题目内容
已知点F1,F2是双曲线
=1(a>0,b>0)的左、右焦点,点P是双曲线上的一点,且
=0,则△PF1F2的面积为( )
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A.ab | B.![]() | C.b2 | D.a2 |
C
∵
=0,∴
,不妨设点P在双曲线的右支上,则可得,
⇒|PF1||PF2|=2b2,
∴S△PF1F2=
|PF1||PF2|=b2,故选C
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∴S△PF1F2=
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A.ab | B.![]() | C.b2 | D.a2 |