题目内容
设向量
,
的夹角为60°且|
|=|
|=1,如果
,
,
.
(1)证明:A、B、D三点共线.
(2)试确定实数k的值,使k的取值满足向量
与向量
垂直.
解:(1)∵
∴
即
共线,
∵
有公共点B
∴A,B,D三点共线.
(2)∵
∴

∵|
|=|
|=1,且
•
=
cos60°=
∴
解得
分析:(1)利用向量共线证明三点共线,先将
表示为
与
的和,再证明
,最后说明
有公共点B,即可证明A、B、D三点共线
(2)因为向量
,
的夹角为60°且|
|=|
|=1,所以
•
=
,故可将向量
,
作为基底,研究
与向量
垂直的问题,利用向量垂直的充要条件列方程即可得k值
点评:本题考察了向量共线的充要条件,向量垂直的充要条件,向量数量积运算性质及应用.

∴


∵

∴A,B,D三点共线.
(2)∵

∴


∵|






∴

解得

分析:(1)利用向量共线证明三点共线,先将





(2)因为向量











点评:本题考察了向量共线的充要条件,向量垂直的充要条件,向量数量积运算性质及应用.

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