分析:由题设知a5=2,a4=4,有①②两种情况:①a3=1,a2=2,a1=4,即m=4;②a3=8,a2=16,有③④两种情况:③a1=5,即m=5;④a1=32,即m=32.
解答:解:∵数列{a
n}满足:a
1=m(m为正整数),a
n+1=
| ,an=2k,k∈N+ | 3an+1,an=2k-1,k∈N+ |
| |
,
将a
6=1代入得a
5=2,a
4=4,有①②两种情况:
①a
3=1,a
2=2,a
1=4,即m=4;
②a3=8,a
2=16,有③④两种情况:
③a
1=5,即m=5;
④a
1=32,即m=32.
故答案为:4,5,32.
点评:本题考查数列的性质和应用,解题时要认真审题,仔细解答,注意公式的合理运用.