ÌâÄ¿ÄÚÈÝ

A¡¢B¡¢C¡¢D¡¢E¶¼ÊǶÌÖÜÆÚÔªËØ£¬Ô­×ÓÐòÊýÒÀ´ÎÔö´ó£¬A¡¢B´¦ÓÚͬһÖÜÆÚ£¬C¡¢D¡¢Eͬ´¦ÁíÒ»ÖÜÆÚ¡£C¡¢B¿É°´Ô­×Ó¸öÊý±È2¡ÃlºÍ1¡Ã1·Ö±ðÐγÉÁ½ÖÖÀë×Ó»¯ºÏÎï¼×ºÍÒÒ¡£D¡¢A°´Ô­×Ó¸öÊý±È3¡Ã2ÐγÉÀë×Ó»¯ºÏÎï±û¡£EÊǵؿÇÖк¬Á¿×î¸ßµÄ½ðÊôÔªËØ¡£¸ù¾ÝÒÔÉÏÐÅÏ¢»Ø´ðÏÂÁÐÎÊÌ⣺£¨Ã¿¿Õ2·Ö£¬¹²8·Ö£©
£¨1£©EÔªËØÔÚÖÜÆÚ±íÖеÄλÖÃÊÇ____________£¬
£¨2£©»­³öAµÄÔ­×ӽṹ¼òͼ          
£¨3£©Àë×Ó»¯ºÏÎïÒҵĵç×ÓʽÊÇ       
£¨4£©C¡¢D¡¢EÐγɵļòµ¥Àë×Ӱ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ£¨ÓÃÀë×Ó·ûºÅ±íʾ£©           


½âÎöA¨DN¡¢B¨DO¡¢C¨DNa¡¢D¨DMg¡¢E¨DAl ¡¢¼×¨D Na2O ¡¢ÒÒ¨D Na2O2 ¡¢±û¨DMg3N2

¢ÆAµÄÔ­×ӽṹʾÒâͼ£º
¢ÇNa2O2µÄµç×Óʽ£º
¢Èµç×Ó²ã½á¹¹ÏàͬµÄÀë×Ó£¬ºËµçºÉÔ½´ó£¬°ë¾¶Ô½Ð¡£¬Àë×Ӱ뾶ÓÉ´óµ½Ð¡µÄ˳ÐòÊÇNa£«  Mg2£«    Al3£« .

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
£¨2012?ÖêÖÞһģ£©ÒÑÖªA¡¢B¡¢C¡¢D¡¢E¶¼ÊǶÌÖÜÆÚÖ÷×åÔªËØ£¬ÇÒÔ­×ÓÐòÊýÒÀ´ÎÔö´ó£®A¡¢BÔ­×ÓµÄÖÊ×ÓÊýÖ®ºÍµÈÓÚCÔ­×ÓºËÄÚµÄÖÊ×ÓÊý£¬DÓëBÔ­×ÓºËÍâµç×ÓÊýÖ®ºÍΪCÔ­×Ӻ˵çºÉÊýµÄÁ½±¶£¬DÔ­×Ó×îÍâ²ãµç×ÓÊýÊÇÆäµç×Ó²ãÊýµÄ3±¶£¬AµÄµ¥ÖÊÊÇ×îÇáµÄÆøÌ壬EÊÇËùÔÚÖÜÆÚÔ­×Ӱ뾶×î´óµÄÔªËØ£®Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©EÔÚÖÜÆÚ±íÖеÄλÖÃΪ
µÚÈýÖÜÆÚµÚ¢ñA×å
µÚÈýÖÜÆÚµÚ¢ñA×å
£¬C¡¢D¡¢EËùÐγɵļòµ¥Àë×Ӱ뾶´óС˳ÐòΪ
r£¨N3-£©£¾r£¨O2- £©£¾r£¨Na+£©
r£¨N3-£©£¾r£¨O2- £©£¾r£¨Na+£©
 £¨ÓÃÀë×Ó·ûºÅ±íʾ£©£®
£¨2£©»¯ºÏÎïABCÊÇÒ»ÖÖ¼«ÈõµÄËᣬ·Ö×ÓÖк¬ÓÐ4¸ö¹²¼Û¼ü£¬Æäµç×ÓʽΪ
£»D¡¢EÐγɵÄÀë×Ó»¯ºÏÎïÖÐÒõÑôÀë×Ó¸öÊý±ÈΪ1£º2£¬¸Ã»¯ºÏÎïÖÐÊÇ·ñ´æÔÚ¹²¼Û¼ü£¿ÎªÊ²Ã´£¿
²»Ò»¶¨´æÔÚ¹²¼Û¼ü£¬ÈçΪNa2O2£¬O2-ÖдæÔÚ¹²¼Û¼ü£»ÈçΪNa2O£¬Ôò²»´æÔÚ¹²¼Û¼ü
²»Ò»¶¨´æÔÚ¹²¼Û¼ü£¬ÈçΪNa2O2£¬O2-ÖдæÔÚ¹²¼Û¼ü£»ÈçΪNa2O£¬Ôò²»´æÔÚ¹²¼Û¼ü

£¨3£©A¡¢B¡¢D¡¢E¿ÉÐγɶàÖÖ»¯ºÏÎÆäÖУ¬¼×¡¢ÒÒÁ½ÖÖ»¯ºÏÎïµÄÏà¶Ô·Ö×ÓÖÊÁ¿Ö®±ÈΪ42£º41£¬ÔòÏàͬÎïÖʵÄÁ¿Å¨¶ÈµÄ¼×¡¢ÒÒË®ÈÜÒº¼îÐÔÇ¿Èõ˳ÐòΪ£º¼×
£¾
£¾
ÒÒ£¨Ì¡¢£¼»ò=£©£¬ÒÒË®½â·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ
CH3COO-+H2OCH3COOH+OH-
CH3COO-+H2OCH3COOH+OH-
£®
£¨4£©250C¡¢1OlkPaÏ£¬BA4µÄȼÉÕÈÈΪa kJ/mol£¬9gҺ̬ˮ±äΪˮÕôÆøÎüÈÈb kJ£¬ÔòBA4ȼÉÕÉú³É¶þÑõ»¯Ì¼ºÍË®ÕôÆøµÄÈÈ»¯Ñ§·½³ÌʽΪ
CH 4£¨g£©+2O2£¨g£©¨TCO 2£¨g£©+2H2O£¨g£©£»¡÷H=-£¨a-4b£©kJ/mol
CH 4£¨g£©+2O2£¨g£©¨TCO 2£¨g£©+2H2O£¨g£©£»¡÷H=-£¨a-4b£©kJ/mol
£®
ÒÑÖªA¡¢B¡¢C¡¢D¡¢E¶¼ÊÇÔªËØÖÜÆÚ±íÖÐÇ°ËÄÖÜÆÚµÄÔªËØ£¬ËüÃǵĺ˵çºÉÊýA£¼B£¼C£¼D£¼E£®BÔ­×ÓµÄp¹ìµÀ°ë³äÂú£¬ÐγɵÄÇ⻯ÎïµÄ·ÐµãÊÇͬÖ÷×åÔªËصÄÇ⻯ÎïÖÐ×îµÍµÄ£®DÔ­×ӵõ½Ò»¸öµç×Óºó3p¹ìµÀÈ«³äÂú£®A+±ÈDÔ­×ÓÐγɵÄÀë×ÓÉÙÒ»¸öµç×Ӳ㣮CÓëAÐγÉA2CÐÍÀë×Ó»¯ºÏÎEµÄÔ­×ÓÐòÊýΪ26£¬EÔ­×Ó»òÀë×ÓÍâΧÓн϶àÄÜÁ¿Ïà½üµÄ¿Õ¹ìµÀ¶øÄÜÓëһЩ·Ö×Ó»òÀë×ÓÐγÉÅäºÏÎÇë¸ù¾ÝÒÔÉÏÇé¿ö£¬»Ø´ðÏÂÁÐÎÊÌ⣺£¨´ðÌâʱ£¬A¡¢B¡¢C¡¢D¡¢EÓÃËù¶ÔÓ¦µÄÔªËØ·ûºÅ±íʾ£©
£¨1£©A¡¢B¡¢C¡¢DµÄµÚÒ»µçÀëÄÜÓÉСµ½´óµÄ˳ÐòΪ
Na£¼S£¼P£¼Cl
Na£¼S£¼P£¼Cl
£®
£¨2£©CµÄÇ⻯Îï·Ö×ÓÊÇ
¼«ÐÔ
¼«ÐÔ
£¨Ìî¡°¼«ÐÔ¡±»ò¡°·Ç¼«ÐÔ¡±£©·Ö×Ó£®
£¨3£©»¯ºÏÎïBD3µÄ·Ö×ӿռ乹ÐÍÊÇ
Èý½Ç׶ÐÎ
Èý½Ç׶ÐÎ
£®
£¨4£©EµÄÒ»ÖÖ³£¼ûÅäºÏÎïE£¨CO£©5³£ÎÂϳÊҺ̬£¬ÈÛµãΪ-20.5¡æ£¬·ÐµãΪ103¡æ£¬Ò×ÈÜÓڷǼ«ÐÔÈܼÁ£®¾Ý´Ë¿ÉÅжÏE£¨CO£©5µÄ¾§ÌåÀàÐÍΪ
·Ö×Ó¾§Ìå
·Ö×Ó¾§Ìå
£»E£¨CO£©5ÔÚÒ»¶¨Ìõ¼þÏ·¢Éú·Ö½â·´Ó¦£ºE £¨CO£©5¨TE £¨s£©+5CO£¬·´Ó¦¹ý³ÌÖУ¬¶ÏÁѵĻ¯Ñ§¼üÖ»ÓÐÅäλ¼ü£¬ÐγɵĻ¯Ñ§¼üÊÇ
½ðÊô¼ü
½ðÊô¼ü
£®
£¨5£©½ðÊôEµ¥Öʵľ§ÌåÔÚ²»Í¬Î¶ÈÏÂÓÐÁ½Öֶѻý·½Ê½£¬¾§°ûÈçͼËùʾ£®ÌåÐÄÁ¢·½¾§°ûºÍÃæÐÄÁ¢·½¾§°ûÖÐʵ¼Êº¬ÓеÄEÔ­×Ó¸öÊýÖ®±ÈΪ
1£º2
1£º2
£®
£¨2011?Î÷°²Ä£Ä⣩[»¯Ñ§Ò»Ñ¡ÐÞÎïÖʽṹÓëÐÔÖÊ]
A¡¢B¡¢C¡¢D¡¢E¶¼ÊǶÌÖÜÆÚÖ÷×åÔªËØ£¬Ô­×ÓÐòÊýÒÀ´ÎÔö´ó£¬B¡¢CͬÖÜÆÚ£¬A¡¢DͬÖ÷×壬EµÄµ¥ÖʼȿÉÈÜÓÚÏ¡ÁòËáÓÖ¿ÉÈÜÓÚÇâÑõ»¯ÄÆÈÜÒº£®a¡¢bÄÜÐγÉÁ½ÖÖÔÚ³£ÎÂϳÊҺ̬µÄ»¯ºÏÎï¼×ºÍÒÒ£¬Ô­×Ó¸öÊý±È·Ö±ðΪ2£º1ºÍ1£º1£®¸ù¾ÝÒÔÉÏÐÅÏ¢»Ø´ðÏÂÁÐ1-3ÎÊ£º
£¨1£©CºÍDµÄÀë×ÓÖУ¬°ë¾¶½ÏСµÄÊÇ
Na+
Na+
 £¨ÌîÀë×Ó·ûºÅ£©£®
£¨2£©ÊµÑéÊÒÔڲⶨCµÄÆø̬Ç⻯ÎïµÄÏà¶Ô·Ö×ÓÖÊÁ¿Ê±£¬·¢ÏÖʵ¼Ê²â¶¨Öµ±ÈÀíÂÛÖµ´ó³öÐí¶à£¬ÆäÔ­ÒòÊÇ
ÓÉÓÚHFÖк¬ÓÐÇâ¼üÏà½áºÏµÄ¾ÛºÏ·ú»¯Çâ·Ö×Ó£¨HF£©n
ÓÉÓÚHFÖк¬ÓÐÇâ¼üÏà½áºÏµÄ¾ÛºÏ·ú»¯Çâ·Ö×Ó£¨HF£©n
£®
£¨3£©C¡¢D¡¢E¿É×é³ÉÀë×Ó»¯ºÏÎïDxE6Æ侧°û£¨¾§°ûÊÇÔÚ¾§ÌåÖоßÓдú±íÐÔµÄ×îСÖظ´µ¥Ôª£©½á¹¹ÈçͼËùʾ£¬ÑôÀë×ÓD+£¨ÓÃ0±íʾ£©Î»ÓÚÕý·½ÌåµÄÀâµÄÖеãºÍÕý·½ÌåÄÚ²¿£»ÒõÀë×ÓEC6x-£¨ÓÃʾ£©Î»ÓÚ¸ÃÕý·½ÌåµÄ¶¥µãºÍÃæÐÄ£¬¸Ã»¯ºÏÎïµÄ»¯Ñ§Ê½ÊÇ
Na3AlF6
Na3AlF6
£®

£¨4£©Mn¡¢Fe¾ùΪµÚËÄÖÜÆÚ¹ý¶ÉÔªËØ£¬Á½ÔªËصIJ¿·ÖµçÀëÄÜÊý¾ÝÁÐÓÚÏÂ±í£º
ÔªËØ Mn Fe
µçÀë
ÄÜ/kJ?mol-1
¢ñ1 717 759
¢ò2 1509 1561
¢ó3 3248 2957
»Ø´ðÏÂÁÐÎÊÌ⣺
MnÔªËؼ۵ç×Ó²ãµÄµç×ÓÅŲ¼Ê½Îª
3d54s2
3d54s2
£¬±È½ÏÁ½ÔªËصÄI2J3¿ÉÖª£¬Æø̬Mn2+ÔÙʧȥһ¸öµç×Ó±ÈÆø̬Fe2+ÔÙʧȥһ¸öµç×ÓÄÑ£®¶Ô´ËµÄ½âÊÍÊÇ
ÓÉMn2+ת»¯ÎªMn3+ʱ£¬3dÄܼ¶ÓɽÏÎȶ¨µÄ3d5°ë³äÂú״̬תΪ²»Îȶ¨µÄ3d4״̬ÐèÒªµÄÄÜÁ¿½Ï¶à£»¶øFe2+µ½Fe3+ʱ£¬3dÄܼ¶Óɲ»Îȶ¨µÄ3d6µ½Îȶ¨µÄ3d5°ë³äÂú״̬£¬ÐèÒªµÄÄÜÁ¿Ïà¶ÔÒªÉÙ
ÓÉMn2+ת»¯ÎªMn3+ʱ£¬3dÄܼ¶ÓɽÏÎȶ¨µÄ3d5°ë³äÂú״̬תΪ²»Îȶ¨µÄ3d4״̬ÐèÒªµÄÄÜÁ¿½Ï¶à£»¶øFe2+µ½Fe3+ʱ£¬3dÄܼ¶Óɲ»Îȶ¨µÄ3d6µ½Îȶ¨µÄ3d5°ë³äÂú״̬£¬ÐèÒªµÄÄÜÁ¿Ïà¶ÔÒªÉÙ
£»
£¨5£©FeÔ­×Ó»òÀë×ÓÍâΧÓн϶àÄÜÁ¿Ïà½üµÄ¿Õ¹ìµÀ¶øÄÜÓëһЩ·Ö×Ó»òÀë×ÓÐγÉÅäºÏÎ
¢ÙÓëFeÔ­×Ó»òÀë×ÓÐγÉÅäºÏÎïµÄ·Ö×Ó»òÀë×ÓÓ¦¾ß±¸µÄ½á¹¹ÌØÕ÷ÊÇ
¾ßÓл¡¶Ôµç×Ó
¾ßÓл¡¶Ôµç×Ó
£®
¢ÚÁùÇèºÏÑÇÌúÀë×Ó£¨Fe£¨CN£©64-£©ÖеÄÅäÌåCN-ÖÐcÔ­×ÓµÄÔÓ»¯¹ìDzÀàÐÍÊÇ
sp
sp
£»
д³öÒ»ÖÖÓëCN-»¥ÎªµÈµç×ÓÌåµÄµ¥ÖÊ·Ö×ӵķÒ×˹½á¹¹Ê½
N¡ÔN
N¡ÔN
£®
ÒÑÖªA¡¢B¡¢C¡¢D¡¢E¶¼ÊÇÖÜÆÚ±íÖÐÇ°ËÄÖÜÆÚµÄÔªËØ£¬ËüÃǵĺ˵çºÉÊýA£¼B£¼C£¼D£¼E£®BµÄ»ù̬ԭ×ÓÖеç×ÓÕ¼¾ÝÈýÖÖÄÜÁ¿²»Í¬µÄÔ­×Ó¹ìµÀ£¬ÇÒÿÖÖ¹ìµÀÖеĵç×Ó×ÜÊýÏàͬ£»DÔ­×ӵĺËÍâ³É¶Ôµç×ÓÊýÊÇδ³É¶Ôµç×ÓÊýµÄ3±¶£®A¡¢B¡¢DÈýÖÖÔªËØ×é³ÉµÄÒ»ÖÖ»¯ºÏÎïMÊÇÐÂ×°ÐÞ¾ÓÊÒÖг£º¬ÓеÄÒ»ÖÖÓк¦ÆøÌ壬A¡¢B¶þÖÖÔªËØ×é³ÉµÄÔ­×Ó¸öÊý±ÈΪ1£º1µÄ»¯ºÏÎïNÊdz£¼ûµÄÓлúÈܼÁ£®EµÄÔ­×ÓÐòÊýΪ26£®Çë¸ù¾ÝÒÔÉÏÇé¿ö£¬»Ø´ðÏÂÁÐÎÊÌ⣺£¨´ðÌâʱ£¬A¡¢B¡¢C¡¢D¡¢EÓÃËù¶ÔÓ¦µÄÔªËØ·ûºÅ±íʾ£©
£¨1£©ÏÂÁÐÐðÊöÕýÈ·µÄÊÇ
ad
ad
£®£¨Ìî×Öĸ£©
a£®M·Ö×ӿռ乹ÐÍΪƽÃæÈý½ÇÐΣ¬¶øBD2ΪֱÏßÐΣ¬BA4ΪÕýËÄÃæÌåÐÎ
b£®MºÍBD2·Ö×ÓÖеÄÖÐÐÄÔ­×Ó¾ù²ÉÈ¡sp2ÔÓ»¯£¬¶øCA3·Ö×ÓÖвÉÈ¡sp3ÔÓ»¯
c£®N ÊǷǼ«ÐÔ·Ö×Ó£¬ÇÒ·Ö×ÓÖЦҼü ºÍ¦Ð¼üµÄ¸öÊý±ÈΪ3£º1
d£®BD2¾§ÌåµÄÈ۵㡢·Ðµã¶¼±È¶þÑõ»¯¹è¾§ÌåµÄµÍ
£¨2£©B¡¢C¡¢DÈýÖÖÔªËصĵ縺ÐÔÓÉСµ½´óµÄ˳ÐòΪ
C£¼N£¼O
C£¼N£¼O
£»CµÄµÚÒ»µçÀëÄÜ´óÓÚDµÄµÚÒ»µçÀëÄÜÔ­ÒòÊÇ
NÔ­×Ó2p¹ìµÀ´¦ÓÚ°ë³äÂú״̬£¬ÄÜÁ¿µÍ
NÔ­×Ó2p¹ìµÀ´¦ÓÚ°ë³äÂú״̬£¬ÄÜÁ¿µÍ
£®
£¨3£©»¯ºÏÎïCA3µÄ·Ðµã±È»¯ºÏÎïBA4µÄ¸ß£¬ÆäÖ÷ÒªÔ­ÒòÊÇ
NH3·Ö×ÓÖ®¼ä´æÔÚÇâ¼ü
NH3·Ö×ÓÖ®¼ä´æÔÚÇâ¼ü
£®
£¨4£©B¡¢D¡¢EÈýÔªËØÄÜÐγɻ¯ºÏÎïE£¨BD£©5£¬³£ÎÂϳÊҺ̬£¬ÈÛµãΪ-20.5¡æ£¬·ÐµãΪ103¡æ£®¾Ý´Ë¿ÉÅжÏE£¨BD£©5¾§ÌåΪ
·Ö×Ó¾§Ìå
·Ö×Ó¾§Ìå
£®»ù̬E2+Àë×ӵĵç×ÓÅŲ¼Ê½Îª
1s22s22p63s23p63d6
1s22s22p63s23p63d6
£®
£¨5£©»¯ºÏÎïBDÓëÔªËØB¡¢CÐγɵÄÒõÀë×Ó»¥ÎªµÈµç×ÓÌ壬ÒõÀë×ӵĻ¯Ñ§Ê½ÊÇ
CN-
CN-
£®
¾«Ó¢¼Ò½ÌÍøÒÑÖªA¡¢B¡¢C¡¢D¡¢E¶¼ÊÇÔªËØÖÜÆÚ±íÖеÄÇ°ËÄÖÜÆÚÔªËØ£¬ËüÃÇÔ­×ÓÐòÊýµÄ´óС¹ØϵΪA£¼C£¼B£¼D£¼E£®ÓÖÖªAÔ­×ÓµÄp¹ìµÀΪ°ë³äÂú£¬ÆäÐγɵÄÇ⻯ÎïµÄ·ÐµãÊÇͬÖ÷×å·Ç½ðÊôÔªËصÄÇ⻯ÎïÖÐ×î¸ßµÄ£®DÔ­×ӵõ½Ò»¸öµç×ÓºóÆä3p¹ìµÀ½«È«³äÂú£®B+Àë×Ó±ÈDÔ­×ÓÐγɵÄÀë×ÓÉÙÒ»¸öµç×Ӳ㣮CÓëB¿ÉÐγÉBCÐ͵ÄÀë×Ó»¯ºÏÎEµÄÔ­×ÓÐòÊýΪ29£®
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©B¡¢C¡¢DµÄµç¸ºÐÔÓÉСµ½´óµÄ˳ÐòΪ
 
£¨ÓÃËù¶ÔÓ¦µÄÔªËØ·ûºÅ±íʾ£©£®B·Ö±ðC¡¢DÐγɵij£¼û»¯ºÏÎïÖУ¬ÈÛµã½Ï¸ßµÄÊÇ
 
£¨Ð´»¯Ñ§Ê½£©£ºCµÄÆø̬Ç⻯ÎïÒ×ÈÜÓÚË®µÄÔ­ÒòÊÇ
 
£®
£¨2£©AµÄ³£¼ûÆø̬Ç⻯ÎïºÍDµÄÆø̬Ç⻯ÎïÏàÓö»á¾çÁÒ·´Ó¦Éú³É»¯ºÏÎï¼×£¬Ôò¼×Öк¬ÓеĻ¯Ñ§¼üÓÐ
 
£®Ô­×ÓÐòÊý±ÈAÉÙlµÄÔªËØX¿ÉÓëÑõÔªËØÐγɻ¯ºÏÎïXO2£¬Ôò1mol¸Ã»¯ºÏÎïÖк¬ÓеĦҼüΪ
 
 mol£®
£¨3£©EÔ­×ӵĻù̬µç×ÓÅŲ¼Ê½Îª
 
£®ÔªËØEµÄµ¥Öʾ§ÌåÔÚ²»Í¬Î¶ÈÏ¿ÉÓÐÁ½Öֶѻý·½Ê½£¬¾§°û·Ö±ðÈçͼaºÍbËùʾ£¬ÔòÆäÃæÐÄÁ¢·½¶Ñ»ýµÄ¾§°ûÓëÌåÐÄÁ¢·½¶Ñ»ýµÄ¾§°ûÖÐʵ¼Êº¬ÓеÄEÔ­×ӵĸöÊýÖ®±ÈΪ
 
£®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø