题目内容
15.设等比数列的公比为q,前n项和为Sn,若Sn+1,Sn,Sn+2成等差数列,则q的值为 .
15.-2
解析:∵S n+1,Sn,S n+2成等差数列,
∴Sn-S n+1=S n+2-Sn,即-a n+1=a n+2+a n+1.
∴an+2=-2an+1.∴q==-2.
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题目内容
15.设等比数列的公比为q,前n项和为Sn,若Sn+1,Sn,Sn+2成等差数列,则q的值为 .
15.-2
解析:∵S n+1,Sn,S n+2成等差数列,
∴Sn-S n+1=S n+2-Sn,即-a n+1=a n+2+a n+1.
∴an+2=-2an+1.∴q==-2.