题目内容
某双曲线的离心率为
A.

B.

C.

D.

【答案】分析:将椭圆的方程化为标准形式,求出椭圆的焦点坐标即双曲线的焦点坐标,利用双曲线的离心率公式求出双曲线中的参数a,利用双曲线的三个参数的关系求出b,得到双曲线的方程.
解答:解:4x2+9y2=36即为
∴椭圆的焦点为
∴双曲线的焦点为
∴双曲线中c=
∵
∴a=2
∴b2=c2-a2=1
∴
故选A
点评:求圆锥切线的方程问题,一般利用待定系数法,注意椭圆的三个参数关系为:b2=a2-c2;而双曲线中三个参数的关系为b2=c2-a2.
解答:解:4x2+9y2=36即为

∴椭圆的焦点为

∴双曲线的焦点为

∴双曲线中c=

∵

∴a=2
∴b2=c2-a2=1
∴

故选A
点评:求圆锥切线的方程问题,一般利用待定系数法,注意椭圆的三个参数关系为:b2=a2-c2;而双曲线中三个参数的关系为b2=c2-a2.

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