ÌâÄ¿ÄÚÈÝ

£¨1£©Ä³Í¬Ñ§ÓÃÍÐÅÌÌìƽ³ÆÁ¿ÉÕ±­µÄÖÊÁ¿£¬ÌìƽƽºâºóµÄ״̬Èçͼ£®ÓÉͼÖпÉÒÔ¿´³ö£¬¸ÃͬѧÔÚ²Ù×÷ʱµÄÒ»¸ö´íÎóÊÇ
íÀÂëÓëÉÕ±­·Å·´ÁËλÖÃ
íÀÂëÓëÉÕ±­·Å·´ÁËλÖÃ
£¬ÉÕ±­µÄʵ¼ÊÖÊÁ¿Îª
27.4
27.4
g£®
£¨2£©Ö¸³öÏÂÃæʵÑéÖдæÔڵĶþ¸ö´íÎó£ºÐèÅäÖÆ250mL 0.2mol?L-1NaClÈÜÒº£¬ÓÒͼÊǸÃͬѧתÒÆÈÜÒºµÄʾÒâͼ
£®
ûÓÐÓò£Á§°ôÒýÁ÷
ûÓÐÓò£Á§°ôÒýÁ÷
£¬
ÈÝÁ¿Æ¿µÄ¹æ¸ñӦΪ250ml
ÈÝÁ¿Æ¿µÄ¹æ¸ñӦΪ250ml
£®
£¨3£©²£Á§°ôÊÇ»¯Ñ§ÊµÑéÖг£ÓõÄÒÇÆ÷£¬½Ì¿ÆÊéÖÐÏÂÁÐÓйØʵÑé¹ý³ÌÖУ¬²»ÐèҪʹÓò£Á§°ô½øÐвÙ×÷µÄÊÇ£¨Ìî×Öĸ´úºÅ£©
CD
CD
£®
A£®ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄÈÜÒº B£®Å¨ÁòËáµÄÏ¡ÊÍ
C£®ÓóäÂú°±ÆøµÄÉÕÆ¿×öÅçȪʵÑé D£®ÇâÑõ»¯Ìú½ºÌåµÄÖƱ¸£®
·ÖÎö£º£¨1£©Ììƽ³ÆÁ¿ÎïÌåʱ×ñÑ­×óÎïÓÒÂëµÄÔ­Ôò£¬ÌìƽƽºâÔ­Àí£º×óÅÌÎïÌåÖÊÁ¿=ÓÒÅÌíÀÂëÖÊÁ¿+ÓÎÂëÖÊÁ¿£»
£¨2£©ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄÈÜҺʵÑ飬ÔÚÒÆҺʱ£¬ÒªÓò£Á§°ôÒýÁ÷£¬ÅäÖƶà´óÌå»ýµÄÈÜÒºÒª²ÉÓöà´óÌå»ýµÄÈÝÁ¿Æ¿£»
£¨3£©×ö»¯Ñ§ÊµÑéʱ¾­³£ÒªÓõ½²£Á§°ô£¬²£Á§°ôÔÚʵÑéÖÐÓкܶàÖØÒªµÄ×÷Óã¬Èç½Á°è¡¢ÒýÁ÷¡¢¹ýÂË¡¢×ªÒƹÌÌåµÈµÈ¶¼ÒªÓõ½²£Á§°ô£®
½â´ð£º½â£º£¨1£©Ììƽ³ÆÁ¿ÎïÌåʱ×ñÑ­×óÎïÓÒÂëµÄÔ­Ôò£¬ÔÚ¸ÃʵÑéͼÖпÉÒÔ¿´³ö£¬¸ÃͬѧÔÚ²Ù×÷ʱµÄÒ»¸ö´íÎóÊÇíÀÂëÓëÉÕ±­·Å·´ÁËλÖ㬸ù¾ÝÌìƽƽºâÔ­Àí£º×óÅÌÎïÌåÖÊÁ¿=ÓÒÅÌíÀÂëÖÊÁ¿+ÓÎÂëÖÊÁ¿£¬Èô¹û·Å·´ÁË£¬Ôò×óÅÌíÀÂëÖÊÁ¿=ÓÒÅÌÎïÌåÖÊÁ¿+ÓÎÂëÖÊÁ¿£¬ËùÒÔÓÒÅÌÎïÌåÖÊÁ¿=×óÅÌíÀÂëÖÊÁ¿-ÓÎÂëÖÊÁ¿=30-2.6=27.4£¬¹Ê´ð°¸Îª£ºíÀÂëÓëÉÕ±­·Å·´ÁËλÖã»27.4£»
£¨2£©ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄÈÜҺʵÑ飬ÔÚÒÆҺʱ£¬ÒªÓò£Á§°ôÒýÁ÷£¬ÓÒͼ¸ÃͬѧÔÚתÒÆÈÜҺʱûÓÐÓò£Á§°ôÒýÁ÷£¬ÅäÖÆ250mLµÄÈÜÒºÒª²ÉÓÃ250mLµÄÈÝÁ¿Æ¿£¬¹Ê´ð°¸Îª£ºÃ»ÓÐÓò£Á§°ôÒýÁ÷£»ÈÝÁ¿Æ¿µÄ¹æ¸ñӦΪ250ml£»
£¨3£©A¡¢ÅäÖÆÒ»¶¨ÎïÖʵÄÁ¿Å¨¶ÈµÄÈÜҺʵÑ飬ÔÚÒÆҺʱ£¬ÒªÓò£Á§°ôÒýÁ÷£¬¹ÊA´íÎó£»
B¡¢Å¨ÁòËáµÄÏ¡ÊÍÒªÓò£Á§°ô½Á°è£¬¹ÊB´íÎó£»
C¡¢ÓóäÂú°±ÆøµÄÉÕÆ¿×öÅçȪʵÑé²»ÐèҪʹÓò£Á§°ô£¬¹ÊCÕýÈ·£»
D¡¢ÇâÑõ»¯Ìú½ºÌåµÄÖƱ¸¹ý³ÌÖÐÓò£Á§°ô½Á°è»áʹ½ºÌå¾Û³Á£¬²»ÐèҪʹÓò£Á§°ô£¬¹ÊDÕýÈ·£®
¹ÊÑ¡CD£®
µãÆÀ£º±¾ÌâÒªÇóѧÉú¾ß±¸»ù±¾µÄ»¯Ñ§ÊµÑé¼¼ÄÜ£¬ÕâÊÇѧϰ»¯Ñ§ºÍ½øÐл¯Ñ§Ì½¾¿»î¶¯µÄ»ù´¡ºÍ±£Ö¤£¬Ö»ÓÐÕÆÎÕ»¯Ñ§ÊµÑéµÄ»ù±¾¼¼ÄÜ£¬²ÅÄÜ°²È«¡¢×¼È·µØ½øÐл¯Ñ§ÊµÑ飮
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ʵÑéÊÒÖÐÓÐһƿÂÈ»¯¼ØºÍÂÈ»¯¸ÆµÄ¹ÌÌå»ìºÍÎͨ¹ýÏÂÃæµÄʵÑé³ýÈ¥ÂÈ»¯¼ØÖÐÂÈ»¯¸Æ£¬²¢ÀûÓô¿¾»µÄÂÈ»¯¼ØÅäÖÆÒ»¶¨Å¨¶ÈµÄÂÈ»¯¼ØÈÜÒº£®¸ù¾ÝʵÑé²½ÖèÌîдÏÂÁпհף®

»Ø´ðÏÂÁÐÎÊÌâ

(1)¼ÓÈëµÄAÊÇ________£®(Ìî·Ö×Óʽ£¬ÏÂͬ)

(2)²Ù×÷¢ÚµÄÃû³ÆÊÇ________£®²Ù×÷¢Ù¡¢¢Ú¾ùÒªÓõ½µÄ²£Á§ÒÇÆ÷ÓÐ________£®

(3)BÎïÖÊÊÇ________£¬¼ÓÈë¹ýÁ¿µÄB·´Ó¦µÄÀë×Ó·½³ÌʽΪ________£®

(4)³ÆÈ¡Ò»¶¨Á¿´¿¾»µÄKCl£¬ÅäÖÆÒ»¶¨Å¨¶ÈµÄÂÈ»¯¼ØÈÜÒº£®

(¢¡)ijͬѧÓÃÍÐÅÌÌìÀ´³ÆÈ¡Ò»¶¨ÖÊÁ¿µÄKCl£¬³Æ·¨ÈçÏÂͼËùʾ£¬ÌìƽµÄÖ¸ÕëÔÚ±ê³ßÖм䣮´Ë²Ù×÷ÊÇ·ñÕýÈ·________(ÌîÕýÈ·»ò²»ÕýÈ·)£»Èô°´´Ë²Ù×÷³ÆÁ¿£¬Ëù³ÆKClµÄʵ¼ÊÖÊÁ¿Îª________g (ÒÑÖªÉÕ±­µÄÖÊÁ¿Îª12.9¿Ë)£®

(¢¢)ijѧÉú½«×¼È·³ÆÁ¿µÄKCl¹ÌÌå·ÅÈëÉÕ±­ÖУ¬¼ÓÈëÔ¼30ºÁÉýÕôÁóË®£¬Óò£Á§°ô½Á°èʹÆäÈܽ⣮½«ÈÜÒºÓÉÉÕ±­µ¹Èë100ºÁÉýÈÝÁ¿Æ¿ÖУ¬È»ºóÍùÈÝÁ¿Æ¿ÖÐСÐĵؼÓÕôÁóË®£¬Ö±µ½ÒºÃæ½Ó½ü¿Ì¶È1£­2ÀåÃ×´¦£¬¸ÄÓýºÍ·µÎ¹Ü¼ÓÕôÁóË®£¬Ê¹ÈÜÒº°¼Ãæ×îµÍµãÇ¡ºÃÓë¿Ì¶ÈÏàÇУ¬°ÑÈÝÁ¿Æ¿¸Ç½ô£¬ÔÙÕñµ´Ò¡ÔÈ£®¸ÃÉú²Ù×÷ÖеĴíÎóÊÇ________ºÍ________£®

£¨¹²13·Ö£©¡²Ò»¡³ÊµÑéÊÒÓÃÇâÑõ»¯ÄÆÅäÖÆ1.00mol/LµÄÇâÑõ»¯ÄÆÈÜÒº0.2L£¬»Ø´ðÏÂÁÐÎÊÌâ

£¨1£©ÏÂÁÐÓйØʹÓÃÍÐÅÌÌìƽµÄÐðÊö£¬ÕýÈ·µÄÊÇ                ¡£

A£®³ÆÁ¿Ç°Ïȵ÷½ÚÌìƽµÄÁãµã¡£

B£®³ÆÁ¿Ê±×óÅ̷ű»³ÆÁ¿ÎÓÒÅÌ·ÅíÀÂë¡£

C£®ÇâÑõ»¯ÄƱØÐë·ÅÔÚ²£Á§Æ÷ÃóÀï³ÆÁ¿¡£ 

D£®³ÆÁ¿Ê±£¬Ó¦ÏȼÓÖÊÁ¿Ð¡ºó¼ÓÖÊÁ¿´óµÄíÀÂëÖÁÌìƽƽºâ¡£

E£®³ÆÁ¿Íê±Ï£¬Ó¦°ÑÌìƽ·Å»ØíÀÂëºÐÖС£                    

£¨2£©Ä³Í¬Ñ§ÓÃÍÐÅÌÌìƽ³ÆȡһʢÓÐÇâÑõ»¯ÄÆÒ©Æ·µÄÉÕ±­£¬Èô×óÅÌÉÏ·ÅÓÐ30gíÀÂ룬ÓÎÂëλÖÃÈçÏÂͼËùʾ£¬ÌìƽµÄÖ¸ÕëÖ¸ÔÚ±ê³ßµÄÖм䡣ÔòÉÕ±­ºÍ·Û¼ÁµÄ×ÜÖÊÁ¿Îª_________¿Ë¡£

 
 

 


¡²¶þ¡³ÓÃ98%µÄŨH2SO4£¨¦Ñ=1.84g/cm3£©ÅäÖƳÉ0.5mol/LµÄÏ¡H2SO4 500mlµÄ²Ù×÷²½ÖèÈçÏ£º¢Ù¼ÆËãËùÓÃŨÁòËáµÄÌå»ý ¢ÚÁ¿È¡Ò»¶¨Ìå»ýµÄŨÁòËá ¢ÛÈܽ⠢ÜתÒÆ¡¢Ï´µÓ ¢Ý¶¨ÈÝ¡¢Ò¡ÔÈ £¬Çë°´ÒªÇóÌî¿Õ£º

£¨1£©Èç¹ûʵÑéÊÒÓÐ15mL¡¢20mL¡¢50mLÁ¿Í²£¬Ó¦Ñ¡Óà      mLÁ¿Í²×îºÃ¡£

£¨2£©µÚ¢Ý²½ÊµÑéµÄ²Ù×÷ÊÇ£¨ÎÄ×ÖÐðÊö£©_______________________________________________

£¨3£©Ä³Ñ§ÉúµÄÏÂÁвÙ×÷ÖÐʹŨ¶ÈÆ«µÍµÄÔ­ÒòÊÇ£º                ¡£

¢Ù ÓÃÁ¿Í²Á¿È¡Å¨ÁòËáʱ£¬¸©ÊÓ¶ÁÊý¡£

¢Ú Á¿Í²ÖÐŨÁòËáÈ«²¿×ªÈëÉÕ±­ÖÐÏ¡Êͺó£¬ÔÙתÒƵ½100mlÈÝÁ¿Æ¿ÖУ¬ÉÕ±­Î´Ï´µÓ¡£

¢Û Óò£Á§°ôÒýÁ÷£¬½«ÈÜҺתÒƵ½ÈÝÁ¿Æ¿ÖÐÓÐÈÜÒºÁ÷µ½ÁËÈÝÁ¿Æ¿ÍâÃæ¡£

¢Ü ŨÁòËáÔÚСÉÕ±­ÖÐÏ¡Êͺó£¬Ã»ÓÐÀäÈ´¾ÍÂíÉÏתÒÆÈëÈÝÁ¿Æ¿¡£

¢Ý ÓýºÍ·µÎ¹Ü¼ÓÕôÁóˮʱ£¬¼ÓÈë¹ý¿ì¶øʹҺÃ泬¹ýÁ˿̶ÈÏߣ¬Á¢¼´ÓõιÜÎüÈ¥¶àÓàµÄË®£¬Ê¹ÈÜÒº°¼Ê¯¸ÕºÃÓë¿Ì¶ÈÏßÏàÇС£

¢Þ µÎ¼ÓÈëÕôÁóË®£¬Ê¹ÈÜÒº°¼Ãæ¸ÕºÃÓë¿Ì¶ÈÏßÏàÇУ¬¸ÇÉÏÆ¿Èû·´¸´Ò¡ÔȺ󣬾²Ö㬷¢ÏÖҺʯ±È¿Ì¶ÈÏߵͣ¬ÔÙ¼ÓË®ÖÁ¿Ì¶ÈÏß¡£

ÏÖÓÐij»ÆÍ­(Í­¡¢Ð¿ºÏ½ð)µÄ¿ÅÁ£×´ÑùÆ·Ô¼100 mg£¬Ä³Í¬Ñ§½«ÑùÆ··ÖΪÁ½µÈ·Ý£¬Ê×ÏÈÓÃÏÂͼËùʾװÖòⶨ»ÆÍ­ÑùÆ·ÖÐпµÄÖÊÁ¿·ÖÊýºÍпµÄÏà¶ÔÔ­×ÓÖÊÁ¿¡£

»Ø´ðÏÂÁÐÎÊÌ⣺

(1)ʵÑ鿪ʼʱ£¬ÓûʹװÖÃÖеÄÏ¡ÁòËáºÍ»ÆÍ­ÖеÄп·¢Éú·´Ó¦£¬Ó¦½øÐеIJÙ×÷ÊÇ____________

______________________£»·´Ó¦½áÊøºó£¬»Ö¸´ÖÁ·´Ó¦Ç°µÄζȣ¬¶Ô¼îʽµÎ¶¨¹Ü½øÐÐ׼ȷ¶ÁÊýÇ°£¬Ó¦½øÐеıØÒª²Ù×÷ÊÇ£º______________________________________________________

(2)ΪÁ˱£Ö¤ÊµÑé½á¹ûµÄ׼ȷ£¬ÇëÄ㽫±¾ÊµÑé¹ý³ÌÖÐÐèÖ±½Ó²â¶¨µÄÓйØÎïÀíÁ¿ÌîÈëϱíÖÐ(ÓÃÎÄ×Ö˵Ã÷£¬²»±ØÌîÂú)£º

¢Ù

¢Ú

¢Û

¢Ü

¢Ý

¢Þ

 

 

 

 

 

 

(3)ijͬѧ»¹ÏëÀûÓÃÍÐÅÌÌìƽºÍÏÂͼËùʾװÖÃÍê³ÉпµÄÖÊÁ¿·ÖÊýºÍпµÄÏà¶ÔÔ­×ÓÖÊÁ¿µÄ²â¶¨ÊµÑé¡£

¢Ù¸ÃʵÑé¹ý³ÌÖУ¬±ØÐë¶Ô·´Ó¦ºóËùÊ£µÄ¹ÌÌå½øÐÐÏ´µÓ¡¢¸ÉÔÈçºÎÈ·¶¨ËùµÃ¹ÌÌåÊǸÉÔïµÄ_____________________________________________________________________¡£

¢ÚÇëÄã´Ó¸ÃʵÑé×°Öá¢ÖÐѧ»¯Ñ§ÊµÑéÊÒµÄÏÖÓÐÌõ¼þÁ½·½Ã棬¶Ô¸ÃʵÑé·½°¸µÄ¿ÉÐÐÐÔ½øÐÐÆÀ¼Û£º___________________________________________________________________¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø