题目内容
盒子中装有四张大小形状均相同的卡片,卡片上分别标有数字-1,0,1,2.称“从盒中随机抽取一张,记下卡片上的数字后并放回”为一次试验(设每次试验的结果互不影响).
(1)在一次试验中,求卡片上的数字为正数的概率;
(2)在四次试验中,求至少有两次卡片上的数字都为正数的概率;
(3)在两次试验中,记卡片上的数字分别为X,η,试求随机变量X=X·η的分布列与数学期望E(X).
(1)在一次试验中,求卡片上的数字为正数的概率;
(2)在四次试验中,求至少有两次卡片上的数字都为正数的概率;
(3)在两次试验中,记卡片上的数字分别为X,η,试求随机变量X=X·η的分布列与数学期望E(X).
(1)
(2)
(3)![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400526338.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400541377.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
(1)记事件A为“在一次试验中,卡片上的数字为正数”,则P(A)=
=
.
(2)记事件B为“在四次试验中,至少有两次卡片上的数字都为正数”.由(1)可知在一次试验中,卡片上的数字为正数的概率是
.所以P(B)=1-
=
.
(3)由题意可知,X,η的可能取值都为-1,0,1,2,
所以随机变量X的可能取值为-2,-1,0,1,2,4.
P(X=-2)=
×
×2=
;
P(X=-1)=
×
×2=
;
P(X=0)=
×
×7=
;
P(X=1)=
×
×2=
;
P(X=2)=
×
×2=
;
P(X=4)=
×
=
.
所以随机变量X的分布列为
所以E(X)=-2×
-1×
+0×
+1×
+2×
+4×
=
.
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400573382.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400526338.png)
(2)记事件B为“在四次试验中,至少有两次卡片上的数字都为正数”.由(1)可知在一次试验中,卡片上的数字为正数的概率是
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400526338.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/201408240344006191163.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400541377.png)
(3)由题意可知,X,η的可能取值都为-1,0,1,2,
所以随机变量X的可能取值为-2,-1,0,1,2,4.
P(X=-2)=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400666352.png)
P(X=-1)=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400666352.png)
P(X=0)=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400760419.png)
P(X=1)=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400666352.png)
P(X=2)=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400666352.png)
P(X=4)=
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400869362.png)
所以随机变量X的分布列为
X | -2 | -1 | 0 | 1 | 2 | 4 |
P | ![]() | ![]() | ![]() | ![]() | ![]() | ![]() |
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400666352.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400666352.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400760419.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400666352.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400666352.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400869362.png)
![](http://thumb.zyjl.cn/pic2/upload/papers/20140824/20140824034400557303.png)
![](http://thumb.zyjl.cn/images/loading.gif)
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