题目内容
若AB是过椭圆
A.

B.

C.

D.

【答案】分析:假设点的坐标,将斜率用坐标表示,再将A,M的坐标代入椭圆方程可求
解答:解:设A(x1,y1),M(x,y),则B(-x1,-y1),则kAM•kBM=
∵A,M在椭圆上,
∴
,
,两式相减,可得KAM•KBM=-
,
故选B.
点评:本题主要考查了圆锥曲线的共同特征.考查了学生综合分析问题和解决问题的能力.
解答:解:设A(x1,y1),M(x,y),则B(-x1,-y1),则kAM•kBM=

∵A,M在椭圆上,
∴



故选B.
点评:本题主要考查了圆锥曲线的共同特征.考查了学生综合分析问题和解决问题的能力.

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[
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A .6 |
B .12 |
C .24 |
D .48 |