题目内容
已知U={2,3,4,5,6},M={3,4,5},N={2,4,6},则( )
分析:由题意,由全集U={2,3,4,5,6},M={3,4,5},N={2,4,6},求出它们的交集、并集或补集即可得到答案.
解答:解:∵全集U={2,3,4,5,6},M={3,4,5},N={2,4,6},
∴CUM={2,6},CUN=[3,5}.
∴M∩N={4},故A错;
M∪N={2,3,4,5,6}=U,故B对;
(CUN)∪M={3,4,5},故C错;
(CUM)∩N={2},故D错.
故选B.
∴CUM={2,6},CUN=[3,5}.
∴M∩N={4},故A错;
M∪N={2,3,4,5,6}=U,故B对;
(CUN)∪M={3,4,5},故C错;
(CUM)∩N={2},故D错.
故选B.
点评:本题考查交并补集的运算,属于集合中的基本运算题,熟练掌握交、并、补运算的定义是解题的关键.

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