ÌâÄ¿ÄÚÈÝ

¹¤ÒµÉÏÉú²úÁòËáʱ£¬ÀûÓô߻¯Ñõ»¯·´Ó¦½«SO2ת»¯ÎªSO3ÊÇÒ»¸ö¹Ø¼ü²½Ö衣ѹǿ¼°Î¶ȶÔSO2ת»¯ÂʵÄÓ°ÏìÈçϱí(Ô­ÁÏÆø¸÷³É·ÖµÄÌå»ý·ÖÊýΪ£ºSO2 7%£¬O2 11%£¬N2 82%)£º

     Ñ¹Ç¿/MPa
ת»¯ÂÊ/%
ζÈ/¡æ     
0.1
0.5
1
10
400
99.2
99.6
99.7
99.9
500
93.5
96.9
97.8
99.3
600
73.7
85.8
89.5
96.4
 
(1)ÒÑÖªSO2µÄÑõ»¯ÊÇ·ÅÈÈ·´Ó¦£¬ÈçºÎÀûÓñíÖÐÊý¾ÝÍƶϴ˽áÂÛ£¿________________________________________________________¡£
(2)ÔÚ400¡«500¡æʱ£¬SO2µÄ´ß»¯Ñõ»¯²ÉÓó£Ñ¹¶ø²»ÊǸßѹ£¬Ö÷ÒªÔ­ÒòÊÇ£º__________________________________________¡£
(3)Ñ¡ÔñÊÊÒ˵Ĵ߻¯¼Á£¬ÊÇ·ñ¿ÉÒÔÌá¸ßSO2µÄת»¯ÂÊ£¿________(Ìî¡°ÊÇ¡±»ò¡°·ñ¡±)£¬ÊÇ·ñ¿ÉÒÔÔö´ó¸Ã·´Ó¦·Å³öµÄÈÈÁ¿£¿________(Ìî¡°ÊÇ¡±»ò¡°·ñ¡±)¡£
(4)ΪÌá¸ßSO3ÎüÊÕÂÊ£¬Êµ¼ÊÉú²úÖÐÓÃ________ÎüÊÕSO2¡£
(5)ÒÑÖª£º2SO2(g)£«O2(g)=2SO3(g) ¦¤H£½£­196.9 kJ¡¤mol£­1£¬¼ÆËãÿÉú²ú1Íò¶Ö98%µÄÁòËáËùÐèÒªµÄSO3ÖÊÁ¿ºÍÓÉSO2Éú²úÕâЩSO3Ëù·Å³öµÄÈÈÁ¿¡£

(1)ѹǿһ¶¨Ê±£¬Î¶ÈÉý¸ßʱ£¬SO2ת»¯ÂÊϽµ£¬ËµÃ÷ÉýÎÂÓÐÀûÄæ·´Ó¦µÄ½øÐУ¬ËùÒÔÕý·´Ó¦Îª·ÅÈÈ·´Ó¦
(2)Ôö´óѹǿ¶ÔÌá¸ßSO2ת»¯ÂÊÎÞÏÔÖøÓ°Ï죬·´¶ø»áÔö¼Ó³É±¾
(3)·ñ     ·ñ
(4)ŨÁòËá
(5)8.0¡Á103 t 9.845¡Á109 kJ

½âÎö

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

(1)»ðɽÅç·¢Ëù²úÉúµÄÁò»Æ¿ÉÓÃÓÚÉú²úÖØÒªµÄ»¯¹¤Ô­ÁÏÁòËᡣijÆóÒµÓÃÏÂͼËùʾµÄ¹¤ÒÕÁ÷³ÌÉú²úÁòË᣺

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙΪ³ä·ÖÀûÓ÷´Ó¦·Å³öµÄÈÈÁ¿£¬½Ó´¥ÊÒÖÐÓ¦°²×°________(ÌîÉ豸Ãû³Æ)¡£ÎüÊÕËþÖÐÌî³äÓÐÐí¶à´É¹Ü£¬Æä×÷ÓÃÊÇ___________________________________¡£
¢ÚΪʹÁò»Æ³ä·ÖȼÉÕ£¬¾­Á÷Á¿¼Æ1ͨÈëȼÉÕÊÒµÄÑõÆø¹ýÁ¿50%£¬ÎªÌá¸ßSO2ת»¯ÂÊ£¬¾­Á÷Á¿¼Æ2µÄÑõÆøÁ¿Îª½Ó´¥ÊÒÖжþÑõ»¯ÁòÍêÈ«Ñõ»¯Ê±ÀíÂÛÐèÑõÁ¿µÄ2.5±¶£¬ÔòÉú²ú¹ý³ÌÖÐÁ÷¾­Á÷Á¿¼Æ1ºÍÁ÷Á¿¼Æ2µÄ¿ÕÆøÌå»ý±ÈӦΪ________¡£¼ÙÉè½Ó´¥ÊÒÖÐSO2µÄת»¯ÂÊΪ95%£¬b¹ÜÅųöµÄβÆøÖжþÑõ»¯ÁòµÄÌå»ý·ÖÊýΪ________(¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊý°´0.2¼Æ)£¬¸ÃβÆøµÄ´¦Àí·½·¨ÊÇ________¡£
¢ÛÓëÒÔÁòÌú¿óΪԭÁϵÄÉú²ú¹¤ÒÕÏà±È£¬¸Ã¹¤ÒÕµÄÌصãÊÇ________(¿É¶àÑ¡)¡£
A£®ºÄÑõÁ¿¼õÉÙ  B£®¶þÑõ»¯ÁòµÄת»¯ÂÊÌá¸ß
C£®²úÉúµÄ·ÏÔü¼õÉÙ  D£®²»ÐèҪʹÓô߻¯¼Á
(2)ÁòËáµÄÓÃ;·Ç³£¹ã·º£¬¿ÉÓ¦ÓÃÓÚÏÂÁÐÄÄЩ·½Ãæ________(¿É¶àÑ¡)¡£
A£®Ï𽺵ÄÁò»¯
B£®±íÃæ»îÐÔ¼Á¡°Íé»ù±½»ÇËáÄÆ¡±µÄºÏ³É
C£®Ç¦Ðîµç³ØµÄÉú²ú
D£®¹ýÁ×Ëá¸ÆµÄÖƱ¸
(3)¿óÎïȼÁϵÄȼÉÕÊDzúÉú´óÆøÖÐSO2µÄÖ÷ÒªÔ­ÒòÖ®Ò»¡£ÔÚȼúÖмÓÈëÊÊÁ¿µÄʯ»Òʯ£¬¿ÉÓÐЧ¼õÉÙúȼÉÕʱSO2µÄÅÅ·Å£¬Çëд³ö´ËÍÑÁò¹ý³ÌÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ________________________¡£

£¨1£©»ðɽÅç·¢Ëù²úÉúµÄÁò»Ç¿ÉÓÃÓÚÉú²úÖØÒªµÄ»¯¹¤Ô­ÁÏÁòËᡣijÆóÒµÓÃÏÂͼËùʾµÄ¹¤ÒÕÁ÷³ÌÉú²úÁòË᣺

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
¢ÙΪ³ä·ÖÀûÓ÷´Ó¦·Å³öµÄÈÈÁ¿£¬½Ó´¥ÊÒÖÐÓ¦°²×°________£¨ÌîÉ豸Ãû³Æ£©¡£ÎüÊÕËþÖÐÌî³äÓÐÐí¶à´É¹Ü£¬Æä×÷ÓÃÊÇ_______________________¡£
¢ÚΪʹÁò»Ç³ä·ÖȼÉÕ£¬¾­Á÷Á¿¼Æ1ͨÈëȼÉÕÊÒµÄÑõÆø¹ýÁ¿50%¡£ÎªÌá¸ßSO2ת»¯ÂÊ£¬¾­Á÷Á¿¼Æ2µÄÑõÆøÁ¿Îª½Ó´¥ÊÒÖжþÑõ»¯ÁòÍêÈ«Ñõ»¯Ê±ÀíÂÛÐèÑõÁ¿µÄ2.5±¶£¬ÔòÉú²ú¹ý³ÌÖÐÁ÷¾­Á÷Á¿¼Æ1ºÍÁ÷Á¿¼Æ2µÄ¿ÕÆøÌå»ý±ÈӦΪ________¡£¼ÙÉè½Ó´¥ÊÒÖÐSO2µÄת»¯ÂÊΪ95%£¬b¹ÜÅųöµÄβÆøÖжþÑõ»¯ÁòµÄÌå»ý·ÖÊýΪ________£¨¿ÕÆøÖÐÑõÆøµÄÌå»ý·ÖÊý°´0.2¼Æ£©£¬¸ÃβÆøµÄ´¦Àí·½·¨ÊÇ________¡£
¢ÛÓëÒÔ»ÆÌú¿óΪԭÁϵÄÉú²ú¹¤ÒÕÏà±È£¬¸Ã¹¤ÒÕµÄÌصãÊÇ________£¨¿É¶àÑ¡£©¡£
A£®ºÄÑõÁ¿¼õÉÙ
B£®¶þÑõ»¯ÁòµÄת»¯ÂÊÌá¸ß
C£®Éú²úµÄ·ÏÔü¼õÉÙ
D£®²»ÐèҪʹÓô߻¯¼Á
£¨2£©ÁòËáµÄÓÃ;·Ç³£¹ã·º£¬¿ÉÓ¦ÓÃÓÚÏÂÁÐÄÄЩ·½Ãæ________£¨¿É¶àÑ¡£©¡£
A£®Ï𽺵ÄÁò»¯
B£®±íÃæ»îÐÔ¼Á¡°Íé»ù±½»ÇËáÄÆ¡±µÄºÏ³É
C£®Ç¦Ðîµç³ØµÄÉú²ú
D£®¹ýÁ×Ëá¸ÆµÄÖƱ¸
£¨3£©¿óÎïȼÁϵÄȼÉÕÊDzúÉú´óÆøÖÐSO2µÄÖ÷ÒªÔ­ÒòÖ®Ò»¡£ÔÚȼúÖмÓÈëÊÊÁ¿µÄʯ»Òʯ£¬¿ÉÓÐЧ¼õÉÙúȼÉÕʱSO2µÄÅÅ·Å£¬Çëд³ö´ËÍÑÁò¹ý³ÌÖз´Ó¦µÄ»¯Ñ§·½³Ìʽ___________________________________________________________¡£

µç×Ó²úÆ·²úÉúµÄ´óÁ¿µç×ÓÀ¬»ø¶Ô»·¾³¹¹³ÉÁ˼«´óµÄÍþв¡£Ä³»¯Ñ§ÐËȤС×齫һÅú·ÏÆúµÄÏß·°å¼òµ¥´¦Àíºó£¬µÃµ½º¬Cu¡¢Al¡¢Fe¼°ÉÙÁ¿Au¡¢PtµÈ½ðÊôµÄ»ìºÏÎ²¢Éè¼Æ³öÈçÏÂÖƱ¸ÁòËáÍ­ºÍÁòËáÂÁ¾§ÌåµÄ·Ïߣº

°´ÒªÇó»Ø´ðÏÂÁÐÎÊÌ⣺
(1)ÂËÔü1ÖдæÔڵĽðÊôÓÐ_____________¡£
(2)ÒÑÖª³ÁµíÎïµÄpHÈçÏÂ±í£º

 
ÇâÑõ»¯Î↑ʼ³ÁµíʱµÄpH
ÇâÑõ»¯Îï³ÁµíÍêȫʱµÄpH
Fe2+
7.0
9.0
Fe3+
1.9
3.7
Cu2+
4.9
6.7
Al3+
3.0
4.4
 
¢ÙÔò²Ù×÷¢ÚÖÐXÎïÖÊ×îºÃÑ¡ÓõÄÊÇ___________(Ìî±àºÅ)
a£®ËáÐÔ¸ßÃÌËá¼ØÈÜÒº    b£®Æ¯°×·Û    c£®ÂÈÆø       d£®Ë«ÑõË®
¢ÚÀíÂÛÉÏÓ¦¿ØÖÆÈÜÒºpHµÄ·¶Î§ÊÇ________________________¡£
(3)¼ìÑéÂËÒº2ÖмȲ»´æÔÚFe2+ÓÖ²»´æÔÚFe3+µÄ²Ù×÷²½ÖèÊÇ____________________¡£
(4)ÓÃÒ»¸öÀë×Ó·½³Ìʽ±íʾÔÚËá½þÒºÖмÓÈëÊÊÁ¿ÂÁ·ÛµÄ·´Ó¦£º___________________¡£
(5)ÓÉCuSO4¡¤5H2OÖƱ¸CuSO4ʱ£¬Ó¦°ÑCuSO4¡¤5H2O·ÅÔÚ______(ÌîÒÇÆ÷Ãû³Æ)ÖмÓÈÈÍÑË®¡£
(6)ÏÖÔÚijЩµçÆ÷ÖÐʹÓõĸßÌúµç³ØÊÇÒ»ÖÖÐÂÐͿɳäµçµç³Ø£¬ÓëÆÕͨ¸ßÄܵç³ØÏà±È£¬¸Ãµç³ØÄܳ¤Ê±¼ä±£³ÖÎȶ¨µÄ·Åµçµçѹ¡£¸ßÌúµç³ØµÄ×Ü·´Ó¦Îª 3Zn + 2K2FeO4 + 8H2O3Zn(OH)2 + 2Fe(OH)3 + 4KOH£¬¸Ãµç³Ø·Åµçʱ¸º¼«·´Ó¦Ê½Îª_______£¬Ã¿ÓÐ1mol K2FeO4±»»¹Ô­£¬×ªÒƵç×ÓµÄÎïÖʵÄÁ¿Îª____£¬³äµçʱÑô¼«·´Ó¦Ê½Îª___________¡£

ÁòËáµÄ¹¤ÒµÖƱ¸ÊÇÒ»¸öÖØÒªµÄ»¯¹¤Éú²ú¹ý³Ì£¬µ«Í¬Ê±ÔÚÉú²ú¹ý³ÌÖлá²úÉú´óÁ¿SO2µÈÎÛȾÎï¡£
£¨1£©½«SO2ͨÈëFe(NO3)3ÈÜÒºÖУ¬ÈÜÒºÓÉ×Ø»ÆÉ«±äΪdzÂÌÉ«£¬µ«Á¢¼´ÓÖ±äΪ×Ø»ÆÉ«£¬´ËʱÈôµÎÈëBaCl2ÈÜÒº£¬Ôò»á²úÉú°×É«³Áµí¡£ÈÜÒºÓÉ×Ø»ÆÉ«±äΪdzÂÌÉ«ÓÃÀë×Ó·½³Ìʽ±íʾΪ_____£¬ºóÓÖÓÉdzÂÌÉ«±äΪ×Ø»ÆÉ«µÄÀë×Ó·½³ÌʽΪ_____¡£
£¨2£©ÒÔÁòËṤҵµÄβÆø¡¢°±Ë®¡¢Ê¯»Òʯ¡¢½¹Ì¿¼°Ì¼ËáÇâ狀ÍKCIΪԭÁÏ¿ÉÒԺϳÉÓÐÖØÒªÓÃ;µÄÁò»¯¸Æ¡¢ÁòËá¼Ø¡¢ÑÇÁòËáÇâ淋ÈÎïÖÊ¡£ºÏ³É·ÏßÈçÏ£º

д³ö·´Ó¦·´Ó¦¢ôµÄ»¯Ñ§·½³Ìʽ                    £»
·´Ó¦IIIÖÐÑõ»¯¼ÁÓ뻹ԭ¼ÁµÄÎïÖʵÄÁ¿Ö®±ÈΪ__         __£»
·´Ó¦VÔÚ25'C¡¢40%ÒÒ¶þ´¼ÈÜÒºÖнøÐУ¬¸Ã¸´·Ö½â·´Ó¦ÄÜ˳Àû½øÐеÄÔ­ÒòÊÇ         ¡£
£¨3£©ÐÂÐÍÄÉÃײÄÁÏÑõȱλÌúËáп£¨ZnFe2Ox£©£¬³£ÎÂÏÂÄÜʹSO2·Ö½â£¬¼õС¹¤Òµ·ÏÆø¶Ô»·¾³µÄÓ°Ï죬ËüÓÉÌúËáп£¨ZnFe2O4£©¾­¸ßλ¹Ô­ÖƵã¬×ª»¯Á÷³ÌÈçÏÂͼËùʾ£º

Èô2molZnFe2OxÓëSO2·´Ó¦¿ÉÉú³É 0.75molS£¬x£½      ,д³öÌúËáп¸ßÎÂϱ»»¹Ô­Éú³ÉÑõȱλÌúËáпµÄ»¯Ñ§·½³Ìʽ                   
£¨4£©Ê¯»Òʯ-ʯ¸àʪ·¨ÑÌÆøÍÑÁò¹¤ÒÕ¼¼ÊõµÄÔ­ÀíÊÇÑÌÆøÖеĶþÑõ»¯ÁòÓ뽬ҺÖеÄ̼Ëá¸ÆÒÔ¼°¿ÕÆø·´Ó¦Éú³Éʯ¸à£¨CaSO4.2H2O£©£¬Ð´³ö¸Ã·´Ó¦µÄ»¯Ñ§·½³Ìʽ         ¡£Ä³µç³§ÓÃú300t£¨ÃºÖк¬ÁòµÄÖÊÁ¿·ÖÊýΪ2.5%£©£¬ÈôȼÉÕʱúÖеÄÁòÈ«²¿×ª»¯Îª¶þÑõ»¯Áò£¬Óø÷½·¨ÍÑÁòʱÓÐ96%µÄÁòת»¯ÎªÊ¯¸à£¬Ôò¿ÉÉú²úʯ¸à         t¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø