题目内容
计算下列各式的值
(1)0.064 -
-(-
)0+160.75+0.25
(2)lg5+(log32)•(log89)+lg2.
(1)0.064 -
1 |
3 |
7 |
8 |
1 |
2 |
(2)lg5+(log32)•(log89)+lg2.
分析:(1)化小数指数为分数指数,0次幂的值代1,然后利用有理指数幂进行化简求值;
(2)首先利用换底公式化为常用对数,然后利用对数的运算性质进行化简计算.
(2)首先利用换底公式化为常用对数,然后利用对数的运算性质进行化简计算.
解答:解:(1)0.064 -
-(-
)0+160.75+0.25
=((0.4)3)-
-1+(24)
+(0.52)
=(0.4)-1-1+8+0.5
=2.5-1+8+0.5
=10;
(2)lg5+(log32)•(log89)+lg2
=lg5+
•
+lg2
=1+
•
=1+
=
.
1 |
3 |
7 |
8 |
1 |
2 |
=((0.4)3)-
1 |
3 |
3 |
4 |
1 |
2 |
=(0.4)-1-1+8+0.5
=2.5-1+8+0.5
=10;
(2)lg5+(log32)•(log89)+lg2
=lg5+
lg2 |
lg3 |
lg9 |
lg8 |
=1+
lg2 |
lg3 |
2lg3 |
3lg2 |
=1+
2 |
3 |
5 |
3 |
点评:本题考查了对数的运算性质,考查了有理指数幂的化简与求值,是基础的运算题.
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