Question

若x、y是正数，则(x+)²+(y+)²的最小值是__________.

Answer 1

答案：4

解析：依题意(x+)²+(y+)²=(x²+)+(y²+)+()≥2×+2×+2=4.

当且仅当x²=,y²=,,即x=y=时取等号.