ÌâÄ¿ÄÚÈÝ

ÔÚÒ»¶¨Î¶ÈÏÂÓмס¢ÒÒÁ½ÈÝ»ýÏàµÈµÄÈÝÆ÷¡£

(1)Ïò¼×ÈÝÆ÷ÖÐͨÈë3 mol N2ºÍ4 mol H2£¬·´Ó¦´ïµ½Æ½ºâʱ£¬Éú³ÉNH3 a mol¡£´Ëʱ£¬NH3µÄÎïÖʵÄÁ¿·ÖÊýÊÇ__________¡£ÈôÔڴﵽƽºâ״̬µÄ¼×ÈÝÆ÷ÖÐͨÈëÉÙÁ¿µÄN2£¬Ôò´ïµ½ÐÂƽºâʱ£¬ÌåϵÖÐN2µÄÌå»ý·ÖÊý½«__________(Ñ¡Ìî¡°Ôö´ó¡±¡°¼õС¡±»ò¡°²»±ä¡±)¡£

(2)ÏòÒÒÖÐͨÈë2 mol NH3£¬Óûʹ·´Ó¦´ïµ½Æ½ºâʱ£¬¸÷ÎïÖʵÄŨ¶ÈÓë(1)ÖеÚÒ»´ÎƽºâÏàͬ£¬ÔòÆðʼʱ»¹ÐèͨÈë__________mol N2ºÍ__________mol H2¡£

(1)¡Á100%  Ôö´ó

(2)2  1

½âÎö£º(1)N2  +  3H22NH3  ¦¤n¼õÉÙ

³õʼ£º      3         4                          0

¦¤n£º                                     a

ƽºâ£º                                 a           a

ËùÒÔNH3µÄÎïÖʵÄÁ¿·ÖÊýΪ¡Á100%¡£

(2)¿¼²é¡°µÈЧƽºâ¡±ÎÊÌâ¡£Òª´ïµ½ÏàͬµÄƽºâ״̬£¬ÐèÂú×ã¡°ÎïÁÏÏ൱¡±£¬ÉèÆðʼͨÈëx mol N2£¬y mol H2£¬Ôòx+¡Á2=3£¬y+¡Á2=4£¬ËùÒÔx=2£¬y=1¡£


Á·Ï°²áϵÁдð°¸
Ïà¹ØÌâÄ¿

Î¥·¨ºÍ²»Á¼ÐÅÏ¢¾Ù±¨µç»°£º027-86699610 ¾Ù±¨ÓÊÏ䣺58377363@163.com

¾«Ó¢¼Ò½ÌÍø