题目内容
若数列{an}的前n项积为n2,那么当n≥2时,{an}的通项公式为( )
A.an=2n-1 | B.an=n2 |
C.an= | D.an= |
D
本题考查数列的通项公式的求法.
由数列{an}的前n项积为
,有
,
,上述两式相除得
,即![](http://thumb.1010pic.com/pic2/upload/papers/20140823/20140823182247087959.png)
故正确答案为D
由数列{an}的前n项积为
![](http://thumb.1010pic.com/pic2/upload/papers/20140823/20140823182246993331.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140823/20140823182247024711.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140823/20140823182247055993.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140823/201408231822470711095.png)
![](http://thumb.1010pic.com/pic2/upload/papers/20140823/20140823182247087959.png)
故正确答案为D
![](http://thumb2018.1010pic.com/images/loading.gif)
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题目内容
A.an=2n-1 | B.an=n2 |
C.an= | D.an= |