ÌâÄ¿ÄÚÈÝ
ÒÑÖª²ð¿ª1 molÇâÆøÖеĻ¯Ñ§¼üÐèÒªÏûºÄ436 kJÄÜÁ¿£¬²ð¿ª1 molÑõÆøÖеĻ¯Ñ§¼üÐèÒªÏûºÄ498 kJ ÄÜÁ¿£¬¸ù¾ÝͼÖеÄÄÜÁ¿Í¼£¬»Ø´ðÏÂÁÐÎÊÌ⣺
![]()
£¨1£©·Ö±ðд³ö¢Ù¢ÚµÄÊýÖµ£º
¢Ù___________KJ£» ¢Ú____________KJ¡£
£¨2£©Éú³ÉH2O£¨g£©ÖеÄ1 mol H¡ªO¼ü·Å³ö_____________kJµÄÄÜÁ¿¡£
£¨3£©ÒÑÖª£ºH2O£¨l£©====H2O£¨g£©
¦¤H =" +44" kJ¡¤mol-1£¬ÊÔд³ö2 molÇâÆøÔÚ×ãÁ¿ÑõÆøÖÐÍêȫȼÉÕÉú³ÉҺ̬ˮµÄÈÈ»¯Ñ§·½³Ì______________________¡£
£¨1£©¢Ù 1370 ¢Ú 1852 £¨2£©463
£¨3£©2H2£¨g£©+O2£¨g£©====2H2O£¨l£©¦¤H ="-570" kJ¡¤mol-1
¡¾½âÎö¡¿£¨3£©
ÊÔÌâ·ÖÎö£º£¨1£©ÖУ¬ÒÑÖª²ð¿ª1 molÇâÆøÖеĻ¯Ñ§¼üÐèÒªÏûºÄ436 kJÄÜÁ¿£¬²ð¿ª1 molÑõÆøÖеĻ¯Ñ§¼üÐèÒªÏûºÄ498 kJ ÄÜÁ¿£¬ËùÒÔ²ð¿ªÁ½Ä¦¶ûÇâÆøºÍһĦ¶ûÑõÆø£¬ÐèÒªµÄÄÜÁ¿Îª2*436+498=1370KJ£¬¢ÚÖиù¾ÝÄÜÁ¿Êغ㣬¿ÉÒÔÖªµÀ·Å³öµÄÄÜÁ¿Îª1370+482=1852KJ£»£¨2£©ÖÐÉú³ÉH2O£¨g£©ÖеÄ1 mol H¡ªO¼ü·Å³öµÄÄÜÁ¿Îª 1852 /4=463kJ£»£¨3£©¸ù¾ÝÇ°ÃæÁ½²½¿ÉÒÔÖªµÀ
2H2£¨g£©+O2£¨g£©====2H2O£¨g£©¦¤H =-482kJ¡¤mol-1£¬ÓÐÒòΪ
H2O£¨l£©====H2O£¨g£©¦¤H =" +44" kJ¡¤mol-1£¬ËùÒÔ2 molÇâÆøÔÚ×ãÁ¿ÑõÆøÖÐÍêȫȼÉÕÉú³ÉҺ̬ˮµÄÈÈ»¯Ñ§·½³ÌΪ2H2£¨g£©+O2£¨g£©====2H2O£¨l£©¦¤H ="-570" kJ¡¤mol-1¡£
¿¼µã£ºÈÈ»¯Ñ§·½³Ìʽ
µãÆÀ£º±¾Ì⿼²éÁËÈÈ»¯Ñ§·½³Ìʽ£¬ÊôÓڸ߿¼¿¼²éµÄÖØµã£¬±¾ÌâҪעÒâ¡÷HµÄ¼ÆË㣬¸ÃÌâ×ÜÌå²»ÄÑ¡£