ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿ÒÔAΪÔÁϺϳÉÒ»ÖÖÖÎÁÆÐÄÔಡҩÎïµÄÖмäÌåMÁ÷³ÌÈçÏÂͼËùʾ£º
ÒÑÖª£º
¢¡.ROH + R£§XROR£§+ HX £¨X£½Cl¡¢Br¡¢I£©
¢¢.È©ÔÚÒ»¶¨Ìõ¼þÏ¿ÉÒÔ·¢ÉúÈçÏÂת»¯£º
Çë»Ø´ðÏÂÁÐÎÊÌâ £º
£¨1£©ÒÑÖª·´Ó¦¢ñΪ¼Ó³É·´Ó¦£¬ÎïÖÊXµÄ½á¹¹¼òʽΪ___________¡£
£¨2£©ÈôÎïÖÊYÖк¬ÓÐÂÈÔªËØ£¬ÎïÖÊYµÄ½á¹¹¼òʽΪ___________¡£
£¨3£©1molG×î¶à¿ÉÓë___________mol Br2·´Ó¦¡£
£¨4£©CÉú³ÉDµÄ»¯Ñ§·´Ó¦·½³ÌʽΪ___________________________¡£
£¨5£©HΪGµÄͬ·ÖÒì¹¹Ì壬ͬʱÂú×ãÏÂÁÐÌõ¼þµÄHµÄ½á¹¹¼òʽΪ_________¡£
A£®ÄÜÓëFeCl3·¢ÉúÏÔÉ«·´Ó¦
B£®ºË´Å¹²ÕñÇâÆ×ÏÔʾ5×é·å
C£®1molGÔÚÒ»¶¨Ìõ¼þÏÂ×î¶àÄÜÓë3mol NaOH·´Ó¦
£¨6£©²ÎÕÕÉÏÊöºÏ³É·Ïߣ¬ÇëÉè¼ÆÓÉDºÏ³ÉEµÄ·Ïß¡£
¡¾´ð°¸¡¿£¨1£©HCHO
£¨2£©
£¨3£©2
£¨4£©
£¨5£©
£¨6£©
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º¸ù¾ÝÌâ¸øÐÅÏ¢ºÍת»¯¹ØϵÍƶϣ¬AΪ£¬XΪHCHO£¬YΪ¡£
£¨1£©ÒÑÖª·´Ó¦¢ñΪ¼Ó³É·´Ó¦£¬ÎïÖÊXµÄ½á¹¹¼òʽΪHCHO¡£
£¨2£©ÈôÎïÖÊYÖк¬ÓÐÂÈÔªËØ£¬ÎïÖÊYµÄ½á¹¹¼òʽΪ¡£
£¨3£©·ÓôÇ»ùÁÚλ¡¢¶ÔλÉϵÄÒ×±»äåË®ÖеÄäåÔ×ÓÈ¡´ú£¬1molG×î¶à¿ÉÓë2mol Br2·´Ó¦¡£
£¨4£©CÉú³ÉDΪ´¼ôÇ»ùÔÚÍ×÷´ß»¯¼Á¼ÓÈȵÄÌõ¼þϱ»ÑõÆøÑõ»¯ÎªÈ©»ù£¬»¯Ñ§·´Ó¦·½³ÌʽΪ¡£
£¨5£©GµÄ·Ö×ÓʽΪC10H10O3£¬A£®ÄÜÓëFeCl3·¢ÉúÏÔÉ«·´Ó¦£¬º¬ÓзÓôÇ»ù£»B£®ºË´Å¹²ÕñÇâÆ×ÏÔʾ5×é·å£¬º¬ÓÐ5ÖÖÇâÔ×Ó£»C£®1molGÔÚÒ»¶¨Ìõ¼þÏÂ×î¶àÄÜÓë3mol NaOH·´Ó¦£¬HµÄ½á¹¹¼òʽΪ¡£
£¨6£©¸ù¾ÝÌâ¸øÐÅÏ¢Éè¼ÆÓÉDºÏ³ÉEµÄ·Ïß¼û´ð°¸¡£