ÌâÄ¿ÄÚÈÝ

A¡¢B¡¢C¡¢D¡¢EÊÇÖÐѧ½×¶Î³£¼ûµÄ5ÖÖ»¯ºÏÎA¡¢BÊÇÑõ»¯ÎԪËØX¡¢YµÄµ¥ÖÊÊÇÉú»îÖг£¼ûµÄ½ðÊô£¬Ïà¹ØÎïÖʼäµÄת»¯¹ØϵÈçͼËùʾ£º

(1)XµÄµ¥ÖÊÓëA·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_______________________________¡£
(2)ÈôÊÔ¼Á1ÊÇNaOHÈÜÒº£¬ÔòXµÄµ¥ÖÊÓëÊÔ¼Á1·´Ó¦µÄÀë×Ó·½³ÌʽÊÇ
___________________________________
(3)ÈôÊÔ¼Á1ºÍÊÔ¼Á2¾ùÊÇÏ¡ÁòËá¡£
¢Ù¼ìÑéÎïÖÊDµÄÈÜÒºÖнðÊôÀë×ӵķ½·¨ÊÇ___________________________________¡£
¢Ú½«ÎïÖÊCÈÜÓÚË®£¬ÆäÈÜÒº³ÊËáÐÔ£¬Ô­ÒòÊÇ(ÓÃÀë×Ó·½³Ìʽ±íʾ)
________________________________________________¡£
¢Ûij¸ßЧ¾»Ë®¼ÁÊÇÓÉY(OH)SO4¾ÛºÏµÃµ½µÄ£¬¹¤ÒµÉÏÒÔE¡¢Ï¡ÁòËáºÍÑÇÏõËáÄÆΪԭÁÏÖƱ¸Y(OH)SO4£¬·´Ó¦ÖÐÓÐNOÉú³É£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ_____________________¡£
(1)Fe2O3£«2Al2Fe£«Al2O3
(2)2Al£«2OH£­£«2H2O=2AlO2¡ª£«3H2¡ü
(3)¢ÙÈ¡ÉÙÁ¿DµÄÈÜÒºÓÚÊÔ¹ÜÖУ¬µÎ¼Ó¼¸µÎKSCNÈÜÒº£¬ÈÜÒº³ÊѪºìÉ«£¬Ö¤Ã÷ÓÐFe3£«
¢ÚAl3£«£«3H2OAl(OH)3£«3H£«
¢Û2FeSO4£«2NaNO2£«H2SO4=2Fe(OH)SO4£«Na2SO4£«2NO¡ü
A¡¢BÊÇÑõ»¯ÎԪËØX¡¢YµÄµ¥ÖÊÊÇÉú»îÖг£¼ûµÄ½ðÊô£¬½áºÏͼ¿ÉÖªAÊÇFe2O3£¬XµÄµ¥ÖÊÊÇAl£¬BÊÇAl2O3£¬YµÄµ¥ÖÊÊÇFe¡£ÈôÊÔ¼Á1ÊÇNaOHÈÜÒº£¬ÔòCΪNaAlO2¡£ÈôÊÔ¼Á1ºÍÊÔ¼Á2¾ùÊÇÏ¡ÁòËᣬÔòDµÄÈÜÒºÖк¬Fe3£«£¬¿ÉÓÃKSCNÈÜÒº¼ìÑ飬CµÄÈÜÒºÖк¬Al3£«£¬Ò×Ë®½â£¬EΪFeSO4¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ij»¯Ñ§ÐËȤС×éÓÃÂÁÍÁ¿ó(Ö÷Òª³É·ÖΪA12 O3,»¹º¬ÓÐSiO2¼°ÌúµÄÑõ»¯Îï)ÌáÈ¡Ñõ»¯ÂÁ×÷Ò±Á¶ÂÁµÄÔ­ÁÏ,ÌáÈ¡µÄ²Ù×÷¹ý³ÌÈçÏÂ:

(1)ÔÚ¹ýÂ˲Ù×÷ÖÐ,³ýÉÕ±­¡¢²£Á§°ôÍâ,»¹ÐèÓõ½µÄ²£Á§ÒÇÆ÷ÓР          ;Ï´µÓ³ÁµíµÄ²Ù×÷ÊÇ                                                                        ¡£
(2)ʵÑéÊÒÖƱ¸ÇâÑõ»¯ÂÁµÄ·½°¸ÓжàÖÖ¡£ÏÖÌṩÂÁм¡¢ÇâÑõ»¯ÄÆÈÜÒº¡¢Ï¡ÁòËáÈýÖÖÒ©Æ·,ÈôÖƱ¸µÈÁ¿µÄÇâÑõ»¯ÂÁ,ÇëÄã´ÓÒ©Æ·ÓÃÁ¿×îÉٵĽǶȳö·¢,Éè¼Æ³ö×î¼ÑʵÑé·½°¸(·½°¸²»±Ø¸ø³ö),д³ö´Ë·½°¸Öз¢Éú·´Ó¦µÄÀë×Ó·½³Ìʽ:                                                                                                                               ,´Ë·½°¸ÖÐËùÓÃÒ©Æ·µÄÎïÖʵÄÁ¿Ö®±ÈÊÇ:n(Al)¡Ãn(H2SO4)¡Ãn(NaOH) =       ¡£
(3)ÐËȤС×éÓû¶ÔÂÁÍÁ¿óÖÐÌúÔªËصļÛ̬½øÐÐ̽¾¿:È¡ÉÙÁ¿¹ÌÌå,¼ÓÈë¹ýÁ¿Ï¡ÏõËá,¼ÓÈÈÈܽâ;È¡ÉÙÐíÈÜÒºµÎ¼ÓKSCNÈÜÒººó³öÏÖºìÉ«¡£Óɴ˵óöÌúÔªËصļÛ̬Ϊ+3µÄ½áÂÛ¡£ÇëÖ¸³ö¸Ã½áÂÛÊÇ·ñºÏÀí²¢ËµÃ÷ÀíÓÉ                                                       ¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø