ÌâÄ¿ÄÚÈÝ

£¨12·Ö£©ÒÑÖªÒ»¸ö̼ԭ×ÓÉÏͬʱÁ¬ÓÐÁ½¸öôÇ»ùʱ£¬Ò×·¢ÉúÈçÏÂת»¯:

Çë¸ù¾Ýͼʾ»Ø´ð£º

£¨1£©EÖк¬ÓйÙÄÜÍŵÄÃû³ÆÊÇ_________£¬¢ÛµÄ·´Ó¦ÀàÐÍÊÇ______________£¬C¸úÐÂÖƵÄÇâÑõ»¯Í­Ðü×ÇÒº·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                              ¡£
£¨2£©ÒÑÖªBµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª162£¬ÆäÍêȫȼÉյIJúÎïÖÐn(CO2)£ºn(H2O) =" 2" £º1¡£FÊǵçÄÔоƬÖи߷Ö×Ó¹â×è¼ÁµÄÖ÷ÒªÔ­ÁÏ£¬F¾ßÓÐÒÔÏÂÌص㣺¢ÙÄܸúFeCl3ÈÜÒº·¢ÉúÏÔÉ«·´Ó¦£»¢ÚÄÜ·¢Éú¼Ó¾Û·´Ó¦£»¢Û±½»·ÉϵÄÒ»ÂÈ´úÎïÖ»ÓÐÁ½ÖÖ¡£ÔòFÔÚÒ»¶¨Ìõ¼þÏ·¢Éú¼Ó¾Û·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ__           _______________________________________________         _¡£
£¨3£©»¯ºÏÎïGÊÇFµÄͬ·ÖÒì¹¹Ì壬ËüÊôÓÚ·¼Ïã×廯ºÏÎÄÜ·¢ÉúÒø¾µ·´Ó¦¡£G¿ÉÄÜÓР    Öֽṹ£¬Ð´³öÆäÖÐÒ»ÖÖͬ·ÖÒì¹¹ÌåµÄ½á¹¹¼òʽ                   ______________       ¡£

£¨1£©ôÇ»ù£»Ñõ»¯»¹Ô­·´Ó¦£»CH3CHO+2Cu(OH)2CH3COOH+Cu2O+2H2O£»
£¨2£©
£¨3£©4£»¡¢¡¢¡¢£¨ÆäÖÐÒ»ÖÖ£©£»

½âÎöÊÔÌâ·ÖÎö£ºAºÍÇâÑõ»¯ÄƵÄË®ÈÜÒº·¢ÉúÈ¡´ú·´Ó¦Éú³ÉCºÍD£¬CÄܺÍÐÂÖÆÇâÑõ»¯Í­·¢ÉúÑõ»¯»¹Ô­·´Ó¦£¬ÔòCµÄ½á¹¹¼òʽΪCH3CHO£¬DΪôÈËᣬ½á¹¹¼òʽΪCH3COONa£¬D±»ËữÉú³ÉE£¬EµÄ½á¹¹¼òʽΪCH3COOH£¬BµÄÏà¶Ô·Ö×ÓÖÊÁ¿Îª162£¬ÆäÍêȫȼÉյIJúÎïÖÐn£¨CO2£©£ºn £¨H2O£©=2£º1£¬ÔòBÖÐ̼ÇâÔ­×Ó¸öÊýÖ®±ÈΪ1£º1£¬ËùÒÔa=b£¬½áºÏÆäÏà¶Ô·Ö×ÓÖÊÁ¿Öª£¬a= 162?32/13=10£¬ËùÒÔBµÄ·Ö×ÓʽΪC10H10O2£¬BË®½âÉú³ÉÒÒËáºÍF£¬F¾ßÓÐÈçÏÂÌص㣺¢ÙÄܸúFeCl3ÈÜÒº·¢ÉúÏÔÉ«·´Ó¦£»¢ÚÄÜ·¢Éú¼Ó¾Û·´Ó¦£»¢Û±½»·ÉϵÄÒ»ÂÈ´úÎïÖ»ÓÐÁ½ÖÖ£¬ÔòFµÄ½á¹¹¼òʽΪ£º £®
£¨1£©EµÄ½á¹¹¼òʽΪCH3COOH£¬EÖйÙÄÜÍÅÃû³ÆÊÇôÈ»ù£¬¹Ê´ð°¸Îª£ºôÈ»ù£»CÄܺÍÐÂÖÆÇâÑõ»¯Í­·¢ÉúÑõ»¯»¹Ô­·´Ó¦£¬ÔòCµÄ½á¹¹¼òʽΪCH3CHO£¬EµÄ½á¹¹¼òʽΪCH3COOH£¬CºÍÐÂÖÆÇâÑõ»¯Í­Ðü×ÇÒº·¢ÉúÑõ»¯»¹Ô­·´Ó¦Éú³ÉE£¬¸Ã·´Ó¦·½³ÌʽΪCH3CHO+2Cu(OH)2CH3COOH+Cu2O+2H2O£»
£¨2£©F¾ßÓÐÈçÏÂÌص㣺¢ÙÄܸúFeCl3ÈÜÒº·¢ÉúÏÔÉ«·´Ó¦£¬ËµÃ÷º¬ÓзÓôÇ»ù£»¢ÚÄÜ·¢Éú¼Ó¾Û·´Ó¦£¬ËµÃ÷º¬ÓÐC=C£¬£»¢Û±½»·ÉϵÄÒ»ÂÈ´úÎïÖ»ÓÐÁ½ÖÖ£¬Ôò±½»·ÉÏÓÐÁ½¸öÈ¡´ú»ù£¬Î»ÓÚ¶ÔλλÖã¬Ó¦Îª£¬¿É·¢Éú¼Ó¾Û·´Ó¦£¬·½³ÌʽΪ£»
£¨3£©»¯ºÏÎïGÊÇFµÄͬ·ÖÒì¹¹Ì壬ÊôÓÚ·¼Ïã×廯ºÏÎÄÜ·¢ÉúÒø¾µ·´Ó¦£¬GÖк¬ÓÐÈ©»ù£¬¿ÉÄܵÄͬ·ÖÒì¹¹ÌåÓС¢¡¢¡¢µÈ4ÖÖ¡£
¿¼µã£ºÓлúÎïµÄÍƶÏ

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

¢ñ.ÏÂͼÖÐA¡¢B¡¢C·Ö±ðÊÇÈýÖÖÓлúÎïµÄ½á¹¹Ä£ÐÍ£º

Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©A¼°ÆäͬϵÎïµÄ·Ö×ÓʽÖеÄ̼ԭ×ÓÊýÓÃn±íʾ¡£µ±n£½_______ʱ£¬ÍéÌþ¿ªÊ¼³öÏÖͬ·ÖÒì¹¹Ìå¡£BÄ£ÐÍÊÇÓлúÎïµÄ________Ä£ÐÍ¡£
£¨2£©½á¹¹¼òʽΪµÄÓлúÎïÖУ¬·Ö×ÓÖÐ×î¶àÓР   ¸öÔ­×Ó¹²Ãæ¡£
£¨3£©µÈÖÊÁ¿µÄA¡¢B¡¢CÈýÖÖÓлúÎïÍêȫȼÉÕÉú³ÉH2OºÍCO2£¬ÏûºÄÑõÆøµÄÌå»ý£¨Ïàͬ״¿öÏ£©×î´óµÄÊÇ________£¨Ìî·Ö×Óʽ£©¡£
¢ò.ÔÚÓлúÎï·Ö×ÓÖУ¬²»Í¬ÇâÔ­×ӵĺ˴Ź²ÕñÇâÆ×Öиø³öµÄ·åÖµ£¨Ðźţ©Ò²²»Í¬£¬¸ù¾Ý·åÖµ£¨Ðźţ©¿ÉÒÔÈ·¶¨ÓлúÎï·Ö×ÓÖÐÇâÔ­×ÓµÄÖÖÀàºÍÊýÄ¿¡£
£¨1£©ÏÂÁÐÎïÖÊÖУ¬ÆäºË´Å¹²ÕñÇâÆ×Öиø³öµÄ·åÖµ£¨Ðźţ©Ö»ÓÐÒ»¸öµÄÊÇ________¡£
A£®CH3COOH        B£®C£¨CH3£©4           C£®CH3COOCH3      D£®CH3OH
£¨2£©»¯ºÏÎïAºÍBµÄ·Ö×Óʽ¶¼ÊÇC2H4Br2£¬AµÄºË´Å¹²ÕñÇâÆ×ͼÈçÏÂͼËùʾ£¬ÔòAµÄ½á¹¹¼òʽΪ________¡£

£¨3£©Óú˴Ź²ÕñÇâÆ׵ķ½·¨À´Ñо¿C2H6OµÄ½á¹¹£¬¼òҪ˵Ã÷¸ù¾ÝºË´Å¹²ÕñÇâÆ׵Ľá¹ûÀ´È·¶¨C2H6O·Ö×ӽṹµÄ·½·¨ÊÇ_______________________           _ ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø