题目内容
△ABC中,

【答案】分析:利用向量模的平方等于向量的平方,将向量模的最值转化为二次函数的最值,利用二次函数最值的求法求出最小值.
解答:解:

=4λ2+4(1-λ)2
=8λ2-8λ+4
对称轴为
当
时,有最小值2
故f(λ)的最小值是
股答案为
点评:本题考查向量模的平方等于向量的平方;将向量模的最值问题等价转化为二次函数最值的求法问题.
解答:解:


=4λ2+4(1-λ)2
=8λ2-8λ+4
对称轴为

当

故f(λ)的最小值是

股答案为

点评:本题考查向量模的平方等于向量的平方;将向量模的最值问题等价转化为二次函数最值的求法问题.

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