题目内容

(08年惠州一中三模理) 设函数

   (Ⅰ)求的最小正周期;

   (Ⅱ)在△ABC中,abc分别是角ABC的对边,

         求bc的长.

解析:(Ⅰ)

                

                                                                      

              ∴                                                                                                                    

   (Ⅱ)f (A) = 2,    即                            

       

        ∴b2 + c2bc = 3                                          ①

        又b2 + c2 + 2bc = 9                                        ②

        ②-①      bc = 2                                    ③

b + c = 3                                             ④

b > c                                                   ⑤

解③④⑤得                                        

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