题目内容
如图所示,是两列频率相同的波在某时刻叠加情况,图中实线为波峰波面,虚线为波谷波面,已知两列波的振幅均为2cm,波速2m/s,波长为8m,E点是BD和AC连线的交点,下列说法正确的是( )
A. A、C处两质点是振动加强点
B. B、D处两质点在该时刻的竖直高度差是4cm
C. E点处是振动加强的质点
D.经2s,B点处质点通过的路程是4cm
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241342497294546.png)
A. A、C处两质点是振动加强点
B. B、D处两质点在该时刻的竖直高度差是4cm
C. E点处是振动加强的质点
D.经2s,B点处质点通过的路程是4cm
C
由图可知,A、C处两质点是波峰和波谷相叠加,是减弱点,A错;D处是两波峰叠加,在平衡位置上方2A=
,B处是两波谷叠加,在平衡位置下方2A=
,所以 B、D处两质点在该时刻的竖直高度差是8cm,B错;在以后的某一时刻,随着波峰的向右传播,出现如图所示的图形,由图可知E点处是振动加强的质点,进而得出在BD连线上的点都是振动加强的质点,C对;由
,因B点是振动加强点,其振幅
,经2s,B点处质点通过的路程是x=
,D错。
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241342500885512.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134249776602.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134249776602.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134249838808.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/20140824134249994769.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241342500411067.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140824/201408241342500885512.png)
![](http://thumb2018.1010pic.com/images/loading.gif)
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