题目内容
(2013•上海)若cosxcosy+sinxsiny=
,sin2x+sin2y=
,则sin(x+y)=
.
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分析:利用两角差的余弦公式及cosxcosy+sinxsiny=
,可得cos(x-y)=
,再利用和差化积公式sin2x+sin2y=
,得到2sin(x+y)cos(x-y)=
,即可得出sin(x+y).
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解答:解:∵cosxcosy+sinxsiny=
,∴cos(x-y)=
.
∵sin2x+sin2y=
,∴2sin(x+y)cos(x-y)=
,
∴2sin(x+y)×
=
,
∴sin(x+y)=
.
故答案为
.
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2 |
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∵sin2x+sin2y=
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∴2sin(x+y)×
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∴sin(x+y)=
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故答案为
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点评:熟练掌握两角和差的正弦余弦公式及和差化积公式是解题的关键.
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