ÌâÄ¿ÄÚÈÝ
¡¾ÌâÄ¿¡¿Ñõ»¯Ìú»Æ£¨»¯Ñ§Ê½ÎªFeOOH£©ÊÇÒ»ÖÖ»ÆÉ«ÑÕÁÏ£¬¹¤ÒµÉÏÓ÷ÏÌúΪÖ÷ÒªÔÁÏÉú²úÑõ»¯Ìú»ÆµÄÒ»ÖÖ¹¤ÒÕÁ÷³ÌÈçÏ£º
£¨1£©Ñõ»¯Ìú»ÆÖÐÌúÔªËصĻ¯ºÏ¼ÛΪ £¬·ÏÌúÔÚ·´Ó¦Ç°³£ÓÃÈȵĴ¿¼îÈÜÒºÇåÏ´±íÃæÓÍÎÛ£¬ÆäÔÀíÊÇ (дÀë×Ó·½³Ìʽ)¡£
£¨2£©Ñõ»¯¹ý³ÌÉú³ÉÑõ»¯Ìú»ÆµÄ»¯Ñ§·½³ÌʽÊÇ ¡£
£¨3£©ÉÏÊöÁ÷³ÌÖУ¬¼ìÑé¡°Ï´µÓ¡±ÊÇ·ñÍêÈ«µÄ·½·¨ÊÇ ¡£
£¨4£©Ñõ»¯Ê±Ó¦¿ØÖÆpHµÄºÏÀí·¶Î§ÊÇ3.5-4.0£¬pH¹ýСµ¼ÖÂÑõ»¯Ìú»Æ²úÂʽϵ͵ĿÉÄÜÔÒòÊÇ ¡£
£¨5£©È¡1gÑùÆ·½øÐд¿¶È²âÊÔ£¬½«ÆäÈܽâÓÚ×ãÁ¿Ï¡ÑÎËáÖУ¬ºóÓÃÒ»¶¨Å¨¶ÈµÄ¹ýÁ¿NaOHÈÜÒº³ÁµíÆäÖеÄÌúÔªËØ£¬µÃµ½³ÁµíµÄÖÊÁ¿ÎªBg£¬ÊÔÓÃËù¸øÊý¾ÝÇó³ö²úÆ·µÄ´¿¶È ¡£
¡¾´ð°¸¡¿£¨1£©+3£¬CO32-+H2OHCO3-+OH-£¨2£©4FeSO4+O2+8NaOH£½FeOOH¡ý+4Na2SO4+2H2O£¨3£©È¡×îºóÒ»´ÎÏ´µÓÒº£¬¼ÓÈëÉÙÁ¿ÂÈ»¯±µÈÜÒº£¬ºó¼ÓÈëÊÊÁ¿Ï¡ÑÎËᣬÈçδ¹Û²ìµ½°×É«³Áµí£¬¼´¿ÉÖ¤Ã÷Ï´¸É¾»
£¨4£©pH¹ýµÍµ¼ÖÂÑõ»¯Ìú»Æ²¿·ÖÈÜÓÚËá £¨5£©89B/107 ¡Á100%
¡¾½âÎö¡¿
ÊÔÌâ·ÖÎö£º£¨1£©ÑõÔªËغÍÇâÔªËصĻ¯ºÏ¼Û·Ö±ðÊÇ£2¼ÛºÍ£«1¼Û£¬Ôò¸ù¾Ý»¯ºÏ¼Û´úÊýºÍΪ0¿ÉÖªÑõ»¯Ìú»ÆÖÐÌúÔªËصĻ¯ºÏ¼ÛΪ£«3¼Û£»´¿¼îË®½âÉú³ÉÇâÑõ»¯ÄÆ£¬ÇâÑõ»¯ÄÆ¿ÉÒÔºÍÓÍÎÛ·¢Éú·´Ó¦£¬Àë×Ó·½³ÌʽΪ£ºCO32-+H2OHCO3-+OH-£»
£¨2£©Ñõ»¯Éú³ÉÑõ»¯Ìú»ÆµÄ»¯Ñ§·½³ÌʽΪ£º4FeSO4+O2+8NaOH£½FeOOH¡ý+4Na2SO4+2H2O¡£
£¨3£©Ï´µÓÊÇΪÁ˳ýÈ¥Ñõ»¯Ìú»ÆÖеÄÁòËáÄÆ£¬ËùÒÔÖ»ÐèÒª¼ìÑéÊÇ·ñ»¹´æÔÚÓÐÁòËá¸ùÀë×Ó¼´¿É£¬¼ìÑéÁòËá¸ùÓÃÑÎËáËữµÄÂÈ»¯±µÈÜÒº£¬¼´ÉÙÁ¿×îºóÒ»´ÎµÄÏ´µÓÒºÓÚÊÔ¹ÜÖУ¬ÏòÆäÖеμÓÑÎËáËữµÄBaCl2ÈÜÒº£¬Èô²»²úÉú°×É«³Áµí£¬Ôò±íÃ÷ÒÑÏ´µÓ¸É¾»£¬·ñÔòδϴµÓ¸É¾»¡£
£¨4£©ÓÉÓÚpH¹ýµÍ»áµ¼ÖÂÑõ»¯Ìú»Æ²¿·ÖÈÜÓÚËᣬËùÒÔµ¼ÖÂÑõ»¯Ìú»Æ²úÂʽϵ͡£
£¨5£©È¡1gÑùÆ·½øÐд¿¶È²âÊÔ£¬½«ÆäÈܽâÓÚ×ãÁ¿Ï¡ÑÎËáÖУ¬ºóÓÃÒ»¶¨Å¨¶ÈµÄ¹ýÁ¿NaOHÈÜÒº³ÁµíÆäÖеÄÌúÔªËØ£¬µÃµ½³ÁµíµÄÖÊÁ¿ÎªBg£¬³ÁµíÊÇÇâÑõ»¯Ìú£¬Ôò²úÆ·µÄ´¿¶ÈΪ¡£
![](http://thumb2018.1010pic.com/images/loading.gif)