ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Ä³½ðÓãÆ·ÖÖÓÐÉ«ÁÛÓëÎÞÉ«ÁÛÊÇÒ»¶ÔÏà¶ÔÐÔ×´£¬ÊÜÒ»¶ÔµÈλ»ùÒò£¨A¡¢a£©¿ØÖÆ£¬ÒÑÖªÔÚº¬ÓлùÒòA¡¢aµÄͬԴȾɫÌåÉÏ£¬ÁíÓÐÒ»¶ÔµÈλ»ùÒò¾ßÓÐÖÂËÀЧӦ£¬µ«ÖÂËÀ»ùÒòµÄ±í´ï»áÊÜÐÔ±ðµÄÓ°Ïì¡£Çë¸ù¾ÝÏÂÁÐÔÓ½»×éºÏ¼°ÔÓ½»½á¹û»Ø´ðÎÊÌâ¡£
ÔÓ½»×éºÏ | Ç×±¾ÀàÐÍ | F1 | |
´Æ | ÐÛ | ||
¢ñ | ÓÐÉ«ÁÛ¡â¡ÁÓÐÉ«ÁÛ¡á | ÓÐÉ«ÁÛ437 | ÓÐÉ«ÁÛ215 |
¢ò | ÎÞÉ«ÁÛ¡â¡ÁÓÐÉ«ÁÛ¡á | ÎÞÉ«ÁÛ220??? ÓÐÉ«ÁÛ222 | ÎÞÉ«ÁÛ226??? ÓÐÉ«ÁÛ224 |
¢ó | ¢ò×éÖеÄÓÐÉ«ÁÛF1×Ô½» | ÎÞÉ«ÁÛ242??? ÓÐÉ«ÁÛ716 | ÎÞÉ«ÁÛ238??? ÓÐÉ«ÁÛ486 |
?
£¨1£©ÔÚÓÐÉ«ÁÛÓëÎÞÉ«ÁÛÕâ¶ÔÏà¶ÔÐÔ×´ÖÐ________ΪÏÔÐÔÐÔ×´£¬¢ñ×éÇ×±¾µÄ»ùÒòÐÍÊÇ________¡£
£¨2£©´ÓÉÏÊöÔÓ½»×éºÏÖпÉÒÔÅжÏÖÂËÀ»ùÒòÊÇ________£¨Ìî¡°ÏÔ¡±»ò¡°Òþ¡±£©ÐÔ»ùÒò¡£Ñо¿·¢ÏÖ¸ÃÖÂËÀ»ùÒòÊÇÓÉ»ùÒòÍ»±ä²úÉú£¬×ÔÈ»Ìõ¼þϼ´Ê¹ÔÚDNA·Ö×Ó¸´Öƹý³ÌÖлùÒòµÄÍ»±äÂÊÒ²±È½ÏµÍ£¬ÔÒò________________¡£
£¨3£©¢ó×éµÄ×Ó´úÖе¼Ö´ÆÐÛÖÐÓÐÉ«ÁÛÓëÎÞÉ«ÁÛ±ÈÀý²îÒìµÄ¿ÉÄÜÔÒòÊÇ________¡£
ÇëÀûÓâó×é²ÄÁÏÉè¼Æ·½°¸ÑéÖ¤ÄãµÄ½âÊÍ£º
¢ÙÉè¼Æ˼·£º________________________________________________¡£
¢Ú½á¹ûºÍ½áÂÛ£º¼××é×Ó´úÐÔ×´±ÈÀýΪ2£º1£¬ÒÒ×é×Ó´úÐÔ×´±ÈÀýÊÇ________£¬Ôò¼ÙÉèÕýÈ·¡£
¡¾´ð°¸¡¿ÓÐÉ«ÁÛ??? AA£¨¡â£©Aa£¨¡á£©??? Òþ??? DNA·Ö×Ó¶ÀÌصÄË«ÂÝÐý½á¹¹Îª¸´ÖÆÌṩÁ˾«È·µÄÄ£°å£¬ÑϸñµÄ¼î»ù»¥²¹Åä¶ÔÔÔò±£Ö¤¸´ÖÆ׼ȷµÄ½øÐÐ??? AAµÄÐÛÐÔ¸öÌ庬ÓÐÁ½¸öÖÂËÀ»ùÒò¶øËÀÍö??? ¼××éÈ¡¢ó×é×Ó´úÖжà¸öÓÐÉ«ÁÛ´ÆÐÔ¸öÌåÓëÎÞÉ«ÁÛÐÛÐÔ¸öÌå²â½»£¬ÒÒ×éÈ¡¢ó×é×Ó´úÖжà¸öÓÐÉ«ÁÛÐÛÐÔ¸öÌåÓëÎÞÉ«ÁÛ´ÆÐÔ¸öÌå²â½»£¬·Ö±ðͳ¼ÆÁ½×é²â½»×Ó´úµÄÓÐÉ«ÁÛÓëÎÞÉ«Á۵ķÖÀë±È??? 1£º1???
¡¾½âÎö¡¿
»ùÒòÔÚÌåϸ°ûÄÚÊdzɶԵģ¬ÆäÖÐÒ»¸öÀ´×Ô¸¸±¾£¬Ò»¸öÀ´×Ôĸ±¾¡£ÔÚÐγÉÅä×Ó¼´Éúֳϸ°ûʱ£¬³É¶ÔµÄ»ùÒò±Ë´Ë·ÖÀ룬·Ö±ð½øÈëµ½²»Í¬µÄÅä×ÓÖУ¬Ã¿¸öÅä×ÓÖÐÖ»º¬ÓгɶԻùÒòÖеÄÒ»¸ö¡£
º¬ÓеÈλ»ùÒòµÄ»ùÒòÐÍΪÔÓºÏ×Ó£¬²»º¬µÈλ»ùÒòµÄ»ùÒòÐÍΪ´¿ºÏ×Ó¡£ÑéÖ¤»ò̽¾¿»ùÒòÐͳ£Óò⽻·¨¡£
£¨1£©¸ù¾ÝÔÓ½»×éºÏIII¿ÉÖª£¬ÓÐÉ«ÁÛ×Ô½»Äܹ»²úÉúÎÞÉ«ÁÛ£¬¿ÉÖªÔÚÓÐÉ«ÁÛÓëÎÞÉ«ÁÛÕâ¶ÔÏà¶ÔÐÔ×´ÖÐÓÐÉ«ÁÛΪÏÔÐÔÐÔ×´¡£ÔÓ½»×éºÏ¢ñµÄ½á¹û£¬´ÆÐÛ±ÈÀýΪ2¡Ã1£¬ËµÃ÷¢ñ×éÇ×±¾µÄ»ùÒòÐÍÊÇAA£¨¡â£©Aa£¨¡á£©£¬ÆäÖÐAAÔÚÐÛÐÔÖÐÖÂËÀ¡£
£¨2£©´ÓÉÏÊöÔÓ½»×éºÏÖпÉÒÔÅжÏÖÂËÀ»ùÒòÊÇÒþÐÔ»ùÒò£¬ÈôΪÏÔÐÔ»ùÒòÖÂËÀ£¬ÔòÕý³£µÄ¸öÌåºó´ú²»»á³öÏÖÖÂËÀµÄ¸öÌå¡£Ñо¿·¢ÏÖ¸ÃÖÂËÀ»ùÒòÊÇÓÉ»ùÒòÍ»±ä²úÉú£¬×ÔÈ»Ìõ¼þϼ´Ê¹ÔÚDNA·Ö×Ó¸´Öƹý³ÌÖлùÒòµÄÍ»±äÂÊÒ²±È½ÏµÍ£¬ÔÒòDNA·Ö×Ó¶ÀÌصÄË«ÂÝÐý½á¹¹Îª¸´ÖÆÌṩÁ˾«È·µÄÄ£°å£¬ÑϸñµÄ¼î»ù»¥²¹Åä¶ÔÔÔò±£Ö¤¸´ÖÆ׼ȷµÄ½øÐС£
£¨3£©ÓÐÒ»¶ÔµÈλ»ùÒò¾ßÓÐÖÂËÀЧӦ£¬µ«ÖÂËÀ»ùÒòµÄ±í´ï»áÊÜÐÔ±ðµÄÓ°Ï죬¢ó×éµÄ×Ó´úÖе¼Ö´ÆÐÛÖÐÓÐÉ«ÁÛÓëÎÞÉ«ÁÛ±ÈÀý²îÒìµÄ¿ÉÄÜÔÒòÊÇAAµÄÐÛÐÔ¸öÌ庬ÓÐÁ½¸öÖÂËÀ»ùÒò¶øËÀÍö¡£
¢Ù¼××éÈ¡¢ó×é×Ó´úÖжà¸öÓÐÉ«ÁÛ´ÆÐÔ¸öÌ壨A_£©ÓëÎÞÉ«ÁÛÐÛÐÔ¸öÌ壨aa£©²â½»£¬ÒÒ×éÈ¡¢ó×é×Ó´úÖжà¸öÓÐÉ«ÁÛÐÛÐÔ¸öÌ壨A_£©ÓëÎÞÉ«ÁÛ´ÆÐÔ¸öÌ壨aa£©²â½»£¬·Ö±ðͳ¼ÆÁ½×é²â½»×Ó´úµÄÓÐÉ«ÁÛÓëÎÞÉ«Á۵ķÖÀë±È¡£
¢ÚÈôAAµÄÐÛÐÔ¸öÌ庬ÓÐÁ½¸öÖÂËÀ»ùÒò¶øËÀÍö£¬Ôò¼××éĸ±¾Îª£¨1/3AA¡¢2/3Aa£©£¬¸¸±¾Îªaa£¬×Ó´úÐÔ×´±ÈÀýΪÓÐÁÛ£¨Aa£©¡ÃÎÞÁÛ(£¨aa£©=2£º1£¬ÒÒ×éĸ±¾Îªaa£¬¸¸±¾Îª£¨Aa£©£¬×Ó´úÐÔ×´±ÈÀýÊÇÓÐÁÛ£¨Aa£©¡ÃÎÞÁÛ(£¨aa£©=1¡Ã1¡£
¡¾ÌâÄ¿¡¿Ï±íΪÈËÌåϸ°ûÍâÒººÍϸ°ûÄÚÒºµÄÎïÖÊ×é³ÉºÍº¬Á¿µÄ²â¶¨Êý¾Ý¡£ÏÂÁÐÏà¹ØÐðÊö´íÎóµÄÊÇ
³É·Ö£¨mmol/L£© | Na+ | K+ | Ca2+ | Mg2+ | Cl- | ÓлúËá | µ°°×ÖÊ | |
¢Ù | ¢Ú | 142 | 5.0 | 2.5 | 1.5 | 103.3 | 6.0 | 16.0 |
¢Û | 147 | 4.0 | 1.25 | 1.0 | 114.0 | 7.5 | 1.0 | |
¢Ü | 10 | 140 | 2.5 | 10.35 | 25 | - | 47 |
?
?
A. ¢ÜÊôÓÚϸ°ûÄÚÒº£¬ÒòΪÆ京Óн϶àµÄµ°°×ÖÊ¡¢K+µÈ
B. ¢ÚÊôÓÚѪ½¬£¬¢ÛÊôÓÚ×éÖ¯Òº£¬¢ÚµÄµ°°×Öʺ¬Á¿¼õÉÙ½«µ¼Ö¢ÛÔö¶à
C. ¸Îϸ°ûÖеÄCO2´Ó²úÉú³¡ËùÀ©É¢µ½¢Ú¹²´©¹ý6²ãÁ×Ö¬·Ö×Ó²ã
D. ¢ÛÓë¢ÜµÄ³É·Ö´æÔÚ²îÒìµÄÖ÷ÒªÔÒòÊÇϸ°ûĤµÄÑ¡Ôñ͸¹ýÐÔ
¡¾ÌâÄ¿¡¿2019Äê8Ô£¬±»³ÆΪ¡°µØÇòÖ®·Î¡±µÄÑÇÂíÑ·ÈÈ´øÓêÁÖÔâÓö³ÖÐø´ó»ð£¬´óÅúÉÁÖÔâÔÖÄÑÐÔ»ÙÃð¡£Ñо¿ÕßÔøµ÷²éijÓêÁÖÉú̬ϵͳ£¬¹²ÓÐ5¸öÓªÑø¼¶£¨ÒÔA¡¢B¡¢C¡¢D¡¢E±íʾ£©¡£¾²â¶¨£¬Ò»ÄêÖÐÁ÷¾Õâ5¸öÓªÑø¼¶µÄÄÜÁ¿ÈçϱíËùʾ¡£»Ø´ðÏÂÁÐÎÊÌ⣺
ÓªÑø¼¶ | A | B | C | D | E |
ÄÜÁ¿£¨J?m-2£© | 160.02¡Á107 | 1001.37¡Á107 | 19.89¡Á107 | 0.37¡Á107 | 2.5¡Á107 |
?
?
£¨1£©»³ö¸ÃÓêÁÖÉú̬ϵͳµÄʳÎïÁ´_______________¡£¾Ý±í¿´³ö£¬ÄÜÁ¿ÔÚ¸÷ÓªÑø¼¶Ö®¼ä´«µÝÓÐ_________________________Ìص㣬ijһӪÑø¼¶µÄÄÜÁ¿²»ÄÜÈ«²¿´«¸øÏÂÒ»ÓªÑø¼¶µÄÔÒò__________________________£¨Ð´³öÁ½µã£©¡£
£¨2£©ÓêÁÖÔÚÎïÖÊÑ»·Öз¢»ÓÖØÒª×÷Óá£ÇëÍƲâ´óÅúÉÁÖ±»»ðÉÕ»ÙÃðºó¿ÉÄÜ´øÀ´µÄÓ°Ïì_______________________________________£¨Ð´³öÁ½µã£©¡£
£¨3£©¾ÙÀý˵³öÓêÁÖÉú̬ϵͳ¼ä½Ó¼ÛÖµ£ºÈç__________¡££¨Ð´Ò»¸öÀý×Ó¼´¿É£©