题目内容
设向量
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A.

B.

C.3,π
D.3,4π
【答案】分析:先要理解题目条件中给出的一种新定义,看准规定的运算,根据所给的运算整理要求解的结论,得到y=f(x)的表示式,后面的问题变为通过恒等变形进行三角函数性质的应用.
解答:解:设p点的坐标是(x,sinx)
∵
⊙
=(
x,3sinx)+(
,0)
=(
x+
,3sinx),
∵点Q在y=f(x)的图象上运动,
∴y=3sin(
x+
)
∴T=4π,
最大值为3
故选D
点评:要让学生体会思路的形成过程,体会数学思想方法的应用.引导学生发现解题方法,展示思路的形成过程,总结解题规律.指导学生搞好解题后的反思,从而提高学生综合应用知识分析和解决问题的能力.
解答:解:设p点的坐标是(x,sinx)
∵


=(


=(


∵点Q在y=f(x)的图象上运动,
∴y=3sin(


∴T=4π,
最大值为3
故选D
点评:要让学生体会思路的形成过程,体会数学思想方法的应用.引导学生发现解题方法,展示思路的形成过程,总结解题规律.指导学生搞好解题后的反思,从而提高学生综合应用知识分析和解决问题的能力.
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设向量
,定义一种向量积:
.已知
,点P在y=sinx的图象上运动,点Q在y=f(x)的图象上运动,且满足
(其中O为坐标原点),则y=f(x)的最大值及最小正周期分别是( )
A.
B.
C.3,π
D.3,4π




A.

B.

C.3,π
D.3,4π