ÌâÄ¿ÄÚÈÝ

ÏÖÓÐһƿŨ¶ÈΪ0.2 mol£¯LµÄijËáÈÜÒº£¬¿ÉÄÜΪ´×Ëá¡¢ÑÎËá»òÁòËáÖеÄÒ»ÖÖ¡£ÎªÁËÈ·¶¨¸ÃËáÈÜÒºµÄ×é³É½øÐÐʵÑé:È¡20.00 mL¸ÃËáÈÜÒº£¬ÖðµÎ¼ÓÈë0.2 mol£¯LµÄÇâÑõ»¯ÄÆÈÜÒº£¬Ç¡ºÃÍêÈ«·´Ó¦Ê±ËùÐè¼îÒºÌå»ýΪ20.00 mL¡£Çë»Ø´ðÏÂÁÐÎÊÌâ¡£

(1)¸ÃËá²»¿ÉÄÜÊÇ________________£»

(2)ÓÃpHÊÔÖ½²âµÃ·´Ó¦ºóËùµÃÈÜÒº³Ê¼îÐÔ£¬¸ù¾Ý´ËÏÖÏó˵Ã÷¸ÃËáÈÜҺΪ__________________£¬ÓÃÀë×Ó·½³Ìʽ˵Ã÷ÈÜÒº³Ê¼îÐÔµÄÔ­Òò_______________________________________________£»

(3)·´Ó¦ºóËùµÃÈÜÒºÖÐÀë×ÓŨ¶ÈÓÉ´óµ½Ð¡µÄ˳ÐòÊÇ____________________________________¡£

(1)ÁòËá»òH2SO4  

(2)´×Ëá»òCH3COOH    CH3COO-+H2OCH3COOH+OH-

(3)c(Na+)£¾c(CH3COO-)£¾c(OH-)£¾c(H+)


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø