题目内容
已知
A.
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B.
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C.
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D.
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【答案】分析:由条件可得 cos2A+isin2A=
,再利用两个复数相等的充要条件可得cos2A=-
,sin2A=
.再由 0<A<π,得到 A=
.
解答:解:∵
,
∴cos2A+isin2A=
,∴cos2A=-
,sin2A=
.
∵0<A<π,∴A=
.
故选:B.
点评:本题主要考查复数代数形式的混合运算,两个复数相等的充要条件,根据三角函数的值求角,属于基础题.
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
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解答:解:∵

∴cos2A+isin2A=

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∵0<A<π,∴A=

故选:B.
点评:本题主要考查复数代数形式的混合运算,两个复数相等的充要条件,根据三角函数的值求角,属于基础题.

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