题目内容
.(本小题满分1 2分)设△ABC的内角A、B、C所对的边分别为a、b、c.已知a=3,B=,S△ABC=6
( I )求△ABC的周长;
(Ⅱ)求sin2A的值.
( I )求△ABC的周长;
(Ⅱ)求sin2A的值.
解:(Ⅰ)∵ ,
∴ ,
∴ ,···························· 2分
由余弦定理得,
,
∴ ,···························· 5分
∴ 的周长为.············· 6分
(Ⅱ)由正弦定理得,,
∴ ,················· 8分
∵ ,
∴ ,故角为锐角,····················· 9分
∴ ,···················· 10分
∴ .··········· 12分
∴ ,
∴ ,···························· 2分
由余弦定理得,
,
∴ ,···························· 5分
∴ 的周长为.············· 6分
(Ⅱ)由正弦定理得,,
∴ ,················· 8分
∵ ,
∴ ,故角为锐角,····················· 9分
∴ ,···················· 10分
∴ .··········· 12分
略
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