ÌâÄ¿ÄÚÈÝ

X¡¢YºÍZ¾ùΪ¶ÌÖÜÆÚÔªËØ£¬Ô­×ÓÐòÊýÒÀ´ÎÔö´ó£¬XµÄµ¥ÖÊΪÃܶÈ×îСµÄÆøÌ壬YÔ­×Ó×îÍâ²ãµç×ÓÊýÊÇÆäÖÜÆÚÊýµÄÈý±¶£¬ZÓëXÔ­×Ó×î´¦²ãµç×ÓÊýÏàͬ¡£»Ø´ðÏÂÁÐÎÊÌ⣺

£¨1£©X¡¢YºÍZµÄÔªËØ·ûºÅ·Ö±ðΪ ¡¢ ¡¢ ¡£

£¨2£©ÓÉÉÏÊöÔªËØ×é³ÉµÄ»¯ºÏÎïÖУ¬¼Èº¬Óй²¼Û¼üÓÖº¬ÓÐÀë×Ó¼üµÄÓÐ ¡¢ ¡£

£¨3£©XºÍY×é³ÉµÄ»¯ºÏÎïÖУ¬¼Èº¬Óм«ÐÔ¹²¼Û¼üÓÖº¬ÓзǼ«ÐÔ¹²¼Û¼üµÄÊÇ ¡£´Ë»¯ºÏÎïÔÚËáÐÔÌõ¼þÏÂÓë¸ßÃÌËá¼Ø·´Ó¦µÄÀë×Ó·½³ÌʽΪ £»´Ë»¯ºÏÎﻹ¿É½«¼îÐÔ¹¤Òµ·ÏË®ÖеÄCN-Ñõ»¯ÎªÌ¼ËáÑκͰ±£¬ÏàÓ¦µÄÀë×Ó·½³ÌʽΪ ¡£

Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

ͨ¹ý³Áµí£­Ñõ»¯·¨´¦Àíº¬¸õ·ÏË®£¬¼õÉÙ·ÏÒºÅŷŶԻ·¾³µÄÎÛȾ£¬Í¬Ê±»ØÊÕK2Cr2O7¡£

ʵÑéÊÒ¶Ôº¬¸õ·ÏÒº(º¬ÓÐCr3+¡¢Fe3+¡¢K+¡¢SO42£­¡¢NO3£­ºÍÉÙÁ¿Cr2O72£­)»ØÊÕÓëÔÙÀûÓù¤ÒÕÈçÏ£º

ÒÑÖª£º¢ÙCr(OH)3 + OH£­ = CrO2£­ + 2H2O£»

¢Ú2CrO2£­ + 3H2O2 + 2OH£­ = 2CrO42£­ + 4H2O£»

¢ÛH2O2ÔÚËáÐÔÌõ¼þϾßÓл¹Ô­ÐÔ£¬Äܽ«+6¼ÛCr»¹Ô­Îª+3¼ÛCr¡£

£¨1£©ÈçͼÊÇÓÃKOH¹ÌÌåÅäÖÆ250mL 6 mol¡¤L£­1 KOHÈÜÒºµÄ¹ý³ÌʾÒâͼ¡£

¢ÙÇëÄã¹Û²ìͼʾÅжϣ¬ÆäÖв»ÕýÈ·µÄ²Ù×÷ÓÐ(ÌîÐòºÅ)_____________________£»

¢ÚÆäÖÐÅäÖÆ250 mLÈÜÒºÌå»ýµÄÈÝÆ÷ÊÇ(ÌîÃû³Æ)_________________£»

¢ÛÈç¹ûÓÃͼʾµÄ²Ù×÷ÅäÖÆÈÜÒº£¬ËùÅäÖƵÄÈÜҺŨ¶È½«________(Ìî¡°Æ«´ó¡±»ò¡°Æ«Ð¡¡±)¡£

(2)ÂËÒº¢ñËữǰ£¬½øÐмÓÈȵÄÄ¿µÄÊÇ_________________¡£±ùÔ¡¡¢¹ýÂ˺ó£¬Ó¦ÓÃÉÙÁ¿ÀäˮϴµÓK2Cr2O7£¬ÆäÄ¿µÄÊÇ_______¡£

£¨3£©Ï±íÊÇÏà¹ØÎïÖʵÄÈܽâ¶ÈÊý¾Ý£º

ÎïÖÊ

0¡æ

20¡æ

40¡æ

60¡æ

80¡æ

100¡æ

KCl

28.0

34.2

40.1

45.8

51.3

56.3

K2SO4

7.4

11.1

14.8

18.2

21.4

24.1

K2Cr2O7

4.7

12.3

26.3

45.6

73.0

102.0

KNO3

13.9

31.6

61.3

106

167

246.0

¸ù¾ÝÈܽâ¶ÈÊý¾Ý£¬²Ù×÷¢ñ¾ßÌå²Ù×÷²½ÖèΪ¢Ù________________¢Ú________________¡£

³ÆÈ¡²úÆ·ÖظõËá¼ØÊÔÑù2.000gÅä³É250mLÈÜÒº£¬È¡³ö25.00mLÓÚ׶ÐÎÆ¿ÖУ¬¼ÓÈë10mL 2mol¡¤L£­1H2SO4ºÍ×ãÁ¿µâ»¯ÄÆ(¸õµÄ»¹Ô­²úÎïΪCr3+£©£¬·ÅÓÚ°µ´¦5min£¬È»ºó¼ÓÈë100mLË®£¬¼ÓÈë3mLµí·Ûָʾ¼Á£¬ÓÃ0.1200 mol¡¤L£­1Na2S2O3±ê×¼ÈÜÒºµÎ¶¨(I2+2S2O32£­=2I£­+S4O62£­)¡£

¢Ùд³öÖظõËá¼ØÑõ»¯µâ»¯ÄƵÄÀë×Ó·½³Ìʽ___________________¡£

¢ÚµÎ¶¨ÖÕµãµÄÏÖÏóΪ___________________¡£

¢ÛÈôʵÑéÖй²ÓÃÈ¥Na2S2O3±ê×¼ÈÜÒº30.00mL£¬ËùµÃ²úÆ·ÖеÄÖظõËá¼ØµÄ´¿¶È Ϊ_________(ÉèÕû¸ö¹ý³ÌÖÐÆäËüÔÓÖʲ»²ÎÓë·´Ó¦)¡£

¢ÜÈôµÎ¶¨¹ÜÔÚʹÓÃǰδÓÃNa2S2O3±ê×¼ÈÜÒºÈóÏ´£¬²âµÃµÄÖظõËá¼ØµÄ´¿¶È½«_____________(Ìî¡°Æ«¸ß¡±¡¢¡°Æ«µÍ¡±»ò¡°²»±ä¡±)¡£

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø