ÌâÄ¿ÄÚÈÝ

£¨1£©ÏÖÓÐA¡¢B¡¢C¡¢D¡¢EÎåÖÖÔªËØ£¬AµÄÔ­×ÓºËÖÐûÓÐÖÐ×Ó£»B¡¢CÔªËØ´¦ÓÚͬһÖÜÆÚ£¬CµÄÔ­×Ó°ë¾¶½ÏС£¬B¡¢CµÄÖÊ×ÓÊýÖ®ºÍΪ27£¬ÖÊ×ÓÊýÖ®²îΪ5£»54 g DµÄµ¥Öʸú×ãÁ¿ÑÎËá·´Ó¦£¬Éú³ÉD3£«ºÍ67.2 L£¨±ê×¼×´¿ö£©ÇâÆø£»EºÍCÄÜÐγÉE2CÐÍÀë×Ó»¯ºÏÎÇÒE¡¢CÁ½ÔªËصļòµ¥Àë×Ó¾ßÓÐÏàͬµç×Ó²ã½á¹¹¡£

¢ÙB¡¢DµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïÏ໥·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º                                         ¡£

¢ÚÓõç×Óʽ±íʾCÓëEÐγÉE2CµÄ¹ý³Ì£º           ¡£

£¨2£©ÔªËØÔÚÖÜÆÚ±íÖеÄλÖ㬷´Ó³ÁËÔªËØµÄÔ­×ӽṹºÍÔªËØµÄÐÔÖÊ¡£ÓÒͼÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö¡£

¢ÙÒõÓ°²¿·ÖÔªËØNÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪ       ¡£

¢ÚÔÚÒ»¶¨Ìõ¼þÏ£¬SÓëH2·´Ó¦ÓÐÒ»¶¨ÏÞ¶È(¿ÉÀí½âΪ·´Ó¦½øÐеij̶È)£¬ÇëÅжϣºÔÚÏàͬÌõ¼þÏÂSeÓëH2·´Ó¦µÄÏ޶ȱÈSÓëH2·´Ó¦ÏÞ¶È   ¡¡¡¡¡¡ ¡£(Ñ¡Ìî¡°¸ü´ó¡±¡¢¡°¸üС¡±»ò¡°Ïàͬ¡±)

¢ÛBr2¾ßÓнÏÇ¿µÄÑõ»¯ÐÔ£¬SO2¾ßÓнÏÇ¿µÄ»¹Ô­ÐÔ£¬½«SO2ÆøÌåͨÈëäåË®ºó£¬·´Ó¦Àë×Ó·½³ÌʽÊÇ__________________________________________¡£

¢ÜÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ         

A£®C¡¢N¡¢O¡¢FµÄÔ­×Ó°ë¾¶Ëæ×ÅÔ­×ÓÐòÊýµÄÔö´ó¶ø¼õС

B£®Si¡¢P¡¢S¡¢ClÔªËØµÄ·Ç½ðÊôÐÔËæ×ź˵çºÉÊýµÄÔö¼Ó¶øÔöÇ¿

C£®¸É±ùÉý»ª¡¢ÒºÌ¬Ë®×ª±äÎªÆøÌ¬¶¼Òª¿Ë·þ·Ö×ÓÄڵĹ²¼Û¼ü

D£®HF¡¢HCl¡¢HBr¡¢HIµÄÈÈÎȶ¨ÐÔÒÀ´Î¼õÈõ

£¨1£©¢ÙAl(OH)3£«OH£­===AlO2£­£«2H2O

¢ÚK¡¤£«£«¡¤KK£« [¡¡ ]2£­ K£«£¨²»´ò¼ýÍ·£¬»ò2K¡¤Ò²¸ø·Ö£©

£¨2£©¢Ù ¶þ ¢õA¢Ú¸üС ¢Û Br2+SO2+H2O==4H++SO+2Br- ¢Ü A BD

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
Ìî¿Õ  £¨1£©ÏÖÓÐA¡¢B¡¢CÈýÖÖÌþ£¬ÆäÇò¹÷Ä£ÐÍÈçͼ£º
¢ÙµÈÖÊÁ¿µÄÒÔÉÏÎïÖÊÍêȫȼÉÕʱºÄÈ¥O2µÄÁ¿×î¶àµÄÊÇ
A
A
£¨Ìî¶ÔÓ¦×Öĸ£¬ÏÂͬ£©£»
¢Úͬ״¿ö¡¢Í¬Ìå»ýµÄÒÔÉÏÈýÖÖÎïÖÊÍêȫȼÉÕʱºÄÈ¥O2µÄÁ¿×î¶àµÄÊÇ
C
C
£»
¢ÛµÈÖÊÁ¿µÄÒÔÉÏÈýÖÖÎïÖÊȼÉÕʱ£¬Éú³É¶þÑõ»¯Ì¼×î¶àµÄÊÇ
B
B
£¬Éú³ÉË®×î¶àµÄÊÇ
A
A
£®
¢ÜÔÚ120¡æ¡¢1.01¡Á105 PaÏÂʱ£¬ÓÐÁ½ÖÖÆøÌ¬ÌþºÍ×ãÁ¿µÄÑõÆø»ìºÏµãȼ£¬ÏàͬÌõ¼þϲâµÃ·´Ó¦Ç°ºóÆøÌåÌå»ýûÓз¢Éú±ä»¯£¬ÕâÁ½ÖÖÆøÌåÊÇ
AB
AB
£®
£¨2£©£®¢ÙO2ºÍO3£» ¢Ú1H¡¢2H¡¢3H£» ¢ÛCH4ºÍC10H22£» ¢ÜÒÒÍéºÍ£¨CH3£©2CHCH2CH3£»
¢Ý£»¢Þ
¢ß
£¨1£©»¥ÎªÍ¬Î»ËصÄÊÇ
¢Ú
¢Ú
£»£¨2£©»¥ÎªÍ¬ËØÒìÐÎÌåµÄÊÇ
¢Ù
¢Ù
£»£¨3£©»¥ÎªÍ¬ÏµÎïµÄÊÇ
¢Û¢Ü
¢Û¢Ü
£»£¨4£©»¥ÎªÍ¬·ÖÒì¹¹ÌåµÄÊÇ
¢ß
¢ß
£»£¨5£©ÊôÓÚͬһÎïÖʵÄÊÇ
¢Ý¢Þ
¢Ý¢Þ
£®£¨ÒÔÉϾùÓÃÐòºÅÌî¿Õ£©
£¨3£©±½µ¹ÈëÊ¢ÓеâË®µÄÊÔ¹ÜÖÐÕñµ´¡¢¾²Ö㬷¢ÏÖ
ÈÜÒº·Ö²ã£¬ÉϲãÒºÌå³Ê×ÏÉ«
ÈÜÒº·Ö²ã£¬ÉϲãÒºÌå³Ê×ÏÉ«
£¬¼Ó¼¸µÎÖ²ÎïÓÍÓÚÊ¢±½µÄÊÔ¹ÜÖÐÕñµ´·¢ÏÖ
ÈÜÒº»ìÈÜ
ÈÜÒº»ìÈÜ
£¬½«Ê¢±½µÄÊÔ¹ÜÖÃÓÚ0¡æµÄ±ùË®Öз¢ÏÖ
³öÏÖ¾§Ìå
³öÏÖ¾§Ìå
£®
£¨1£©ÏÖÓÐA¡¢B¡¢C¡¢D¡¢EÎåÖÖÔªËØ£¬AµÄÔ­×ÓºËÖÐûÓÐÖÐ×Ó£»B¡¢CÔªËØ´¦ÓÚͬһÖÜÆÚ£¬CµÄÔ­×Ó°ë¾¶½ÏС£¬B¡¢CµÄÖÊ×ÓÊýÖ®ºÍΪ27£¬ÖÊ×ÓÊýÖ®²îΪ5£»0.96g DµÄµ¥Öʸú×ãÁ¿ÑÎËá·´Ó¦£¬Éú³ÉD3+ºÍ1.2L£¨±ê×¼×´¿ö£©ÇâÆø£»EºÍCÄÜÐγÉE2CÐÍÀë×Ó»¯ºÏÎÇÒE¡¢CÁ½ÔªËصļòµ¥Àë×Ó¾ßÓÐÏàͬµç×Ó²ã½á¹¹£®
¢Ùд³öÔªËØ·ûºÅ£ºA
H
H
£¬C
S
S
£¬E
K
K
£®
¢ÚB¡¢DµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïÏ໥·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º
Al£¨OH£©3+OH-=AlO2-+2H2O
Al£¨OH£©3+OH-=AlO2-+2H2O
£®
¢ÛÓõç×Óʽ±íʾCÓëEÐγÉE2CµÄ¹ý³Ì£º
£®
£¨2£©ÔªËØÔÚÖÜÆÚ±íÖеÄλÖ㬷´Ó³ÁËÔªËØµÄÔ­×ӽṹºÍÔªËØµÄÐÔÖÊ£®ÓÒͼÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö£®
¢ÙÒõÓ°²¿·ÖÔªËØNÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪµÚ
¶þ
¶þ
ÖÜÆÚµÚ
¢õA
¢õA
×壮
¸ù¾ÝÔªËØÖÜÆÚÂÉ£¬Ô¤²â£ºËáÐÔÇ¿Èõ H3AsO4
£¼
£¼
H3PO4£®£¨Óá°£¾¡±»ò¡°£¼¡±±íʾ£©
¢ÚÔªËØSµÄ×î¸ßÕý¼ÛºÍ×îµÍ¸º¼ÛµÄ´úÊýºÍΪ
+4
+4
£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬SÓëH2·´Ó¦ÓÐÒ»¶¨ÏÞ¶È£¨¿ÉÀí½âΪ·´Ó¦½øÐеij̶ȣ©£¬ÇëÅжϣºÔÚÏàͬÌõ¼þÏÂSeÓëH2·´Ó¦µÄÏ޶ȱÈSÓëH2·´Ó¦ÏÞ¶È
¸üС
¸üС
£®£¨Ñ¡Ìî¡°¸ü´ó¡±¡¢¡°¸üС¡±»ò¡°Ïàͬ¡±£©
¢ÛBr2¾ßÓнÏÇ¿µÄÑõ»¯ÐÔ£¬SO2¾ßÓнÏÇ¿µÄ»¹Ô­ÐÔ£¬½«SO2ÆøÌåͨÈëäåË®ºó£¬ÈÜÒºÖдæÔÚµÄÖ÷ÒªÀë×ÓÊÇ
Br-¡¢SO42-¡¢H+
Br-¡¢SO42-¡¢H+
£®
¢ÜÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
A¡¢B¡¢D
A¡¢B¡¢D

A£®C¡¢N¡¢O¡¢FµÄÔ­×Ó°ë¾¶Ëæ×ÅÔ­×ÓÐòÊýµÄÔö´ó¶ø¼õС
B£®Si¡¢P¡¢S¡¢ClÔªËØµÄ·Ç½ðÊôÐÔËæ×ź˵çºÉÊýµÄÔö¼Ó¶øÔöÇ¿
C£®¸É±ùÉý»ª¡¢ÒºÌ¬Ë®×ª±äÎªÆøÌ¬¶¼Òª¿Ë·þ·Ö×ÓÄڵĹ²¼Û¼ü
D£®HF¡¢HCl¡¢HBr¡¢HIµÄÈÈÎȶ¨ÐÔÒÀ´Î¼õÈõ£®

£¨12·Ö£©
£¨1£©ÏÖÓÐA¡¢B¡¢C¡¢D¡¢EÎåÖÖÔªËØ£¬AµÄÔ­×ÓºËÖÐûÓÐÖÐ×Ó£»B¡¢CÔªËØ´¦ÓÚͬһÖÜÆÚ£¬CµÄÔ­×Ó°ë¾¶½ÏС£¬B¡¢CµÄÖÊ×ÓÊýÖ®ºÍΪ27£¬ÖÊ×ÓÊýÖ®²îΪ5£» DµÄµ¥ÖʸúÑÎËá·´Ó¦£¬Éú³ÉD3£«ºÍÇâÆø£»EºÍCÄÜÐγÉE2CÐÍÀë×Ó»¯ºÏÎÇÒE¡¢CÁ½ÔªËصļòµ¥Àë×Ó¾ßÓÐÏàͬµç×Ó²ã½á¹¹¡£
¢Ùд³öÔªËØ·ûºÅ£º
A      £¬C       £¬E        ¡£
¢Ú B¡¢DµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïÏ໥·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º
                                                              ¡£
¢Ûд³öE2CµÄµç×Óʽ£º                                    ¡£
£¨2£©ÔªËØÔÚÖÜÆÚ±íÖеÄλÖ㬷´Ó³ÁËÔªËØµÄÔ­×ӽṹºÍÔªËØµÄÐÔÖÊ¡£ÏÂͼÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö¡£

¢ÙÒõÓ°²¿·ÖÔªËØNÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪµÚ      ÖÜÆÚµÚ     ×å¡£
¸ù¾ÝÔªËØÖÜÆÚÂÉ£¬Ô¤²â£ºËáÐÔÇ¿Èõ H3AsO4          H3PO4¡££¨Óá°>¡±»ò¡°£¼¡±±íʾ£©
¢ÚÔªËØSµÄ×î¸ßÕý¼ÛºÍ×îµÍ¸º¼ÛµÄ´úÊýºÍΪ____________£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬SÓëH2·´Ó¦ÓÐÒ»¶¨ÏÞ¶È(¿ÉÀí½âΪ·´Ó¦½øÐеij̶È)£¬ÇëÅжϣºÔÚÏàͬÌõ¼þÏÂSeÓëH2·´Ó¦µÄÏ޶ȱÈSÓëH2·´Ó¦ÏÞ¶È  ¡¡¡¡¡¡¡£(Ñ¡Ìî¡°¸ü´ó¡±¡¢¡°¸üС¡±»ò¡°Ïàͬ¡±)
¢Û Br2¾ßÓнÏÇ¿µÄÑõ»¯ÐÔ£¬SO2¾ßÓнÏÇ¿µÄ»¹Ô­ÐÔ£¬½«SO2ÆøÌåͨÈëäåË®ºó£¬ÈÜÒºÖдæÔÚµÄÖ÷ÒªÀë×ÓÊÇ________________________________________________¡£
¢ÜÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ         
A£®C¡¢N¡¢O¡¢FµÄÔ­×Ó°ë¾¶Ëæ×ÅÔ­×ÓÐòÊýµÄÔö´ó¶ø¼õС
B£®Si¡¢P¡¢S¡¢ClÔªËØµÄ·Ç½ðÊôÐÔËæ×ź˵çºÉÊýµÄÔö¼Ó¶øÔöÇ¿
C£®¸É±ùÉý»ª¡¢ÒºÌ¬Ë®×ª±äÎªÆøÌ¬¶¼Òª¿Ë·þ·Ö×ÓÄڵĹ²¼Û¼ü
D£®HF¡¢HCl¡¢HBr¡¢HIµÄÈÈÎȶ¨ÐÔÒÀ´Î¼õÈõ

£¨1£©ÏÖÓÐA¡¢B¡¢C¡¢D¡¢EÎåÖÖÔ­×ÓÐòÊýµÝÔöµÄÖ÷×åÔªËØ£¬AµÄÔ­×ÓºËÖÐûÓÐÖÐ×Ó£»B¡¢CÔªËØ´¦ÓÚͬһÖÜÆÚ£¬CµÄÔ­×Ó°ë¾¶½ÏС£¬B¡¢CµÄÖÊ×ÓÊýÖ®ºÍΪ27£¬ÖÊ×ÓÊýÖ®²îΪ5£»DµÄµ¥ÖʸúÑÎËá·´Ó¦£¬Éú³ÉD3£«ºÍÇâÆø£»EºÍCÄÜÐγÉE2CÐÍÀë×Ó»¯ºÏÎÇÒE¡¢CÁ½ÔªËصļòµ¥Àë×Ó¾ßÓÐÏàͬµç×Ó²ã½á¹¹¡£

¢Ù д³öÔªËØ·ûºÅ£ºA       £¬C        £¬E         ¡£

¢Ú B¡¢DµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïÏ໥·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º

                                                               ¡£

¢Û д³öE2CµÄµç×Óʽ£º                                     ¡£

£¨2£©ÔªËØÔÚÖÜÆÚ±íÖеÄλÖ㬷´Ó³ÁËÔªËØµÄÔ­×ӽṹºÍÔªËØµÄÐÔÖÊ¡£ÏÂͼÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö¡£

¢Ù ÒõÓ°²¿·ÖÔªËØNÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪµÚ       ÖÜÆÚµÚ      ×å¡£

¸ù¾ÝÔªËØÖÜÆÚÂÉ£¬Ô¤²â£ºËáÐÔÇ¿Èõ H3AsO4          H3PO4¡££¨Óá°>¡±»ò¡°£¼¡±±íʾ£©

¢Ú ÔªËØSµÄ×î¸ßÕý¼ÛºÍ×îµÍ¸º¼ÛµÄ´úÊýºÍΪ____________£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬SÓëH2·´Ó¦ÓÐÒ»¶¨ÏÞ¶È(¿ÉÀí½âΪ·´Ó¦½øÐеij̶È)£¬ÇëÅжϣºÔÚÏàͬÌõ¼þÏÂSeÓëH2·´Ó¦µÄÏ޶ȱÈSÓëH2·´Ó¦ÏÞ¶È   ¡¡¡¡¡¡ ¡£(Ñ¡Ìî¡°¸ü´ó¡±¡¢¡°¸üС¡±»ò¡°Ïàͬ¡±)

¢Û Br2¾ßÓнÏÇ¿µÄÑõ»¯ÐÔ£¬SO2¾ßÓнÏÇ¿µÄ»¹Ô­ÐÔ£¬½«SO2ÆøÌåͨÈëäåË®ºó£¬ÈÜÒºÖдæÔÚµÄÖ÷ÒªÀë×ÓÊÇ________________________________________________¡£

¢Ü ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ         

A£®C¡¢N¡¢O¡¢FµÄÔ­×Ó°ë¾¶Ëæ×ÅÔ­×ÓÐòÊýµÄÔö´ó¶ø¼õС

B£®Si¡¢P¡¢S¡¢ClÔªËØµÄ·Ç½ðÊôÐÔËæ×ź˵çºÉÊýµÄÔö¼Ó¶øÔöÇ¿

C£®¸É±ùÉý»ª¡¢ÒºÌ¬Ë®×ª±äÎªÆøÌ¬¶¼Òª¿Ë·þ·Ö×ÓÄڵĹ²¼Û¼ü

D£®HF¡¢HCl¡¢HBr¡¢HIµÄÈÈÎȶ¨ÐÔÒÀ´Î¼õÈõ

 

£¨12·Ö£©

£¨1£©ÏÖÓÐA¡¢B¡¢C¡¢D¡¢EÎåÖÖÔªËØ£¬AµÄÔ­×ÓºËÖÐûÓÐÖÐ×Ó£»B¡¢CÔªËØ´¦ÓÚͬһÖÜÆÚ£¬CµÄÔ­×Ó°ë¾¶½ÏС£¬B¡¢CµÄÖÊ×ÓÊýÖ®ºÍΪ27£¬ÖÊ×ÓÊýÖ®²îΪ5£» DµÄµ¥ÖʸúÑÎËá·´Ó¦£¬Éú³ÉD3£«ºÍÇâÆø£»EºÍCÄÜÐγÉE2CÐÍÀë×Ó»¯ºÏÎÇÒE¡¢CÁ½ÔªËصļòµ¥Àë×Ó¾ßÓÐÏàͬµç×Ó²ã½á¹¹¡£

¢Ù д³öÔªËØ·ûºÅ£º

A       £¬C        £¬E         ¡£

¢Ú B¡¢DµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔӦˮ»¯ÎïÏ໥·´Ó¦µÄÀë×Ó·½³ÌʽΪ£º

                                                               ¡£

¢Û д³öE2CµÄµç×Óʽ£º                                     ¡£

£¨2£©ÔªËØÔÚÖÜÆÚ±íÖеÄλÖ㬷´Ó³ÁËÔªËØµÄÔ­×ӽṹºÍÔªËØµÄÐÔÖÊ¡£ÏÂͼÊÇÔªËØÖÜÆÚ±íµÄÒ»²¿·Ö¡£

¢Ù ÒõÓ°²¿·ÖÔªËØNÔÚÔªËØÖÜÆÚ±íÖеÄλÖÃΪµÚ       ÖÜÆÚµÚ      ×å¡£

¸ù¾ÝÔªËØÖÜÆÚÂÉ£¬Ô¤²â£ºËáÐÔÇ¿Èõ H3AsO4          H3PO4¡££¨Óá°>¡±»ò¡°£¼¡±±íʾ£©

¢Ú ÔªËØSµÄ×î¸ßÕý¼ÛºÍ×îµÍ¸º¼ÛµÄ´úÊýºÍΪ____________£¬ÔÚÒ»¶¨Ìõ¼þÏ£¬SÓëH2·´Ó¦ÓÐÒ»¶¨ÏÞ¶È(¿ÉÀí½âΪ·´Ó¦½øÐеij̶È)£¬ÇëÅжϣºÔÚÏàͬÌõ¼þÏÂSeÓëH2·´Ó¦µÄÏ޶ȱÈSÓëH2·´Ó¦ÏÞ¶È   ¡¡¡¡¡¡ ¡£(Ñ¡Ìî¡°¸ü´ó¡±¡¢¡°¸üС¡±»ò¡°Ïàͬ¡±)

¢Û Br2¾ßÓнÏÇ¿µÄÑõ»¯ÐÔ£¬SO2¾ßÓнÏÇ¿µÄ»¹Ô­ÐÔ£¬½«SO2ÆøÌåͨÈëäåË®ºó£¬ÈÜÒºÖдæÔÚµÄÖ÷ÒªÀë×ÓÊÇ________________________________________________¡£

¢Ü ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ         

A£®C¡¢N¡¢O¡¢FµÄÔ­×Ó°ë¾¶Ëæ×ÅÔ­×ÓÐòÊýµÄÔö´ó¶ø¼õС

B£®Si¡¢P¡¢S¡¢ClÔªËØµÄ·Ç½ðÊôÐÔËæ×ź˵çºÉÊýµÄÔö¼Ó¶øÔöÇ¿

C£®¸É±ùÉý»ª¡¢ÒºÌ¬Ë®×ª±äÎªÆøÌ¬¶¼Òª¿Ë·þ·Ö×ÓÄڵĹ²¼Û¼ü

D£®HF¡¢HCl¡¢HBr¡¢HIµÄÈÈÎȶ¨ÐÔÒÀ´Î¼õÈõ

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø