÏÁ·ìA£¬ÔÚÏÁ·ìAµÄÕý¶ÔÃæ»­Ò»Ìõ±êÖ¾Ïߣ®ÎíµÎËùÊܵĿÕÆø×èÁ¦¼«Ð¡£¬¿ÉºöÂÔÔÚת̨¿ªÊ¼×ª¶¯´ïµ½Îȶ¨×ªËÙʱ£¬Ïò²àÃæͬÑù¿ªÓÐÏÁ·ìBµÄÖ½ºÐÖÐÅçÉäÓÍÆáÎíµÎ£¬µ±ÏÁ·ìAתÖÁÓëÏÁ·ìBÕý¶ÔƽÐÐʱ£¬ÎíµÎ±ãͨ¹ýÏÁ·ìAÔÚÖ½´øµÄÄÚ²àÃæÁôϺۼ££®¸Ä±äÅçÉäËÙ¶ÈÖظ´ÊµÑ飬ÔÚÖ½´øÉÏÁôÏÂһϵÁеĺۼ£a¡¢b¡¢c¡¢D£®½«Ö½´ø´Óת̨ÉÏÈ¡ÏÂÀ´£¬Õ¹¿ªÆ½·Å£¬ÈçͼÒÒËùʾ

ÒÑÖªv0£¾
¦Ø?D¦Ð
£¬ÇëÄã°ï¸ÃͬѧÍê³ÉÏÂÁÐÈÎÎñ£º
£¨1£©ÉèÅçÉäµ½Ö½´øÉϵÄÓÍÆáÎíµÎºÛ¼£µ½±êÖ¾ÏߵľàÀëΪS£¬Ôò
´ÓͼÒÒ¿ÉÖª£¬ÔÚa¡¢b¡¢c¡¢dËĸöµãÖÐËÙ¶È×î´óµÄÎíµÎµ½±êÖ¾ÏߵľàÀëS1=
0.70
0.70
cm£®£»
£¨2£©ÈôÎíµÎÅçÉäËÙ¶ÈΪv0£¬ÊÔÇó½âת̨ת¶¯µÄ½ÇËٶȦØΪ¶àÉÙ£¿£¨ÓÃ×Öĸ±íʾ£©
£¨3£©ÈôÒÔ×Ý×ø±ê±íʾÎíµÎËÙ¶Èv0¡¢ºá×ø±ê±íʾÎíµÎ¾à±êÖ¾Ïß¾àÀëµÄµ¹Êý1/s£¬»­³öv0-1/sͼÏßÈçͼ±ûËùʾ£¬ÊÔ¼ÆËãת̨ת¶¯µÄ½ÇËٶȦØÖµ£®
£¨2011?ºþ±±¶þÄ££©Ä³Í¬Ñ§Éè¼ÆÁËÒ»¸ö²â¶¨ÓÍÆáÅçǹÏòÍâÅçÉäÓÍÆáÎíµÎËٶȵÄʵÑ飮Ëû²ÉÓÃͼ£¨1£©ËùʾµÄ×°Ö㬸ÃÓÍÆáÅçǹÄܹ»ÏòÍâÅçÉäËÄÖÖËٶȴóС²»Í¬µÄÓÍÆáÎíµÎ£¬Ò»¸öÖ±¾¶ÎªDµÄÖ½´ø»·£¬°²·ÅÔÚÒ»¸ö¿ÉÒÔ°´ÕÕÒ»¶¨×ªËÙת¶¯µÄ¹Ì¶¨×ªÌ¨ÉÏ£¬Ö½´ø»·ÉÏ¿ÌÓÐÒ»ÌõÏÁ·ìA£¬ÔÚÏÁ·ìAµÄÕý¶ÔÃæ»­Ò»Ìõ±êÖ¾Ïߣ¬ÔÚת̨¿ªÊ¼×ª¶¯´ïµ½Îȶ¨½ÇËٶȦØʱ£¬Ïò²àÃæͬÑù¿ªÓÐÏÁ·ìBµÄÖ½ºÐÖÐÅçÉäÓÍÆáÎíµÎ£¬µ±ÏÁ·ìAתÖÁ¿¿½üÏÁ·ìBÇÒÓë֮ƽÐÐÕý¶Ôʱ£¬ÎíµÎ±ãͨ¹ýÏÁ·ìAÔÚÖ½´øµÄÄÚ²àÃæÁôϺۼ££®¸Ä±äÅçÉäËÙ¶ÈÖظ´ÊµÑ飬ÔÚÖ½´øÉÏÁôÏÂһϵÁеĺۼ£a¡¢b¡¢c¡¢d£®½«Ö½´ø´Óת̨ÉÏÈ¡ÏÂÀ´£¬Õ¹¿ªÆ½·ÅÔڿ̶ȳßÅԱߣ¬Èçͼ£¨2£©Ëùʾ£¬Èç¹û²»¼ÆÎíµÎËùÊܵÄÖØÁ¦ºÍ¿ÕÆø×èÁ¦£®

£¨1£©ÓÃvmin±íʾËÄ´ÎʵÑéÖÐÓÍÆáÎíµÎµÄ×îСËٶȣ¬ÈôÒª±£Ö¤ËÄ´ÎʵÑéÎíµÎ¶¼ÔÚÖ½´ø»·×ª¶¯°ëȦµÄʱ¼äÄÚ´ïµ½Ö½´ø»·£¬ÔòÖ½´ø»·×ª¶¯µÄ½ÇËٶȦØÓ¦Âú×ãµÄÌõ¼þÊÇ£º
¦Ø=
vmin¦Ð
D
¦Ø=
vmin¦Ð
D
£®
£¨2£©ÔÚÂú×㣨1£©µÄÌõ¼þÏ£¬ÈôD=40cm£¬¦Ø=2.4rad/s£¬ÓÉͼ£¨b£©¿ÉÖªËÄ´ÎʵÑéÖÐÅçÉäËÙ¶È×î´óµÄÎíµÎËÙ¶Èvmax=
32
32
m/s£®
I ÀûÓÃͼ10ÖÐËùʾµÄ×°ÖÿÉÒÔÑо¿×ÔÓÉÂäÌåÔ˶¯£®ÊµÑéÖÐÐèÒªµ÷ÕûºÃÒÇÆ÷£¬½Óͨ´òµã¼ÆʱÆ÷µÄµçÔ´£¬ËÉ¿ªÖ½´ø£¬Ê¹ÖØÎïÏÂÂ䣮´òµã¼ÆʱÆ÷»áÔÚÖ½´øÉÏ´ò³öһϵÁеÄСµã£®
£¨1£©ÎªÁ˲âµÃÖØÎïÏÂÂäµÄ¼ÓËٶȣ¬»¹ÐèÒªµÄʵÑéÆ÷²ÄÓÐ
 
£®£¨ÌîÈëÕýÈ·Ñ¡ÏîÇ°µÄ×Öĸ£©
A£®ÌìƽB£®Ãë±íC£®¿Ì¶È³ß
£¨2£©ÈôʵÑéÖÐËùµÃµ½µÄÖØÎïÏÂÂäµÄ¼ÓËÙ¶ÈֵСÓÚµ±µØµÄÖØÁ¦¼ÓËÙ¶ÈÖµ£¬¶øʵÑé²Ù×÷ÓëÊý¾Ý´¦Àí¾ùÎÞ´íÎó£¬Ð´³öÒ»¸öÄãÈÏΪ¿ÉÄÜÒýÆð´ËÎó²îµÄÔ­Òò£º
 
£®
II£¨5·Ö£©ÎªÁ˲âÁ¿µçÔ´µÄµç¶¯ÊƺÍÄÚ×裬ÔÚʵÑéÊÒÀïÎÒÃÇͨ³£²Éȡͼ¼×Ëùʾµç·²âÁ¿£¬Çë¸ù¾Ý¸Ãµç·ͼÔÚͼÒÒÖÐÁ¬½ÓʵÎïͼ
 
£®
¾«Ó¢¼Ò½ÌÍø
IIIijͬѧÉè¼ÆÁËÒ»¸ö²â¶¨¼¤¹â²¨³¤µÄʵÑé×°ÖÃÈçͼ¼×Ëùʾ£¬¼¤¹âÆ÷·¢³öµÄÒ»ÊøÖ±¾¶ºÜСµÄºìÉ«¼¤¹â½øÈëÒ»¸öÒ»¶Ë×°ÓÐË«·ì¡¢ÁíÒ»¶Ë×°ÓийâƬµÄÕÚ¹âͲ£¬¸Ð¹âƬµÄλÖÃÉϳöÏÖÒ»ÅŵȾàµÄÁÁµã£¬Í¼ÒÒÖеĺڵã´ú±íÁÁµãµÄÖÐÐÄλÖã®
£¨1£©Í¨¹ýÁ¿³öÏàÁÚ¹âµãµÄ¾àÀë¿ÉËã³ö¼¤¹âµÄ²¨³¤£¬¾Ý×ÊÁϽéÉÜ£¬ÈôË«·ìµÄ·ì¼ä¾àÀëΪa£¬Ë«·ìµ½¸Ð¹âƬµÄ¾àÀëΪ¸Ð¹âƬÉÏÏàÁÚÁ½¹âµã¼äµÄ¾àÀëΪb£¬Ôò¹âµÄ²¨³¤¦Ë=
abL
£®¸Ãͬѧ²âµÃL=1.0000m£¬Ë«·ì¼ä¾àa=0.22mm£¬Óôø10·Ö¶ÈÓαêµÄ¿¨³ß²â¸Ð¹âƬÉϵĹâµã¼ä¾àʱ£¬³ßÓëµãµÄÖÐÐÄλÖÃÈçͼÒÒËùʾ£®Í¼ÒÒÖеÚÒ»¸ö¹âµãµ½µÚËĸö¹âµãµÄ¾àÀëÊÇ
 
mm£®ÊµÑéÖм¤¹âµÄ²¨³¤¦Ë=
 
m£¨±£ÁôÁ½Î»ÓÐЧÊý×Ö£©
£¨2£©Èç¹ûʵÑéʱ½«ºì¼¤¹â»»³ÉÀ¶¼¤¹â£¬ÆÁÉÏÏàÁÚÁ½¹âµã¼äµÄ¾àÀ뽫
 
£®£¨Ñ¡Ìî±ä´ó¡¢±äС¡¢²»±ä£©
¾«Ó¢¼Ò½ÌÍø

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø