ÌâÄ¿ÄÚÈÝ
W¡¢X¡¢Y¡¢Z¾ùΪµÄ¶ÌÖÜÆÚÔªËØ£¬Ô×ÓÐòÊýÒÀ´ÎÔö¼Ó£¬ WµÄÔ×ÓºËÍâ×îÍâ²ãµç×ÓÊýÊÇ´ÎÍâ²ãµÄ2±¶£¬ X-¡¢Y+¾ßÓÐÏàͬµÄµç×Ó²ã½á¹¹£¬ ZµÄÒõÀë×Ó²»ÄÜ·¢ÉúË®½â·´Ó¦¡£ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ
A. Ô×Ӱ뾶£ºY>Z>X>W
B. ¼òµ¥Ç⻯ÎïµÄ·Ðµã£º Z>X>W
C. ×î¸ß¼ÛÑõ»¯ÎïµÄË®»¯ÎïµÄËáÐÔ£ºW<Z<X
D. XÓëYÁ½ÖÖÔªËØ×é³ÉµÄ»¯ºÏÎïÊÇÀë×Ó»¯ºÏÎï
¼×´¼ÊÇÖØÒªµÄ»¯Ñ§¹¤Òµ»ù´¡ÔÁϺÍÇå½àÒºÌåȼÁÏ¡£¹¤ÒµÉÏ¿ÉÀûÓÃCO»òCO2À´Éú²úȼÁϼ״¼¡£ÒÑÖª¼×´¼ÖƱ¸µÄÓйػ¯Ñ§·´Ó¦ÒÔ¼°ÔÚ²»Í¬Î¶ÈϵĻ¯Ñ§·´Ó¦Æ½ºâ³£ÊýÈçϱíËùʾ£º
»¯Ñ§·´Ó¦ | ƽºâ³£Êý | ζȡæ | |
500 | 800 | ||
¢Ù2H2(g)+CO(g) CH3OH(g) | K1 | 2.5 | 0.15 |
¢ÚH2(g)+CO2(g) H2O (g)+CO(g) | K2 | 1.0 | 2.50 |
¢Û3H2(g)+CO2(g) CH3OH(g)+H2O (g) | K3 | ||
£¨1£©·´Ó¦¢ÚÊÇ________________£¨Ìî¡°ÎüÈÈ¡±»ò¡°·ÅÈÈ¡±£©·´Ó¦¡£
£¨2£©Ä³Î¶ÈÏ·´Ó¦¢ÙÖÐH2µÄƽºâת»¯ÂÊ£¨a£©ÓëÌåϵ×Üѹǿ(P)µÄ¹Øϵ£¬Èç×óÏÂͼËùʾ¡£Ôòƽºâ״̬ÓÉA±äµ½Bʱ£¬Æ½ºâ³£ÊýK(A)_____________K(B)£¨Ìî¡°£¾¡±¡¢¡°£¼¡±»ò¡°£½¡±£©¡£¾Ý·´Ó¦¢ÙÓë¢Ú¿ÉÍƵ¼³öK1¡¢K2ÓëK3Ö®¼äµÄ¹Øϵ£¬ÔòK3=_______£¨ÓÃK1¡¢K2±íʾ£©¡£
£¨3£©ÔÚ3 LÈÝ»ý¿É±äµÄÃܱÕÈÝÆ÷Öз¢Éú·´Ó¦¢Ú£¬ÒÑÖªc(CO)Ó뷴Ӧʱ¼ät±ä»¯ÇúÏߢñÈçÓÒÉÏͼËùʾ£¬ÈôÔÚt0ʱ¿Ì·Ö±ð¸Ä±äÒ»¸öÌõ¼þ£¬ÇúÏߢñ±äΪÇúÏߢòºÍÇúÏߢó¡£
µ±ÇúÏߢñ±äΪÇúÏߢòʱ£¬¸Ä±äµÄÌõ¼þÊÇ_____________________¡£
µ±ÇúÏߢñ±äΪÇúÏߢóʱ£¬¸Ä±äµÄÌõ¼þÊÇ_____________________¡£
£¨4£©Ò»ÖÖ¼×´¼È¼Áϵç³Ø£¬Ê¹Óõĵç½âÖÊÈÜÒºÊÇ2mol¡¤L£1µÄKOHÈÜÒº¡£
Çëд³ö¼ÓÈë(ͨÈë)bÎïÖÊÒ»¼«µÄµç¼«·´Ó¦Ê½_________________£»
ÿÏûºÄ6.4g¼×´¼×ªÒƵĵç×ÓÊýΪ_______________¡£
£¨5£©Ò»¶¨Ìõ¼þϼ״¼ÓëÒ»Ñõ»¯Ì¼·´Ó¦¿ÉÒԺϳÉÒÒËᡣͨ³£×´¿öÏ£¬½«a mol/LµÄ´×ËáÓëb mol/LBa(OH)2ÈÜÒºµÈÌå»ý»ìºÏºó£¬ÈÜÒºÖУº2c(Ba2£«)= c(CH3COO-)£¬Óú¬aºÍbµÄ´úÊýʽ±íʾ¸Ã»ìºÏÈÜÒºÖд×ËáµÄµçÀë³£ÊýKaΪ________________¡£
ÒÒËáÒìÎìõ¥ÊÇ×é³ÉÃÛ·äÐÅÏ¢ËصijɷÖÖ®Ò»£¬¾ßÓÐÏ㽶µÄÏãζ¡£ÊµÑéÊÒÖƱ¸ÒÒËáÒìÎìõ¥µÄ·´Ó¦¡¢×°ÖúÍÓйØÊý¾ÝÈçÏ£º
Ïà¶Ô·Ö×ÓÖÊÁ¿ | Ãܶȣ¯(g¡¤cm3) | ·Ðµã£¯¡æ | Ë®ÖÐÈܽâÐÔ | |
ÒìÎì´¼ | 88 | 0.8123 | 131 | ΢ÈÜ |
ÒÒËá | 60 | 1.0492 | 118 | ÈÜ |
ÒÒËáÒìÎìõ¥ | 130 | 0.8670 | 112 | ÄÑÈÜ |
ʵÑé²½Ö裺
ÔÚA ÖмÓÈë4.40gÒìÎì´¼¡¢6.00gÒÒËá¡¢ÊýµÎŨÁòËáºÍ2¡«3ƬËé´ÉƬ¡£¿ªÊ¼»ºÂý¼ÓÈÈA£¬»ØÁ÷50min¡£·´Ó¦ÒºÀäÖÁÊÒκóµ¹Èë·ÖҺ©¶·ÖУ¬·Ö±ðÓÃÉÙÁ¿Ë®¡¢±¥ºÍ̼ËáÇâÄÆÈÜÒººÍˮϴµÓ£»·Ö³öµÄ²úÎï¼ÓÈëÉÙÁ¿ÎÞË®MgSO4¹ÌÌ壬¾²ÖÃƬ¿Ì£¬¹ýÂ˳ýÈ¥MgSO4¹ÌÌ壬½øÐÐÕôÁó´¿»¯£¬ÊÕ¼¯140¡«143¡æÁó·Ö£¬µÃÒÒËáÒìÎìõ¥4.55g¡£
Çë»Ø´ðÏÂÁÐÎÊÌ⣺
£¨1£©ÒÇÆ÷BµÄÃû³ÆÊÇ_____£»BÖÐÀäÈ´Ë®ÊÇ´Ó_____£¨Ìî¡°Ï¿ڡ±»ò¡°ÉÏ¿Ú¡±£©Á÷½øµÄ¡£
£¨2£©¼ÓÈëËé´ÉƬµÄ×÷ÓÃÊÇ_______£»Èç¹û¼ÓÈÈÒ»¶Îʱ¼äºó·¢ÏÖÍü¼Ç¼Ó´ÉƬ£¬Ó¦¸Ã²ÉÈ¡µÄ²Ù×÷ÊÇ_____________________¡£
£¨3£©ÔÚÏ´µÓ¡¢·ÖÒº²Ù×÷ÖУ¬µÚ¶þ´ÎÏ´µÓ£¬Óñ¥ºÍ̼ËáÇâÄÆÈÜҺϴµÓµÄÖ÷ҪĿµÄÊÇ_______£¬²»ÄÜÓÃNaOHÈÜҺϴµÓµÄÔÒòÊÇ___________¡£µÚ¶þ´ÎÏ´µÓºó£¬³ä·ÖÕñµ´£¬È»ºó¾²Ö㬴ý·Ö²ãºó£¬²úÎïÓ¦¸Ã´Ó·ÖҺ©¶·µÄ_______£¨Ìî¡°ÉÏ¿Úµ¹³ö¡±»ò¡°Ï¿ڷųö¡±£©¡£
£¨4£©ÔÚÕôÁó²Ù×÷ÖУ¬ÒÇÆ÷Ñ¡Ôñ¼°°²×°¶¼ÕýÈ·µÄÊÇÏÂͼÖеÄ_____£¨Ìî×Öĸ±êºÅ£©£¬Èô´Ó130¡æ ±ã¿ªÊ¼ÊÕ¼¯Áó·Ö£¬»áʹʵÑéµÄ²úÂÊ______£¨Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°ÎÞÓ°Ï족£©¡£
£¨5£©Ë®µÄ·ÐµãΪ100¡æ£¬±ÈÒÒËáÒìÎìõ¥µÍ42¡æ £¬µ«ÈÔÒªÏȼÓÈëMgSO4ºó¹ýÂËÔÙÕôÁ󣬶ø²»ÊÇÖ±½ÓÕôÁó¡£½áºÏÌâÖÐÐÅÏ¢·ÖÎö£¬ÏÂÁÐ˵·¨ÕýÈ·µÄÊÇ______£¨Ìî×Öĸ£©¡£
A.Ë®¿ÉÄÜ»áÓëÒÒËáÒìÎìõ¥ÐγÉÒ»ÖÖ¡°ºã·ÐÈÜÒº¡±£¨ÔÚÈÜÒºµÄijһ×é³Éʱ£¬ÔÚijζÈÏ£¬»ìºÏҺͬʱÆû»¯»òͬʱÀäÄý£©£¬²»ÄܽøÒ»²½Ìá´¿£¬ËùÒÔÒªÏÈÓÃMgSO4¸ÉÔï
B.ÔÚ¼ÓÈëMgSO4ºóÈç²»ÏȹýÂ˾ÍÕôÁ󣬼ÓÈÈʱÁòËáþµÄ½á¾§Ë®ºÏÎïÓÖ»áÍÑË®
C.Èç²»ÏÈÓÃMgSO4ÎüÊÕË®·Ö£¬ÕôÁóʱˮÏȱ»Õô³ö£¬ÀË·ÑÄÜÔ´ºÍÑÓ³¤ÕôÁóʱ¼ä
D.±¾ÊµÑéÖÐÒªÒÒËá¹ýÁ¿£¬¶ø²»ÊÇÒìÎì´¼¹ýÁ¿£¬¿ÉÄܵÄÔÒòÊÇÒìÎì´¼±ÈÒÒËá¼Û¸ñ¹ó£»ÁíÍâÒìÎì´¼¹ýÁ¿Ê±£¬ÒìÎì´¼ÓëÒÒËáÒìÎìõ¥·ÐµãÏà½ü(СÓÚ30¡æ£©£¬ÕôÁóʱÍêÈ«·ÖÀëÀ§ÄÑ
£¨6£©½«ÒÒËáÒìÎìõ¥ÖеÄÒìÎì´¼³ýÈ¥£¬ÊÇÔÚÄĸö²½ÖèÖгýÈ¥µÄ______£¨Ìî×Öĸ£©¡£
A.ÔÚµÚÒ»´ÎˮϴºÍºóÃæµÄ·ÖÒºÖгýÈ¥µÄ
B.ÔÚµÚ¶þ´ÎÓñ¥ºÍ̼ËáÇâÄÆÈÜҺϴµÓºÍºóÃæµÄ·ÖÒºÖгýÈ¥µÄ
C.ÔÚ¡°¹ýÂË¡±ÖгýÈ¥µÄ
D.ÓÉÓÚ±¾ÊµÑéÖмÓÈë¹ýÁ¿ÒÒËᣬÒìÎì´¼ÒѾ·´Ó¦ÍêÈ«£¬ËùÒÔ²»Ðè³ýÔÓ£¨ÒìÎì´¼£©ÁË
E.ÔÚ×îºóµÄ¡°ÕôÁó¡±²½ÖèÖгýÈ¥µÄ
£¨7£©²úÎïÒÒËáÒìÎìõ¥µÄ²úÂÊÊÇ__________¡£