题目内容
如右图,定圆半径为
,圆心为
,则直线
与直线
的交点在( )
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A.第一象限 | B.第二象限 | C.第三象限 | D.第四象限 |
D
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分析:先求出两直线的交点的坐标,由题中的图象可知,b>a>c,再判断交点的横坐标、纵坐标的符号,从而得到
两直线的交点所在的象限.
解:把直线ax+by+c=0与直线x+y-1="0" 联立方程组,解得它们的交点坐标为(
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由题中的图象可知,b>a>c,故有
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∴交点(
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故选 D.
点评:本题考查求两直线的交点的坐标的方法,通过考查交点的横坐标、纵坐标的符号,判断交点所在的象限.
关键是解读图象信息,得到b>a>c,体现了数形结合数学思想.
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