题目内容
已知关于
的不等式
,其中
。
⑴试求不等式的解集
;
⑵对于不等式的解集
,若满足
(其中
为整数集)。试探究集合
能否为有限集?若能,求出使得集合
中元素个数最少的
的所有取值,并用列举法表示集合
;若不能,请说明理由。
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⑴试求不等式的解集
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⑵对于不等式的解集
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(1)见解析(2)
,故集合
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(1)当
时,
;当
且
时,
;
当
时,
;(不单独分析
时的情况不扣分)
当
时,
。(10分)
(2)由(1)知:当
时,集合
中的元素的个数无限;
当
时,集合
中的元素的个数有限,此时集合
为有限集。(12分)
因为
,当且仅当
时取等号,
所以当
时,集合
的元素个数最少。(14分)
此时
,故集合
。(16分)
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当
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当
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(2)由(1)知:当
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当
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因为
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所以当
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此时
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