ÌâÄ¿ÄÚÈÝ

ÎåÖÖ¶ÌÖÜÆÚÔªËصÄÐÔÖÊ»òÔ­×ӽṹÐÅÏ¢ÈçÏÂ±í£º
ÔªËØ
ÔªËØÐÔÖÊ»òÔ­×ӽṹÐÅÏ¢
Q
Ô­×ÓºËÍâÓÐ6ÖÖ²»Í¬Ô˶¯×´Ì¬µÄµç×Ó
R
×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµç×ÓÊýµÄ3±¶
X
Æø̬Ç⻯ÎïµÄË®ÈÜÒº³ÊÈõ¼îÐÔ
Y
µÚÈýÖÜÆÚÔªËصļòµ¥Àë×ÓÖÐÀë×Ӱ뾶×îС
Z
µ¥ÖÊΪÒø°×É«¹ÌÌ壬ÔÚ¿ÕÆøÖÐȼÉÕ·¢³ö»ÆÉ«»ðÑæ
Çë¸ù¾Ý±íÖÐÐÅÏ¢»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©QÔ­×ӵĵç×ÓÅŲ¼Ê½Îª___________________________£¬ÆäͬλËØÓР            ¡£
£¨2£©RÓëZ×é³ÉµÄ»¯ºÏÎïµÄ»¯Ñ§Ê½ÊÇ                  ¡£
£¨3£©XÆø̬Ç⻯Îï·Ö×ӵĿռ乹ÐÍΪ               ¡£XµÄ×î¸ß¼ÛÑõ»¯Îï¶ÔÓ¦µÄË®»¯ÎïÆäŨÈÜÒºÓëͬÀàÎïÖÊÏà±ÈÔÚ»¯Ñ§ÐÔÖÊÉϱíÏÖµÄÌØÊâÐÔÓР                      ¡£
£¨4£©Yµ¥ÖÊÓëV2O5·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                                         ¡£
£¨5£©ÔÚ1.01¡Á105Pa¡¢298Kʱ£¬1.4gQRÆøÌåÔÚ1.6gR2ÆøÌåÖÐÍêȫȼÉÕ£¬Éú³ÉQR2ÆøÌåʱ·Å³ö14.15kJÈÈÁ¿£¬±íʾQRȼÉÕµÄÈÈ»¯Ñ§·½³ÌʽΪ                            ¡£
£¨1£©1s22s22p2£¨1·Ö£©      12C¡¢13C¡¢14C £¨1·Ö£©
£¨2£©Na2O¡¢Na2O2£¨1·Ö£©
£¨3£©Èý½Ç׶ÐΣ¨1·Ö£©²»Îȶ¨ÐÔºÍÇ¿Ñõ»¯ÐÔ£¨2·Ö£©
£¨4£©10Al+3V2O5     5Al2O3 +6V£¨2·Ö£¬Î´Åäƽ»òȱ·´Ó¦Ìõ¼þ¿Û1·Ö£©
£¨5£©2CO(g)+O2(g)¡ú2CO2(g)+566KJ£¨2·Ö
ÂÔ
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø