ÌâÄ¿ÄÚÈÝ

ÏÂÁи÷×éÀë×ÓÔÚÖ¸¶¨ÈÜÒºÖÐÄÜ´óÁ¿¹²´æµÄÊÇ

  ¢ÙÎÞÉ«ÈÜÒºÖУºK+¡¢Na+¡¢MnO4-¡¢SO42£­ ¢ÚpH=11µÄÈÜÒºÖУºCO32£­¡¢Na+¡¢NO3£­¡¢AlO2-

¢Û¼ÓÈëAlÄܷųöH2µÄÈÜÒºÖУºCl£­¡¢SO42£­¡¢NO3£­¡¢Mg2+

¢ÜÔÚÓÉË®µçÀë³öµÄc(OH£­)=10£­13mol¡¤L£­1µÄÈÜÒºÖУºNa+¡¢Ba2+¡¢Cl£­¡¢I£­

¢ÝÔÚÈÜÒºÖÐÄÜ´óÁ¿¹²´æ£¬¼ÓÈëNaOHºó¼ÓÈȼÈÓÐÆøÌå·Å³öÓÖÓгÁµíÉú³ÉµÄÈÜÒº£º

Ca2+¡¢HCO3£­¡¢NH4+¡¢AlO2£­

¢ÞÄÜʹ·Ó̪±äºìÉ«µÄÈÜÒº£ºNa+¡¢C1£­¡¢S2£­¡¢SO32£­

A£®¢Ù¢Û¢Ý¡¡¡¡        B£®¢Ú¢Ü¢Ý      C£®¢Ú¢Ü¢Þ¡¡       D£®¢Ü¢Ý¢Þ

 

C

½âÎö:¢ÙÖÐMnO4-Ϊ×ϺìÉ«£¬²»ºÏÌâÒ⣬ÅųýA£»¢ÝÖÐNH4++OH-NH3¡ü+H2O,

HCO3£­+ OH-=CO32-  CO32-+Ca2+= CaCO3¡ý,·ûºÏÌâÒâ¡£ËùÒÔ¢Ù¢ÝÕýÈ·£¬Ñ¡ÔñA¡£

 

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø