ÌâÄ¿ÄÚÈÝ

ijͬѧΪÁË̽¾¿ÁòÓëÑõÆøµÄ·´Ó¦Çé¿ö£¬×°ÅäºÃÈçͼËùʾµÃ×°Ö㬴ýÄÚÍâ¿ÕÆøѹǿ²»±äʱ±ê×¢³öË®ÒøÒºÃæµÄ¿Ì¶È£¨ÓúìÆᣩ¡£È¡ÏÂÏðƤÈû£¬ÔÚ²£Á§È¼ÉÕ³×ÖмÓÈëÁò·Û£¬Óþƾ«µÆµãȼѸËÙÒÆÈë׶ÐÎÆ¿Öв¢Èû½ôÏðƤÈû¡£Áò·Û°²¾²µØȼÉÕ£¬Ë®ÒøÖùÍÆÏò×ó¹Ü¡£µ±»ðÑæϨÃðºó£¬¾²Öã¬Ë®ÒøÖùÓÖÂýÂýµØ»Øµ½Ô­Ïȱ궨µÄ¿Ì¶È¡£¼òÒª»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©Ë®ÒøÖùÍÆÏò×ó¹Ü˵Ã÷ʲô£¿
_______________________________________________¡£
£¨2£©Áò·Ûδȼ¾¡Ê±»ðÑæ¾ÍϨÃðÁË£¬ËµÃ÷_________________________________¡£
£¨3£©¸ù¾ÝË®ÒøÖù×îºóÓֻص½Ô­Ïȱ궨µÄ¿Ì¶È£¬¿ÉµÃµ½Ê²Ã´½áÂÛ£¿
__________________________________________________________________¡£
£¨4£©¸ù¾Ý·´Ó¦·½³ÌʽS + O2 ="=" SO2ºÍÉÏÊö½áÂÛÓÖ¿ÉÍƵ¼³öʲô£¿£¨»òÖ¤Ã÷ʲô£¿£©
_______________________________________________________________________¡£
£¨1£©¢Ù¸Ã·´Ó¦ÊÇ·ÅÈÈ·´Ó¦£»¢ÚÆøÌåÊÜÈÈÅòÕÍ   
£¨2£©Æ¿ÄÚÑõÆøÒѺľ¡
£¨3£©¢ÙͬÎÂͬѹÏ£¬·´Ó¦ÏûºÄµÄÑõÆøÓëÉú³ÉµÄSO2Ìå»ýÏàͬ£»¢ÚѹǿÏàͬ£»¢ÛÎïÖʵÄÁ¿Ïàͬ      
£¨4£©Í¬ÎÂͬѹÏ£¬ÏàͬÌå»ýµÄÆøÌ庬ÓÐÏàͬµÄ·Ö×ÓÊý
±¾ÌâÁªÏµÎïÀíѧÖÐÆøÌåѹǿ֪ʶ£¬¿¼²é»ù±¾»¯Ñ§·´Ó¦¡£Ë®ÒøÖùµÄ´æÔÚ£¬½«×¶ÐÎÆ¿ÖÐÆøÌå¸ôΪһÃܱÕÌåϵ¡£µ±Ë®ÒøÖùÍÆÏò×ó¹Üʱ£¬ËµÃ÷׶ÐÎÆ¿ÖÐÆøÌåÅòÕÍ£¬ÓÉÓÚ·´Ó¦£ºS + O2 ="=" SO2£¬¿´³ö·´Ó¦Ç°ºóÆøÌåÌå»ýûÓб仯£¬Òò´ËΨһµÄ¿ÉÄܾÍÊǸ÷´Ó¦·ÅÈÈ¡£
µ±¹ýÒ»¶Îʱ¼äºó£¬×¶ÐÎÆ¿ÖÐÆøÌåͨ¹ý²£Á§±ÚÓëÍâ½ç½øÐÐÁËÈÈ´«µÝ£¬»Ö¸´µ½Ô­À´Î¶ȣ¬ÕâʱÆøÌåµÄÌå»ýÓëÔ­À´µÄÌå»ýÒ»Ñù£¬¼´Ñ¹Ç¿Ã»Óиı䣬Òò´ËË®ÒøÖùÓֻص½Ô­Ïȱ궨µÄ¿Ì¶È¡£
Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿
ÂÁþºÏ½ðÒѳÉΪÂÖ´¬ÖÆÔì¡¢»¯¹¤Éú²úµÈÐÐÒµµÄÖØÒª²ÄÁÏ¡£Ñо¿ÐÔѧϰС×éΪ²â¶¨Ä³º¬Ã¾3£¥Ò»5£¥µÄÂÁþºÏ½ð(²»º¬ÆäËüÔªËØ)ÖÐþµÄÖÊÁ¿·ÖÊý£¬Éè¼ÆÒÔÏÂʵÑé·½°¸½øÐÐ̽¾¿¡£ÌîдÏÂÁпհס£  
£ÛʵÑé·½°¸£ÝÂÁþºÏ½ð·ÛÄ©²â¶¨Ê£Óà¹ÌÌåÖÊÁ¿
£ÛʵÑé²½Öè£Ý
²½Öè1£º³ÆÈ¡5£®4gÂÁþºÏ½ð·ÛÄ©ÑùÆ·£¬Í¶ÈëVmL 2£®0mol¡¤L¡ª1NaOHÈÜÒºÖУ¬³ä·Ö·´Ó¦¡£
²½Öè2£º¹ýÂË¡¢Ï´µÓ¡¢¸ÉÔï¡¢³ÆÁ¿¹ÌÌå¡£
[½»Á÷ÓëÌÖÂÛ]
(1) ʵÑéÖз¢Éú·´Ó¦µÄ»¯Ñ§·½³ÌʽÊÇ                                        £»
(2)²ÎÓë·´Ó¦µÄNaOHÈÜÒºµÄÌå»ýV¡Ý             £»
(3)²½Öè2ÖУ¬Èç¹û¾­Á½´Î¹ýÂËÂËÒºÈÔ»ë×Ç£¬ÔòÔ­Òò¿ÉÄÜÊÇ_________(Ö»ÌîÒ»µã)£»
(4)²½Öè2ÖУ¬ÈôδϴµÓ¹ÌÌ壬²âµÃþµÄÖÊÁ¿·ÖÊý½«     (Ìî¡°Æ«¸ß¡±»ò¡°Æ«µÍ¡±)¡£
[ʵÑéÍØÕ¹] ÇëÄãÁíÉè¼ÆÒ»¸öʵÑé·½°¸(ÓÃÉÏÊö·½°¸µÄÊÔ¼Á)£¬²â¶¨¸ÃÂÁþºÏ½ðÖÐþµÄÖÊÁ¿·ÖÊý¡£
ÒªÇ󣺴ÓÏÂͼÖÐÌôÑ¡ËùÐèµÄÒÇÆ÷£¬»­³ö¸Ã·½°¸µÄʵÑé×°Öüòͼ£¨Ìí¼Ó±ØÒªµÄÈû×Ó¡¢²£Á§µ¼¹Ü¡¢½ºÆ¤¹Ü£¬¹Ì¶¨×°Öò»Óû­£©£¬²¢±êÃ÷ËùÓÃÊÔ¼Á.
Àà±ÈÊÇ»¯Ñ§Ñ§Ï°Öг£Óõķ½·¨Ö®Ò»£¬ÒÑÖªÏõËáÄÜ°ÑÌúÑõ»¯³É Fe ( NO3)3¡¢£¬µ«µ±Ìú¹ýÁ¿Ê±£¬²úÎïÊÇ Fe ( NO3 ) 2¡£Ä³Í¬Ñ§ÊÜ´ËÆô·¢£¬Ìá³öÒ»¸öÏàËƵĹ۵㣺ÂÈÆøÓëÌú·Û·´Ó¦£¬µ± C12×ãÁ¿Ê±Éú³É FeC13 , µ±Ìú·Û¹ýÁ¿Ê±²úÎïÊÇ FeCl2¡£ÎªÑéÖ¤¸Ã¹ÛµãÊÇ·ñÕýÈ·£¬¸Ãͬѧ½«Ò»¸ùϸµÄ´¿ÌúË¿·Ö±ðÔÚ×ãÁ¿ºÍÉÙÁ¿µÄ C12Öеãȼ£¬È¡Æä±íÃæÉú³ÉÎï²¢·Ö±ð±àºÅΪ A¡¢B £¬È»ºóͨ¹ýʵÑéÈ·¶¨Æä³É·Ö¡£Ì½¾¿¹ý³ÌÈçÏ£º
( 1 £©Ìá³ö¼ÙÉ裺 A ÊÇ FeCl3, B ÊÇ FeCl 2¡£
( 2 £©Éè¼ÆʵÑé·½°¸£º·Ö±ðÈ¡ A¡¢B µÄÈÜÒº¾ù½øÐÐÒÔÏÂʵÑ飬µ«ÊµÑéÏÖÏóÏàͬ¡£ÇëÌîдϱíÖеÄÏàÓ¦¿Õ¸ñ¡£

( 3 £©¸ù¾ÝÉÏÊöʵÑé½áÂÛ£¬Ð´³ö C12ÓëÌú·Û¼ÓÈÈʱ·¢Éú·´Ó¦µÄ»¯Ñ§·½³Ìʽ£º
_________________________________________________________________¡£
( 4 £©Îª½øÒ»²½Ì½¾¿ FeC13ÈÜÒºµÄÐÔÖÊ£¬ËûÓÖÀûÓà A ÈÜÒº×öÁËÈçÏÂһЩʵÑ飬ÆäÖÐÃ÷ÏÔ´íÎóµÄÊÇ____________________¡£
A£®½« A ÈÜÒºµÎÈë·ÐË®ÖУ¬²¢¼ÌÐø¼ÓÈȵõ½ºìºÖÉ«ÒºÌ壬¸ÃÒºÌåÄܲúÉú¶¡´ï¶ûÏÖÏó
B£®Ïò A ÈÜÒºÖмÓÈëÉÙÁ¿Ìú·Û£¬Ìú·ÛÈܽ⣬ÈÜÒºÑÕÉ«¼ÓÉî
C£®ÔÚ A ÈÜÒºÖÐµÎ¼Ó Na OH ŨÈÜÒº£¬³öÏÖºìºÖÉ«³Áµí
D£®½« A ÈÜÒº¼ÓÈÈÕô¸É²¢×ÆÉÕ£¬µÃµ½ FeC13¹ÌÌå
( 5 £©Êµ¼ÊÓ¦Óãº
FeCl3ÈÜÒº³£×÷Ó¡Ë¢µç·ͭ°å¸¯Ê´¼Á£¬¸¯Ê´ºóµÄ·ÏÒºÖк¬ÓÐ FeC13¡¢FeCl2¡¢CuCl2£¬Ä³Ñо¿ÐÔѧϰС×éµÄͬѧÃÇÉè¼ÆÁËÁ½ÖÖ´Ó·ÏÒºÖлØÊÕ CuµÄ·½°¸£º
·½°¸1£ºÏò·ÏÒºÖмÓÈ˹ýÁ¿µÄÌú·Û£¬³ä·Ö·´Ó¦ºó£¬¹ýÂË¡£ÔÚËùµÃÂËÔüÖмÓÈË×ãÁ¿µÄÑÎËᣬ³ä·Ö·´ºó£¬ÔÙ¹ýÂ˼´µÃµ½Í­¡£·½°¸1 ÖÐÉæ¼°µÄËÄÖÖÑôÀë×ÓµÄÑõ»¯ÐÔÓÉÇ¿µ½ÈõµÄ˳ÐòΪ£º
_____________________________________¡£
·½°¸2 £ºÔÚ·ÏÒºÖмÓÈËÊÊÁ¿µÄÑÎËáµ÷½ÚÈÜÒºµÄ pH =" 1" £¬ÓÃÍ­ºÍʯī×÷µç¼«½øÐеç½â¡£µ±¹Û²ìµ½Òõ¼«ÉÏÓÐÉÙÁ¿ÆøÅݲúÉúʱ£¬¼´Í£Ö¹µç½â£¬ÕâʱҪ»ØÊÕµÄ Cu ÒÑÈ«²¿Îö³ö¡£·½°¸ 2 ÖÐÍ­×÷_________¼«£¬Ëù·¢ÉúµÄµç¼«·´Ó¦Îª£¨ÈôÓжà¸öµç¼«·´Ó¦£¬Çë°´ÕÕ·´Ó¦·¢ÉúµÄÏȺó˳ÐòÈ«²¿Ð´³ö£©___________________________________________________
·½°¸ 2 Ôڵ缫ÉÏÖ±½Ó»ØÊÕÍ­£¬²Ù×÷Éϱȷ½°¸ 1 ¼ò±ã£¬µ«·½°¸ 2 Ò²Óв»×ãÖ®´¦£¬Ö÷Òª±íÏÖΪ£º_____________________________________________________¡£
»¯Ñ§Ñ§Ï°Ð¡×é¶ÔijþÂÁºÏ½ð½øÐÐÁËÈçÏÂʵÑéÑо¿£¬ÇëÄã²ÎÓë²¢Íê³É¶ÔÓйØÎÊÌâµÄ½â´ð£®
ʵÑéÒ©Æ·£º9.0gþÂÁºÏ½ð£¬100mLamol/LÏ¡ÁòËᣬ260mL5mol/LÇâÑõ»¯ÄÆÈÜÒº£®
ʵÑé²½Öè

¢Ù½«9.0gþÂÁºÏ½ðÓë100mLamol/LÏ¡ÁòËáÔÚͼËùʾװÖÃÖгä·Ö·´Ó¦ÖÁ·´Ó¦Íê±Ï£¬²¢ÊÕ¼¯Éú³ÉµÄÈ«²¿ÆøÌ壮
¢ÚÏòbÄڵĻìºÏÒºÖÐÖðµÎ¼ÓÈë260mL5mol/LÇâÑõ»¯ÄÆÈÜÒº²¢³ä·Ö»ìºÏ£¬µ±ÇâÑõ»¯ÄÆÈÜÒºµÎ¼ÓÖÁ200mLʱÉú³ÉµÄ³ÁµíÁ¿×î´ó£®
ÎÊÌâÌÖÂÛ
£¨1£©ÒÇÆ÷bµÄÃû³ÆÊÇ______£®
£¨2£©¸ù¾ÝʵÑéÄ¿µÄ¿ÉÖª£¬9.0gþÂÁºÏ½ðÓë100amol/LÏ¡ÁòËᷴӦʱ£¬Ó¦¸Ã¹ý£¨×㣩Á¿µÄÎïÖÊÊÇ______£¨ÌþÂÁºÏ½ð¡±»ò¡°Ï¡ÁòËᡱ£©£¬ÒÔ±£Ö¤ÁíÒ»ÖÖÎïÖÊÄܹ»ÍêÈ«·´Ó¦ÎÞÊ£Ó࣮
£¨3£©ÊµÑé²½Öè¢ÚÖУ¬µ±bÄÚ»ìºÏÒºÖÐÒòµÎ¼ÓÇâÑõ»¯ÄÆÈÜÒºÖÁÉú³ÉµÄ³ÁµíÁ¿×î´óʱ£¬´ËʱËùµÃÈÜÒºÖеÄÈÜÖÊÊÇ______£®
£¨4£©ÊµÑé²½Öè¢Ù½áÊøºó£¬¶ÁÈ¡Á¿Í²Ëù³ÊÏÖµÄÊý¾Ýʱ£¬ÐèҪעÒâµÄÈý¸öÖ÷ÒªÎÊÌâÊÇ£ºÒ»ÊÇÒª______£¬¶þÊÇÒªµ÷ÕûÁ¿Í²ÒºÃæÓë¹ã¿ÚÆ¿ÒºÃæÏàƽ£¬ÈýÊÇҪʹÊÓÏßÓëÁ¿Í²ÄڵݼҺÃæÏàƽ£®
£¨5£©Èô±ê×¼×´¿öÏ£¬ÓÉʵÑé²½Öè¢ÙµÃµ½µÄÆøÌåÌå»ýΪ10.08L£¬ÔòºÏ½ðÖÐþµÄÖÊÁ¿·ÖÊýΪ______£®
£¨6£©ÔÚ¡°amol/LÏ¡ÁòËᡱÖÐaµÄֵΪ______£®
£¨7£©ÇëÔÚͼÖл­³öʵÑé²½Öè¢ÚÖÐÉú³É³ÁµíµÄÎïÖʵÄÁ¿£¨n£©Ëæ¼ÓÈëÇâÑõ»¯ÄÆÈÜÒºµÄÌå»ý[v£¨NaOH£©]µÄ±ä»¯ÇúÏߣ®

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø