题目内容
(1)计算:0.064-
-(-
)0+7log72+0.25
×0.5-4;
(2)lg
-lg
+lg12.5-log89•log278.
1 |
3 |
1 |
8 |
5 |
2 |
(2)lg
1 |
2 |
5 |
8 |
分析:(1)利用指数的运算法则和运算性质,把0.064-
-(-
)0+7log72+0.25
×0.5-4等价转化为
-1+2+0.55×0.5-4,由此能求出结果.
(2)利用对数的运算法则和运算性质,把lg
-lg
+lg12.5-log89•log278等价转化为lg(
×
×12.5)-
×
,由此能求出结果.
1 |
3 |
1 |
8 |
5 |
2 |
1 |
0.4 |
(2)利用对数的运算法则和运算性质,把lg
1 |
2 |
5 |
8 |
1 |
2 |
8 |
5 |
lg9 |
lg8 |
lg8 |
lg27 |
解答:解:(1)0.064-
-(-
)0+7log72+0.25
×0.5-4
=
-1+2+0.55×0.5-4
=
+1+0.5
=4.
(2)lg
-lg
+lg12.5-log89•log278
=lg(
×
×12.5)-
×
=lg10-
=1-
=
.
1 |
3 |
1 |
8 |
5 |
2 |
=
1 |
0.4 |
=
5 |
2 |
=4.
(2)lg
1 |
2 |
5 |
8 |
=lg(
1 |
2 |
8 |
5 |
lg9 |
lg8 |
lg8 |
lg27 |
=lg10-
2lg3 |
3lg3 |
=1-
2 |
3 |
=
1 |
3 |
点评:本题考查指数和对数的运算法则和运算性质的求法,是基础题.解题时要认真审题,仔细解答.
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