题目内容
(1)化简
;
(2)求值:
.
sin(2π-α)cos(π+α) |
cos(π-α)sin(3π-α)sin(-α-π) |
(2)求值:
| ||
sin12°(4cos212°-2) |
(1)
=
=-
;
(2)
=
=
=
=-
=-4
.
sin(2π-α)cos(π+α) |
cos(π-α)sin(3π-α)sin(-α-π) |
-sinα•(-cosα) |
-cosα•sinα•sinα |
1 |
sinα |
(2)
| ||
sin12°(4cos212°-2) |
=
| ||||||
2sin12°cos24° |
=
2
| ||||||||
2sin12°•cos12°•cos24° |
=
2
| ||
sin24°•cos24° |
=-
2
| ||
|
=-4
3 |
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