题目内容
设a=(cos(x-
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(1)设f(x)=a·b,试在如图的坐标系中画出函数y=f(x)在[-π,
π]上的简图;
(2)设方程f(x)=a在[0,π]上的三正根依次成等比数列,试求实数a的值.
解:(1)a·b=cos(x-
)-
sin(x-
)=cos
cos(x-
)-sin
sin(x-
)
=cos(+x-
)=cos(x+
),∴f(x)=cos(x+
).
x | - | - |
|
|
|
|
| |
f(x) | 0 | 1 | 0 | -1 | 0 | 1 | 0 | -1 |
(2)方程f(x)=a的根即为y=f(x)的图象与直线y=a交点的横坐标,如(1)简图,设三根分别为0<x1<x2<x3,则A(x1,a),B(x2,a)两点关于直线x=π对称,
故x1+x2=π.而x3-x1=2π,∴x2=
π-x1,x3=2π+x1.
由x22=x1x3得(π-x1)2=x1(2π+x1),解得x1=
π,
∴a=f(x1)=cos(x1+)=cos
π.
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