ÌâÄ¿ÄÚÈÝ
Ѫºìµ°°×ÊÇÈËºÍÆäËû¼¹×µ¶¯Îïºìϸ°ûµÄÖ÷Òª×é³É³É·Ö£¬¸ºÔðѪҺÖÐO2ºÍ²¿·ÖCO2µÄÔËÊä¡£Çë¸ù¾ÝѪºìµ°°×µÄÌáÈ¡ºÍ·ÖÀëÁ÷³Ìͼ»Ø´ðÎÊÌâ¡£
(1)½«ÊµÑéÁ÷³Ì²¹³äÍêÕû£ºAΪ________£¬BΪ________¡£Äý½ºÉ«Æ×·¨µÄ»ù±¾ÔÀíÊǸù¾Ý________¶ø´ïµ½µ°°×ÖÊ·ÖÀëµÄÓÐЧ·½·¨¡£
(2)Ï´µÓºìϸ°ûµÄÄ¿µÄÊÇÈ¥³ý________£¬Ï´µÓ´ÎÊý¹ýÉÙ£¬ÎÞ·¨³ýÈ¥£»ÀëÐÄËٶȹý¸ßºÍʱ¼ä¹ý³¤»áʹ____________һͬ³Áµí¡£´ï²»µ½·ÖÀëµÄЧ¹û¡£Ï´µÓ¸É¾»µÄ±êÖ¾ÊÇ________________¡£ÊÍ·ÅѪºìµ°°×µÄ¹ý³ÌÖÐÆð×÷ÓõÄÊÔ¼ÁÊÇ________________¡£
(3)ÔÚB¹ý³ÌÖмÓÈëÎïÖʵÄÁ¿Å¨¶ÈΪ20m mol/LµÄÁ×ËỺ³åÒº(pHΪ7.0)µÄÄ¿µÄÊÇ__________________________________________________________________¡£Èç¹ûºìÉ«Çø´ø________________£¬ËµÃ÷É«Æ×ÖùÖÆ×÷³É¹¦
£¨1£©Ñªºìµ°°×µÄÊÍ·Å ÑùÆ·µÄ¼ÓÈëºÍÏ´ÍÑ Ïà¶Ô·Ö×ÓÖÊÁ¿µÄ´óС
£¨2£©ÔÓµ°°×£¨Ñª½¬µ°°×£© °×ϸ°û£¨µÈ£© ÀëÐĺóÉÏÇåÒºÖÐûÓлÆÉ« ÕôÁóË®ºÍ¼×±½
£¨3£©Ä£ÄâÉúÎïÌåÄÚµÄÉúÀí»·¾³£¨±£³ÖÌåÍâpHºÍÌåÄÚÒ»Ö¡¢±£³Öµ°°×ÖʵÄÕý³£½á¹¹¡¢Î¬³ÖÏ´ÍÑËùÐèµÄѹÁ¦µÈºÏÀí´ð°¸¾ù¿É£©¾ùÔÈÒ»ÖµÄÒÆ¶¯
½âÎö