题目内容
如图,在△AOB中,





解:=
+
=
+
,
=λa,
=μb?设
=m
=m(
-
)=m(b-λa),
=n
=n(
-
)=n(a-μb).?∴λa+m(b-λa)=μb+n(a-μb),?∴(λ-mλ-n)a=(μ-μn-m)b.?又a与b不共线,∴
解得
?∴
=λa+
(b-λa)=
a+
b.

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题目内容
如图,在△AOB中,解:=
+
=
+
,
=λa,
=μb?设
=m
=m(
-
)=m(b-λa),
=n
=n(
-
)=n(a-μb).?∴λa+m(b-λa)=μb+n(a-μb),?∴(λ-mλ-n)a=(μ-μn-m)b.?又a与b不共线,∴
解得
?∴
=λa+
(b-λa)=
a+
b.