题目内容
已知
A.

B.

C.

D.

【答案】分析:由条件求得sinα=-
,cosα=
=
,再由tanα=
求得结果.
解答:解:∵
,
∴sinα=-
,cosα=
=
,
∴tanα=
=-
,
故选 B.
点评:本题主要考查同角三角函数的基本关系、诱导公式的应用,属于基础题.




解答:解:∵

∴sinα=-



∴tanα=


故选 B.
点评:本题主要考查同角三角函数的基本关系、诱导公式的应用,属于基础题.

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