题目内容

函数f (x) = x2bxc对任意实数t,都有f (2t) = f (2t),那么   (    )

(A) f (2)f (1)f (4)   (B) f (1)f (2)f (4)

(C) f (2)f (4)f (1)   (D) f (4)f (2)f (1)

 

答案:A
提示:

注意对称轴为 x = 2

 


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