ÌâÄ¿ÄÚÈÝ

ijͬѧÀûÓÃÈçÌâ10£­lͼËùʾµÄ×°ÖÃ̽¾¿Á¦µÄƽÐÐËıßÐζ¨Ôò£ºÊúÖ±·ÅÖÃÆÌÓа×Ö½µÄľ°åÉϹ̶¨ÓÐÁ½¸öÇáÖÊС»¬ÂÖ£¬Ï¸ÏßABºÍOCÁ¬½ÓÓÚ¡£µã£¬Ï¸ÏßABÈƹýÁ½»¬ÂÖ£¬D¡¢EÊÇϸÏßÓ뻬ÂÖµÄÁ½¸ö½Ó´¥µã¡£ÔÚϸÏßÄ©¶ËA¡¢B¡¢CÈý´¦·Ö±ð¹ÒÓв»Í¬ÊýÁ¿µÄÏàͬ¹³Â룬ÉèËù¹Ò¹³ÂëÊý·Ö±ðÓÃNl¡¢N2¡¢N3±íʾ£®¹ÒÉÏÊʵ±ÊýÁ¿µÄ¹³Â룬µ±ÏµÍ³Æ½ºâʱ½øÐÐÏà¹Ø¼Ç¼£®¸Ä±äËù¹Ò¹³ÂëµÄÊýÁ¿£¬Öظ´½øÐжà´ÎʵÑ飮

(1)ÏÂÁÐÄÜÂú×ãϵͳƽºâµÄNl¡¢N2¡¢N3µÄÈ¡Öµ¿ÉÄÜΪ£º

(A)N1=N2=3£¬N3=4      (B)N1=N2=3£¬N3=6

(C) N1=N2=N3=3          (D)N1=3£¬N2=4£¬N3=8

(2)ÏÂÁйØÓÚ±¾ÊµÑé²Ù×÷µÄÃèÊö£¬ÕýÈ·µÄÓУº

(A)ÐèÒªÀûÓÃÌìƽ²â³ö¹³ÂëµÄÖÊÁ¿

(B)¡Ï EOD²»Ò˹ý´ó

(C)Á½»¬ÂÖµÄÖáÐIJ»±Ø´¦ÓÚͬһÌõˮƽÏßÉÏ

(D)ÿ´ÎʵÑ鶼ӦʹϸÏߵĽáµãD´¦ÓÚͬһλÖÃ

(3)ÿ´ÎʵÑé½áÊøºó£¬ÐèÒª¼Ç¼µÄÏîÄ¿ÓÐNl¡¢N2¡¢N3µÄÊýÖµºÍ_____¡ø______£º

(4)¸ÃͬѧÀûÓÃij´ÎʵÑé½á¹ûÔÚ°×Ö½ÉÏ»æÖÆÁËÈçÌâl0-2ͼËùʾµÄʵÑé½á¹û´¦Àíͼ£¬Ôò¸ù¾ÝÄã¶Ô±¾ÊµÑéµÄÀí½â£¬À­Á¦FODºÍFOEµÄºÏÁ¦µÄ²âÁ¿ÖµÓ¦ÊÇͼÖеÄ____¡ø_____(Ñ¡Ìî¡°F¡±»ò¡°F¡ä¡±)£»

£¨1£©b£¨4·Ö£©

£¨2£©ÈçͼËùʾ£¨6·Ö£©£¨Èô2¡¢6×éÊý¾Ý䱨¾¯µã£¬µÃÒ»°ë·Ö£©

£¨3£©ÈçͼËùʾ£¨6·Ö£©£¨´íÒ»´¦²»µÃ·Ö£©

£¨4£©2£¨4·Ö£©

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨¸ù¾Ý³£ÖÝÊÐËÄУ¸ßÈýÎïÀíÁª¿¼ÊÔ¾íµÚ11Ìâ¸Ä±à£©ÏÖÓÐÒ»ÌØÊâµÄµç³Ø£¬Æäµç¶¯ÊÆEԼΪ9V£¬ÄÚ×èrÔÚ35¡«55¦¸·¶Î§£¬×î´óÔÊÐíµçÁ÷Ϊ50mA£®Îª²â¶¨Õâ¸öµç³ØµÄµç¶¯ÊƺÍÄÚ×裬ijͬѧÀûÓÃÈçͼ¼×µÄµç·½øÐÐʵÑ飮ͼÖеçѹ±íµÄÄÚµç×èºÜ´ó£¬¶Ôµç·µÄÓ°Ïì¿ÉÒÔ²»¼Æ£»RΪµç×èÏ䣬×èÖµ·¶Î§Îª0¡«9999¦¸£»R0ÊǶ¨Öµµç×è

£¨1£©ÊµÑéÊÒ±¸ÓеĶ¨Öµµç×èR0ÓÐÒÔϼ¸ÖÖ¹æ¸ñ£¬Ó¦Ñ¡ÓÃ
C
C

A£®10¦¸£¬2.5W             B£®50¦¸£¬1.0W
C£®150¦¸£¬1.0W            D£®1500¦¸£¬5.0W
£¨2£©¸Ãͬѧ½ÓÈë·ûºÏÒªÇóµÄR0ºó£¬±ÕºÏ¿ª¹ØS£¬µ÷Õûµç×èÏäµÄ×èÖµ¶Á³öµçѹ±íµÄʾÊýU£¬Ôٸıäµç×èÏä×èÖµ£¬È¡µÃ¶à×éÊý¾Ý£¬È»ºóͨ¹ý×÷³öÓйØÎïÀíÁ¿µÄÏßÐÔͼÏó£¬ÈçͼÒÒËùʾ£¬ÇóµÃµçÔ´µÄµç¶¯ÊƺÍÄÚ×裮
a£®Çëд³ö¸ÃÏßÐÎͼÏó¶ÔÓ¦µÄº¯Êý±í´ïʽ
1
U
=
r
E
?
1
R+R0
+
1
E
1
U
=
r
E
?
1
R+R0
+
1
E
£¨ÓÃ×ÖĸE¡¢r¡¢U¡¢R¡¢R0±íʾ£©
b£®Çë±êÃ÷ͼÒÒÁ½¸ö×ø±êÖáËù±íʾµÄÎïÀíÁ¿£¬ºá×ø±ê
1
R+R0
1
R+R0
£¬×Ý×ø±ê
1
U
1
U

£¨3£©¸ù¾ÝÒÒͼËù×÷³öµÄͼÏóÇóµÃ¸Ãµç³ØµÄµç¶¯ÊÆEΪ
10
10
V£¬ÄÚµç×èrԼΪ
50¦¸
50¦¸
¦¸£®
I£®Ä³Í¬Ñ§ÀûÓÃÈçͼ£¨a£©×°ÖÃ×ö¡°Ì½¾¿µ¯»Éµ¯Á¦´óСÓëÆ䳤¶ÈµÄ¹Øϵ¡±µÄʵÑ飮
¢ÙÔÚ°²×°¿Ì¶È³ßʱ£¬±ØÐëʹ¿Ì¶È³ß±£³Ö
ÊúÖ±
ÊúÖ±
״̬£®
¢ÚËûͨ¹ýʵÑéµÃµ½Èçͼ£¨b£©ËùʾµÄµ¯Á¦´óСFÓ뵯»É³¤¶ÈxµÄ¹ØϵͼÏߣ®ÓÉ´ËͼÏ߿ɵøõ¯»ÉµÄÔ­³¤x0=
4
4
cm£¬¾¢¶ÈϵÊýk=
50
50
N/m£®
¢ÛËûÓÖÀûÓñ¾ÊµÑéÔ­Àí°Ñ¸Ãµ¯»É×ö³ÉÒ»°Ñµ¯»É³Ó£¬µ±µ¯»É³ÓÉϵÄʾÊýÈçͼ£¨c£©Ëùʾʱ£¬¸Ãµ¯»ÉµÄ³¤¶Èx=
10
10
cm£®
¢ò£®Ä³Ñ§Ï°Ð¡×éΪ̽¾¿µ¼µçÈÜÒºµÄµç×èÔÚÌå»ýÏàͬʱ£¬µç×èÖµÓ볤¶ÈµÄ¹Øϵ£®Ñ¡È¡Ò»¸ùÈ齺¹Ü£¬ÀïÃæ¹àÂúÁËÑÎË®£¬Á½¶ËÓôÖÍ­Ë¿Èûס¹Ü¿Ú£¬ÐγÉÒ»¶Î·â±ÕµÄÑÎË®Öù£®½øÐÐÁËÈçÏÂʵÑ飺
£¨1£©¸ÃС×齫ÑÎË®Öù×÷Ϊ´¿µç×裬´Ö²âÆäµç×èԼΪ¼¸Ç§Å·£®ÏÖ²ÉÓ÷ü°²·¨²âÑÎË®ÖùµÄµç×裬ÓÐÈçÏÂʵÑéÆ÷²Ä¿É¹©Ñ¡Ôñ£º
A£®Ö±Á÷µçÔ´£ºµç¶¯ÊÆ12V£¬ÄÚ×èºÜС£¬¶î¶¨µçÁ÷1A£»
B£®µçÁ÷±íA1£ºÁ¿³Ì0¡«10mA£¬ÄÚ×èÔ¼10¦¸£»C£®µçÁ÷±íA2£ºÁ¿³Ì0¡«600mA£¬ÄÚ×èÔ¼0.5¦¸£»
D£®µçѹ±íV£ºÁ¿³Ì0¡«15V£¬ÄÚ×èÔ¼15¦¸£»E£®»¬¶¯±ä×èÆ÷R1£º×î´ó×èÖµ10¦¸£»
F£®»¬¶¯±ä×èÆ÷R2£º×î´ó×èÖµ5¦¸£»G£®¿ª¹Ø£®µ¼ÏßµÈ
Ôڿɹ©Ñ¡ÔñµÄÆ÷²ÄÖУ¬Ó¦Ñ¡ÓõĵçÁ÷±íÊÇ
A
 
1
A
 
1
£¨Ìî¡°A1¡±»ò¡°A2¡±£©£¬Ó¦¸ÃÑ¡ÓõĻ¬¶¯±ä×èÆ÷ÊÇ
R
 
2
R
 
2
£¨Ìî¡°R1¡±»ò¡°R2¡±£©£®
£¨2£©¸ù¾ÝËùÑ¡µÄÆ÷²ÄÔÚÌâ¸øµÄ·½¿òÄÚ£¨Í¼1£©»­³öʵÑéµÄµç·ͼ£®
£¨3£©ÎÕסÈ齺¹ÜÁ½¶Ë°ÑËü¾ùÔÈÀ­³¤£¬¶à´ÎʵÑé²âµÃÑÎË®Öù³¤¶ÈL£¬µç×èRµÄÊý¾ÝÈçÏÂ±í£º
ʵÑé´ÎÊý 1 2 3 4 5 6
³¤¶ÈL£¨cm£© 20.0 25.0 30.0 35.0 40.0 45.0
µç×èR£¨k¦¸£© 1.3 2.1 3.0 4.1 5.3 6.7
ΪÁËÑо¿µç×èRÓ볤¶ÈLµÄ¹Øϵ£¬¸ÃС×éÓÃ×Ý×ø±ê±íʾµç×èR£¬×÷³öÁËÈçͼ£¨Í¼2£©ËùʾµÄͼÏߣ¬ÄãÈÏΪºá×ø±ê±íʾµÄÎïÀíÁ¿ÊÇ
L
2
 
L
2
 
£®

ijͬѧÀûÓÃÈçÌâ10£­lͼËùʾµÄ×°ÖÃ̽¾¿Á¦µÄƽÐÐËıßÐζ¨Ôò£ºÊúÖ±·ÅÖÃÆÌÓа×Ö½µÄľ°åÉϹ̶¨ÓÐÁ½¸öÇáÖÊС»¬ÂÖ£¬Ï¸ÏßABºÍOCÁ¬½ÓÓÚ¡£µã£¬Ï¸ÏßABÈƹýÁ½»¬ÂÖ£¬D¡¢EÊÇϸÏßÓ뻬ÂÖµÄÁ½¸ö½Ó´¥µã¡£ÔÚϸÏßÄ©¶ËA¡¢B¡¢CÈý´¦·Ö±ð¹ÒÓв»Í¬ÊýÁ¿µÄÏàͬ¹³Â룬ÉèËù¹Ò¹³ÂëÊý·Ö±ðÓÃNl¡¢N2¡¢N3±íʾ£®¹ÒÉÏÊʵ±ÊýÁ¿µÄ¹³Â룬µ±ÏµÍ³Æ½ºâʱ½øÐÐÏà¹Ø¼Ç¼£®¸Ä±äËù¹Ò¹³ÂëµÄÊýÁ¿£¬Öظ´½øÐжà´ÎʵÑ飮

(1)ÏÂÁÐÄÜÂú×ãϵͳƽºâµÄNl¡¢N2¡¢N3µÄÈ¡Öµ¿ÉÄÜΪ£º

(A)N1=N2=3£¬N3=4      (B)N1=N2=3£¬N3=6

(C) N1=N2=N3=3          (D)N1=3£¬N2=4£¬N3=8

(2)ÏÂÁйØÓÚ±¾ÊµÑé²Ù×÷µÄÃèÊö£¬ÕýÈ·µÄÓУº

(A)ÐèÒªÀûÓÃÌìƽ²â³ö¹³ÂëµÄÖÊÁ¿

(B)¡Ï EOD²»Ò˹ý´ó

(C)Á½»¬ÂÖµÄÖáÐIJ»±Ø´¦ÓÚͬһÌõˮƽÏßÉÏ

(D)ÿ´ÎʵÑ鶼ӦʹϸÏߵĽáµãD´¦ÓÚͬһλÖÃ

(3)ÿ´ÎʵÑé½áÊøºó£¬ÐèÒª¼Ç¼µÄÏîÄ¿ÓÐNl¡¢N2¡¢N3µÄÊýÖµºÍ_____¡ø______£º

(4)¸ÃͬѧÀûÓÃij´ÎʵÑé½á¹ûÔÚ°×Ö½ÉÏ»æÖÆÁËÈçÌâl0-2ͼËùʾµÄʵÑé½á¹û´¦Àíͼ£¬Ôò¸ù¾ÝÄã¶Ô±¾ÊµÑéµÄÀí½â£¬À­Á¦FODºÍFOEµÄºÏÁ¦µÄ²âÁ¿ÖµÓ¦ÊÇͼÖеÄ____¡ø_____(Ñ¡Ìî¡°F¡±»ò¡°F¡ä¡±)£»

ijͬѧÀûÓÃÈçÌâ10£­lͼËùʾµÄ×°ÖÃ̽¾¿Á¦µÄƽÐÐËıßÐζ¨Ôò£ºÊúÖ±·ÅÖÃÆÌÓа×Ö½µÄľ°åÉϹ̶¨ÓÐÁ½¸öÇáÖÊС»¬ÂÖ£¬Ï¸ÏßABºÍOCÁ¬½ÓÓÚ¡£µã£¬Ï¸ÏßABÈƹýÁ½»¬ÂÖ£¬D¡¢EÊÇϸÏßÓ뻬ÂÖµÄÁ½¸ö½Ó´¥µã¡£ÔÚϸÏßÄ©¶ËA¡¢B¡¢CÈý´¦·Ö±ð¹ÒÓв»Í¬ÊýÁ¿µÄÏàͬ¹³Â룬ÉèËù¹Ò¹³ÂëÊý·Ö±ðÓÃNl¡¢N2¡¢N3±íʾ£®¹ÒÉÏÊʵ±ÊýÁ¿µÄ¹³Â룬µ±ÏµÍ³Æ½ºâʱ½øÐÐÏà¹Ø¼Ç¼£®¸Ä±äËù¹Ò¹³ÂëµÄÊýÁ¿£¬Öظ´½øÐжà´ÎʵÑ飮

(1)ÏÂÁÐÄÜÂú×ãϵͳƽºâµÄNl¡¢N2¡¢N3µÄÈ¡Öµ¿ÉÄÜΪ£º

(A)N1=N2=3£¬N3=4      (B)N1=N2=3£¬N3=6

(C) N1=N2=N3=3          (D)N1=3£¬N2=4£¬N3=8

(2)ÏÂÁйØÓÚ±¾ÊµÑé²Ù×÷µÄÃèÊö£¬ÕýÈ·µÄÓУº

(A)ÐèÒªÀûÓÃÌìƽ²â³ö¹³ÂëµÄÖÊÁ¿

(B)¡Ï EOD²»Ò˹ý´ó

(C)Á½»¬ÂÖµÄÖáÐIJ»±Ø´¦ÓÚͬһÌõˮƽÏßÉÏ

(D)ÿ´ÎʵÑ鶼ӦʹϸÏߵĽáµãD´¦ÓÚͬһλÖÃ

(3)ÿ´ÎʵÑé½áÊøºó£¬ÐèÒª¼Ç¼µÄÏîÄ¿ÓÐNl¡¢N2¡¢N3µÄÊýÖµºÍ__________£º

(4)¸ÃͬѧÀûÓÃij´ÎʵÑé½á¹ûÔÚ°×Ö½ÉÏ»æÖÆÁËÈçÌâl0-2ͼËùʾµÄʵÑé½á¹û´¦Àíͼ£¬Ôò¸ù¾ÝÄã¶Ô±¾ÊµÑéµÄÀí½â£¬À­Á¦FODºÍFOEµÄºÏÁ¦µÄ²âÁ¿ÖµÓ¦ÊÇͼÖеÄ_________(Ñ¡Ìî¡°F¡±»ò¡°F¡ä¡±)£»

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø