题目内容
已知S是△ABC所在平面外一点,D是SC的中点,若
=x
+y
+z
,则x+y+z=______.
BD |
AB |
AC |
AS |
如图,D是SC的中点,故有
=
(
+
)
=
(
+
)+
(
-
)
=-
+
+
又由已知
=x
+y
+z
故x=-1,y=
,z=
代入得x+y+z=0
故答案为 0
BD |
1 |
2 |
BS |
BC |
=
1 |
2 |
BA |
AS |
1 |
2 |
AC |
AB |
=-
AB |
1 |
2 |
AC |
1 |
2 |
AS |
又由已知
BD |
AB |
AC |
AS |
故x=-1,y=
1 |
2 |
1 |
2 |
代入得x+y+z=0
故答案为 0
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