ÌâÄ¿ÄÚÈÝ

(1998ÄêÉϺ££¬31)Âȼµç½â±¥ºÍʳÑÎË®ÖÆÈ¡NaOHµÄ¹¤ÒÕÁ÷³ÌʾÒâͼ14-4ÈçÏÂ

ͼ14-4

ÒÀ¾ÝÉÏͼ£¬Íê³ÉÏÂÁÐÌî¿Õ£º

(1)ÔÚµç½â¹ý³ÌÖУ¬ÓëµçÔ´Õý¼«ÏàÁ¬µÄµç¼«ÉÏËù·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ                    £¬ÓëµçÔ´¸º¼«ÏàÁ¬µÄµç¼«¸½½ü£¬ÈÜÒºpH         (Ñ¡Ìî¡°²»±ä¡±¡°Éý¸ß¡±»ò¡°Ï½µ¡±)¡£

(2)¹¤ÒµÊ³Ñκ¬Ca2+¡¢Mg2+µÈÔÓÖÊ¡£¾«Öƹý³Ì·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ

                     ¡¢                 ¡£

(3)Èç¹û´ÖÑÎÖк¬Á¿½Ï¸ß£¬±ØÐëÌí¼Ó±µÊÔ¼Á³ýÈ¥£¬¸Ã±µÊÔ¼Á¿ÉÒÔÊÇ                  (Ñ¡Ìîa£¬b£¬c¶àÑ¡¿Û·Ö)¡£

a.Ba(OH)2        b.Ba(NO3)2        c.BaCl2

(4)ΪÓÐЧ³ýÈ¥Ca2+¡¢Mg2+¡¢£¬¼ÓÈëÊÔ¼ÁµÄºÏÀí˳ÐòΪ         (Ñ¡Ìîa¡¢b¡¢c¶àÑ¡¿Û·Ö)¡£

a.ÏȼÓNaOH£¬ºó¼ÓNa2CO3£¬ÔÙ¼Ó±µÊÔ¼Á

b.ÏȼÓNaOH£¬ºó¼Ó±µÊÔ¼Á£¬ÔÙ¼ÓNa2CO3

c.ÏȼӱµÊÔ¼Á£¬ºó¼ÓNaOH£¬ÔÙ¼ÓNa2CO3

(5)ÍÑÑι¤ÐòÖÐÀûÓÃNaOHºÍNaClÔÚÈܽâ¶ÈÉϵIJîÒ죬ͨ¹ý       ¡¢ÀäÈ´¡¢       (Ìîд²Ù×÷Ãû³Æ)³ýÈ¥NaCl

(6)ÔÚ¸ôĤ·¨µç½âʳÑÎˮʱ£¬µç½â²Û·Ö¸ôΪÑô¼«ÇøºÍÒõ¼«Çø£¬·ÀÖ¹Cl2ÓëNaOH·´Ó¦£»²ÉÓÃÎÞ¸ôĤµç½âÀäµÄʳÑÎˮʱ£¬Cl2ÓëNaOH³ä·Ö½Ó´¥£¬²úÎï½öÊÇNaClOºÍH2£¬ÏàÓ¦µÄ»¯Ñ§·½³ÌʽΪ                 ¡£

´ð°¸£º

(1)2Cl£­£­2e£­====Cl2£»Éý¸ß

(2)Ca2++====CaCO3¡ý

Mg2++2OH£­====Mg(OH)2¡ý

(3)a¡¢c        (4)b¡¢c        (5)Õô·¢£»¹ýÂË

(6)NaCl+H2O====NaClO+H2¡ü

»ò2NaCl+2H2O====H2¡ü+Cl2¡ü+2NaOH

Cl2+2NaOH====NaCl+NaClO+H2O


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

£¨8·Ö£©(1998ÄêÉϺ£)Âȼµç½â±¥ºÍʳÑÎË®ÖÆÈ¡NaOHµÄ¹¤ÒÕÁ÷³ÌʾÒâͼÈçÏÂ

ÒÀ¾ÝÉÏͼ£¬Íê³ÉÏÂÁÐÌî¿Õ£º

(1)ÔÚµç½â¹ý³ÌÖУ¬ÓëµçÔ´Õý¼«ÏàÁ¬µÄµç¼«ÉÏËù·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ              £¬ÓëµçÔ´¸º¼«ÏàÁ¬µÄµç¼«¸½½ü£¬ÈÜÒºpH             (Ñ¡Ìî¡°²»±ä¡±¡°Éý¸ß¡±»ò¡°Ï½µ¡±)¡£

(2)¹¤ÒµÊ³Ñκ¬Ca2+¡¢Mg2+µÈÔÓÖÊ¡£¾«Öƹý³Ì·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ

                                ¡¢                                    ¡£

(3)Èç¹û´ÖÑÎÖÐSO42-º¬Á¿½Ï¸ß£¬±ØÐëÌí¼Ó±µÊÔ¼Á³ýÈ¥SO42-£¬¸Ã±µÊÔ¼Á¿ÉÒÔ

ÊÇ          (Ñ¡Ìîa£¬b£¬c¶àÑ¡¿Û·Ö)¡£

a£®Ba(OH)2        b£®Ba(NO3)2       c£®BaCl2

(4)ΪÓÐЧ³ýÈ¥Ca2+¡¢Mg2+¡¢SO42¡ª£¬¼ÓÈëÊÔ¼ÁµÄºÏÀí˳ÐòΪ       (Ñ¡Ìîa¡¢b¡¢c¶àÑ¡¿Û·Ö)

a£®ÏȼÓNaOH,ºó¼ÓNa2CO3£¬ÔÙ¼Ó±µÊÔ¼Á

b£®ÏȼÓNaOH£¬ºó¼Ó±µÊÔ¼Á£¬ÔÙ¼ÓNa2CO3

c£®ÏȼӱµÊÔ¼Á£¬ºó¼ÓNaOH£¬ÔÙ¼ÓNa2CO3

(5)ÍÑÑι¤ÐòÖÐÀûÓÃNaOHºÍNaClÔÚÈܽâ¶ÈÉϵIJîÒ죬ͨ¹ý       ¡¢ÀäÈ´¡¢              (Ìîд²Ù×÷Ãû³Æ)³ýÈ¥NaCl

(6)ÔÚ¸ôĤ·¨µç½âʳÑÎˮʱ£¬µç½â²Û·Ö¸ôΪÑô¼«ÇøºÍÒõ¼«Çø£¬·ÀÖ¹Cl2ÓëNaOH·´Ó¦£»²ÉÓÃÎÞ¸ôĤµç½âÀäµÄʳÑÎˮʱ£¬Cl2ÓëNaOH³ä·Ö½Ó´¥£¬²úÎï½öÊÇNaClOºÍH2£¬ÏàÓ¦µÄ»¯Ñ§·½³ÌʽΪ                                                           ¡£

 

£¨8·Ö£©(1998ÄêÉϺ£)Âȼµç½â±¥ºÍʳÑÎË®ÖÆÈ¡NaOHµÄ¹¤ÒÕÁ÷³ÌʾÒâͼÈçÏÂ

ÒÀ¾ÝÉÏͼ£¬Íê³ÉÏÂÁÐÌî¿Õ£º
(1)ÔÚµç½â¹ý³ÌÖУ¬ÓëµçÔ´Õý¼«ÏàÁ¬µÄµç¼«ÉÏËù·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ              £¬ÓëµçÔ´¸º¼«ÏàÁ¬µÄµç¼«¸½½ü£¬ÈÜÒºpH             (Ñ¡Ìî¡°²»±ä¡±¡°Éý¸ß¡±»ò¡°Ï½µ¡±)¡£
(2)¹¤ÒµÊ³Ñκ¬Ca2+¡¢Mg2+µÈÔÓÖÊ¡£¾«Öƹý³Ì·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ
                                ¡¢                                    ¡£
(3)Èç¹û´ÖÑÎÖÐSO42-º¬Á¿½Ï¸ß£¬±ØÐëÌí¼Ó±µÊÔ¼Á³ýÈ¥SO42-£¬¸Ã±µÊÔ¼Á¿ÉÒÔ
ÊÇ          (Ñ¡Ìîa£¬b£¬c¶àÑ¡¿Û·Ö)¡£
a£®Ba(OH)2        b£®Ba(NO3)2        c£®BaCl2
(4)ΪÓÐЧ³ýÈ¥Ca2+¡¢Mg2+¡¢SO42¡ª£¬¼ÓÈëÊÔ¼ÁµÄºÏÀí˳ÐòΪ      (Ñ¡Ìîa¡¢b¡¢c¶àÑ¡¿Û·Ö)
a£®ÏȼÓNaOH,ºó¼ÓNa2CO3£¬ÔÙ¼Ó±µÊÔ¼Á
b£®ÏȼÓNaOH£¬ºó¼Ó±µÊÔ¼Á£¬ÔÙ¼ÓNa2CO3
c£®ÏȼӱµÊÔ¼Á£¬ºó¼ÓNaOH£¬ÔÙ¼ÓNa2CO3
(5)ÍÑÑι¤ÐòÖÐÀûÓÃNaOHºÍNaClÔÚÈܽâ¶ÈÉϵIJîÒ죬ͨ¹ý      ¡¢ÀäÈ´¡¢              (Ìîд²Ù×÷Ãû³Æ)³ýÈ¥NaCl
(6)ÔÚ¸ôĤ·¨µç½âʳÑÎˮʱ£¬µç½â²Û·Ö¸ôΪÑô¼«ÇøºÍÒõ¼«Çø£¬·ÀÖ¹Cl2ÓëNaOH·´Ó¦£»²ÉÓÃÎÞ¸ôĤµç½âÀäµÄʳÑÎˮʱ£¬Cl2ÓëNaOH³ä·Ö½Ó´¥£¬²úÎï½öÊÇNaClOºÍH2£¬ÏàÓ¦µÄ»¯Ñ§·½³ÌʽΪ                                                           ¡£

£¨8·Ö£©(1998ÄêÉϺ£)Âȼµç½â±¥ºÍʳÑÎË®ÖÆÈ¡NaOHµÄ¹¤ÒÕÁ÷³ÌʾÒâͼÈçÏÂ

ÒÀ¾ÝÉÏͼ£¬Íê³ÉÏÂÁÐÌî¿Õ£º

(1)ÔÚµç½â¹ý³ÌÖУ¬ÓëµçÔ´Õý¼«ÏàÁ¬µÄµç¼«ÉÏËù·¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ               £¬ÓëµçÔ´¸º¼«ÏàÁ¬µÄµç¼«¸½½ü£¬ÈÜÒºpH              (Ñ¡Ìî¡°²»±ä¡±¡°Éý¸ß¡±»ò¡°Ï½µ¡±)¡£

(2)¹¤ÒµÊ³Ñκ¬Ca2+¡¢Mg2+µÈÔÓÖÊ¡£¾«Öƹý³Ì·¢Éú·´Ó¦µÄÀë×Ó·½³ÌʽΪ

                                 ¡¢                                     ¡£

(3)Èç¹û´ÖÑÎÖÐSO42-º¬Á¿½Ï¸ß£¬±ØÐëÌí¼Ó±µÊÔ¼Á³ýÈ¥SO42-£¬¸Ã±µÊÔ¼Á¿ÉÒÔ

ÊÇ           (Ñ¡Ìîa£¬b£¬c¶àÑ¡¿Û·Ö)¡£

a£®Ba(OH)2        b£®Ba(NO3)2        c£®BaCl2

(4)ΪÓÐЧ³ýÈ¥Ca2+¡¢Mg2+¡¢SO42¡ª£¬¼ÓÈëÊÔ¼ÁµÄºÏÀí˳ÐòΪ       (Ñ¡Ìîa¡¢b¡¢c¶àÑ¡¿Û·Ö)

a£®ÏȼÓNaOH,ºó¼ÓNa2CO3£¬ÔÙ¼Ó±µÊÔ¼Á

b£®ÏȼÓNaOH£¬ºó¼Ó±µÊÔ¼Á£¬ÔÙ¼ÓNa2CO3

c£®ÏȼӱµÊÔ¼Á£¬ºó¼ÓNaOH£¬ÔÙ¼ÓNa2CO3

(5)ÍÑÑι¤ÐòÖÐÀûÓÃNaOHºÍNaClÔÚÈܽâ¶ÈÉϵIJîÒ죬ͨ¹ý       ¡¢ÀäÈ´¡¢               (Ìîд²Ù×÷Ãû³Æ)³ýÈ¥NaCl

(6)ÔÚ¸ôĤ·¨µç½âʳÑÎˮʱ£¬µç½â²Û·Ö¸ôΪÑô¼«ÇøºÍÒõ¼«Çø£¬·ÀÖ¹Cl2ÓëNaOH·´Ó¦£»²ÉÓÃÎÞ¸ôĤµç½âÀäµÄʳÑÎˮʱ£¬Cl2ÓëNaOH³ä·Ö½Ó´¥£¬²úÎï½öÊÇNaClOºÍH2£¬ÏàÓ¦µÄ»¯Ñ§·½³ÌʽΪ                                                            ¡£

 

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø